As I have been obtaining all the equipment and tooling to build a gravity machine introduced in 1949 by William Skinner I find it amazing that this tidbit of information has alluded so many in the understanding of why this machine will work and some of the details necessary to understand it. If you would like to communicate with me along these lines please do.
THANK YOU thank you for taking the time to put this awesome informative video out...I'm studying for the PipeFittes Apprentice test in Frisco and I believe this will help...thanks again
Early in the vid, you use the terms "fulcrum, resistance arm and effort arm", then later you use "fulcrum, input side and output side" . When teaching, consistency is a greatly desired quality, and complicating things by using two terms for each of these parts is not the best way for students to learn.
Noname 123 What you are talking about is a dynamic lever, like a whip, in which the lenth of the output arm changes over time. Essentually it a first class lever.
I agree that the flexible whip could be defined as dynamic, but I mean something quite different. Can I ask this question:- Q: We have equal masses equidistant on a beam, either side of a common pivot point. That arrangement is said to be in a state of perfect balance. Because the centre of mass = centre of gravity in all revolute positions about the pivot point, the system is said to be gravity equalised, meaning PE is constant at all times. Agree? Now, do you, mathematical, foresee, a situation whereby we can remove a mass from that balanced beam, yet still maintain perfect countenance of the remaining supported mass without any intervention to alter the radial position of the remaining mass on the beam ? No masses are located at the pivot point.
Noname 123 In a word,no. However, we cannot just assume the comass is at the same point as the cograv.But regardless, the system you are describing is still a first class lever. If the pivot point is static the revoving a mass from the beam would take it out of equilibrium producing a torque resultin rotation. Basically the same as a pully wheel, which is , well, a first class lever.
Ok that answer is actually good for me as it means I've designed something noteworthy. If you private message me on My page? I'll show you how its done :)
As I have been obtaining all the equipment and tooling to build a gravity machine introduced in 1949 by William Skinner I find it amazing that this tidbit of information has alluded so many in the understanding of why this machine will work and some of the details necessary to understand it. If you would like to communicate with me along these lines please do.
THANK YOU thank you for taking the time to put this awesome informative video out...I'm studying for the PipeFittes Apprentice test in Frisco and I believe this will help...thanks again
That is what I need
I'm studying for a major exam after 15 years of not having this subject. very helpful.
thanks for your dedicating times and efforts
Thank yiu so much sir I'm highly grateful with the information you just shared please continue! :D
excellent sir! it really helped me a lot thanx.....
Fantastic
thank you so much.
Can you do a video on gears?
Thanks
What if there is two different forces on a class one lever
Early in the vid, you use the terms "fulcrum, resistance arm and effort arm", then later you use "fulcrum, input side and output side" . When teaching, consistency is a greatly desired quality, and complicating things by using two terms for each of these parts is not the best way for students to learn.
Sir, are you aware that there is, in fact, a 4th class of lever (that being the dynamic lever).
Noname 123 What you are talking about is a dynamic lever, like a whip, in which the lenth of the output arm changes over time. Essentually it a first class lever.
I agree that the flexible whip could be defined as dynamic, but I mean something quite different.
Can I ask this question:-
Q: We have equal masses equidistant on a beam, either side of a common pivot point. That arrangement is said to be in a state of perfect balance. Because the centre of mass = centre of gravity in all revolute positions about the pivot point, the system is said to be gravity equalised, meaning PE is constant at all times. Agree?
Now, do you, mathematical, foresee, a situation whereby we can remove a mass from that balanced beam, yet still maintain perfect countenance of the remaining supported mass without any intervention to alter the radial position of the remaining mass on the beam ?
No masses are located at the pivot point.
Noname 123 In a word,no. However, we cannot just assume the comass is at the same point as the cograv.But regardless, the system you are describing is still a first class lever. If the pivot point is static the revoving a mass from the beam would take it out of equilibrium producing a torque resultin rotation. Basically the same as a pully wheel, which is , well, a first class lever.
Ok that answer is actually good for me as it means I've designed something noteworthy.
If you private message me on My page? I'll show you how its done :)