NETWORK SECURITY - DIFFIE HELLMAN KEY EXCHANGE ALGORITHM

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  • Опубликовано: 8 ноя 2024

Комментарии • 229

  • @sundeepsaradhi
    @sundeepsaradhi  6 лет назад +139

    HI VIEWERS THERE IS A SMALL MISTAKE WHILE WRITING THE FORMULA AND IN THE EXAMPLE PROBLEM.
    At THE TIME 9:18
    CORRECT ONE : PUBLIC KEY OF USER A
    WRONG ONE : WRITTEN AS PUBLIC KEY OF USER B
    AT THE TIME 25:01
    CORRECT ONE : POWER IS XB
    WRONG ONE : WRITTEN POWER AS XA
    PLEASE MAKE A CORRECTION AND I AM SORRY FOR THE MISTAKE.

    • @saurabhkumarbarnwal6957
      @saurabhkumarbarnwal6957 6 лет назад +2

      it's ok sir
      thanks for teaching

    • @saurabhkumarbarnwal6957
      @saurabhkumarbarnwal6957 6 лет назад

      sir, can u give me notes about topic

    • @rishi1987ful
      @rishi1987ful 6 лет назад +4

      Sundeep Saradhi Kanthety
      Sir how will both the user come to know the value of q?

    • @DrunkenHamster7
      @DrunkenHamster7 6 лет назад

      @@rishi1987ful lol mindfk

    • @DrunkenHamster7
      @DrunkenHamster7 6 лет назад

      Alice and Bob agree to use a modulus p = 23 and base g = 5 (which is a primitive root modulo 23).(wiki)

  • @bindupotluri45
    @bindupotluri45 3 года назад +27

    Words can't explain how glad I am to have found your channel the day before my exam. Thank you soo much!!

  • @becool1270
    @becool1270 Год назад +2

    What a nice explanation, a person who even does every small calculations (multiplications and divisions) to make the student understand. Thank you sir, you efforts were well received and appreciated.

  • @TheShakthirvd
    @TheShakthirvd 6 лет назад +6

    You’re awesome bloke! Some faculties are struggling to explain this but you did it in ease! Thank you!

    • @sundeepsaradhi
      @sundeepsaradhi  5 лет назад +2

      hi aravind
      thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.

    • @eieikhaing5930
      @eieikhaing5930 5 лет назад

      Thank you sir i like your teaching method. Please explain for me about A5/1 of stream cipher

  • @jadavshanker9304
    @jadavshanker9304 4 года назад +1

    That is the indian teacher talent. Nowhere in the world like India guru. Only demon lacking is lack of technology. Otherwise India could be in number one position in the world with moral education. You are superb sir. You have lot patiency and did wonderful job to make sense me by crystal clear explanation. You are the wonderfull hero and true guru.

  • @K.Sureshcse
    @K.Sureshcse Год назад

    SIR YOUR WAY OF EXPLAINING THE CONCEPT IS GOOD

  • @nishagyanchanddubey3011
    @nishagyanchanddubey3011 Год назад

    Slow and Nice...such complex problems need longer explanations...I am not disappointed clicking on this video Thanks a lot, Sir... 😊👍

  • @vishnu5807
    @vishnu5807 5 лет назад +3

    Good one sir... Your explanation is far better than my lecturer at college...👌

  • @jalendarch89
    @jalendarch89 5 лет назад +3

    What a wonderful explanation... Simply loved it Sir
    Thanks

  • @balaiiit6388
    @balaiiit6388 6 лет назад +6

    Thank you Sir. Easy Steps to find K.
    K =5^8 mod 11
    = (625 x 625) mod 11
    = (9 x 9) mod 11 ( Divide 625 by 11, rem=9)
    = 81 mod 11
    K = 4

  • @maheshb3756
    @maheshb3756 3 года назад

    Sir you have helped me a lot sir during my exams time. Your explonation is very goood and clear. Keep maintian that sir. You are one of the best teacher in my study career. I was scared about this subject and i found you on youtube. Now i learned lot of subject. Thank you very much sir.

  • @sherinsuganthi6095
    @sherinsuganthi6095 Год назад

    Really excellent presentation sir and easy to understand 👍

  • @ajayvijayan4303
    @ajayvijayan4303 2 года назад +1

    thankyou sir, you are a lifesaver

  • @TheBurningFreeze
    @TheBurningFreeze 6 лет назад +2

    Your videos are great man! They do not go unappreciated!!!

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад +2

      hi thanks for watching my sessions and giving support to our channel.

  • @mdmehedihasan6958
    @mdmehedihasan6958 4 года назад

    Great.....your teaching style fabulous......very helpful for us.

  • @koyavasudhalakshmi2073
    @koyavasudhalakshmi2073 3 года назад +1

    Awesome explanation sir,very clear 👏👏👏

  • @vaikuntaraopotnuru7335
    @vaikuntaraopotnuru7335 6 лет назад

    Very good explanation sir..I never seen these detailed and clear explanation by anyone so far

  • @bhavyamodhiya9099
    @bhavyamodhiya9099 11 месяцев назад

    Salute to your teaching and way of explaining!!

  • @aashaypatil7745
    @aashaypatil7745 4 года назад

    nice video sir i have learned a lot. and I will score a good grade because of you sir. thanks sir

  • @akeelashivakumar3587
    @akeelashivakumar3587 2 года назад

    Your explanations are very clear
    Thank you

  • @karun537
    @karun537 6 лет назад +4

    Sir...i am really delighted by your class... your videos are very informative and useful

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад

      hi karun
      thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.

    • @sravan9958
      @sravan9958 4 года назад

      @@sundeepsaradhi come to our college as teacher

  • @jollygoodfellow2023
    @jollygoodfellow2023 5 лет назад +1

    Excellent presentation and your knowledge is superior. Thanks a Million. Harry

  • @sairam-co2cj
    @sairam-co2cj 5 лет назад

    Fantastic explanation Sandeep...THanks alot..easy method of explaining.

  • @divyasreekanth8218
    @divyasreekanth8218 6 лет назад

    Thank you very much sir, i like the way of your teaching , u explain very nicely ..

  • @trincolab8069
    @trincolab8069 4 года назад

    Sir, Really helpful for me your valuable lecture
    Thank you very much sir

  • @ammykay4949
    @ammykay4949 4 года назад

    This was very very helpful. Your videos really helped me with my assignment.

  • @t.udhayaumabharathii6055
    @t.udhayaumabharathii6055 Год назад

    Nice explanation... 👏👏👏Thank you sir👍

  • @osizzle963
    @osizzle963 5 лет назад +9

    Hi, a couple of minor errors but overall an excellent video. Thank You!

  • @viswabhaskar4404
    @viswabhaskar4404 4 года назад

    Really superb explanation sir ......

  • @ashishnair8919
    @ashishnair8919 5 лет назад +1

    last min i got this before exam!!! thank u soo much!

  • @prajwalj2776
    @prajwalj2776 4 года назад +1

    superb explanation

  • @hempathak7001
    @hempathak7001 7 месяцев назад

    thank you so much sir ,very nice explanation

  • @nisargpatwari3021
    @nisargpatwari3021 5 лет назад +1

    thank you sir for these videos because of them i was able to clear my subject easliy

  • @uff_rani
    @uff_rani 2 года назад

    thanks you so much sir, You teach fabulous

  • @masoom5320
    @masoom5320 5 лет назад

    thnks you sundee saradhi kanthety guru g

  • @subashiniselvarajan8468
    @subashiniselvarajan8468 7 месяцев назад

    wonderfully explained. one small doubt. how do the sender and receiver choose the same q and alpha values or how the sender and reciver exchange the q and alpha values

  • @archanareddy4242
    @archanareddy4242 5 лет назад +3

    Sir please upload number theory, format and Euler therom..Ur teaching is good and I shared Ur video with my friends

  • @vedprakash9099
    @vedprakash9099 5 лет назад

    Awesome explanation sir

  • @sunilyadav-wc7zb
    @sunilyadav-wc7zb 4 года назад +1

    Sir i have watched your many video. You are superb in explaining thing. I have query here, prime numer q is selected by sender and alpha is selected as a premitive root of q. How does receiver get this q and alpha. Whole calculation is based on these two value only. Kindly explain sir. Thanks in advance

  • @enikarlaprasannakumar1028
    @enikarlaprasannakumar1028 2 года назад

    Super sir tqu for conveying with patience

  • @OmitA25
    @OmitA25 6 лет назад

    very nice explanation sir

  • @prathamug5930
    @prathamug5930 Год назад

    Sir what an explanation 🙇🏻🙏🏻

  • @sumitpatil7835
    @sumitpatil7835 6 лет назад +2

    Thank you for this valuable lecture sir...

  • @akramrayri7538
    @akramrayri7538 4 года назад

    thank you so much Sir..you are the best

  • @thegreatkizo
    @thegreatkizo 4 года назад +1

    Thank you for this amazing video, you basically saved me.

  • @arkadey7589
    @arkadey7589 6 лет назад +2

    Thank u sir....!!! loved your graphics lectures also

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад

      hi Arka
      thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.

  • @chinthakadissanayake1790
    @chinthakadissanayake1790 4 года назад

    great channel thanks sir you are hardly teaching

  • @vivekkumargoel2676
    @vivekkumargoel2676 9 месяцев назад

    @sundeepsaradhi sir , I have one doubt like in the lecture it is mention we have to use "q" on both side to find the sceret key , how q is shared between sender and receiver in real time

  • @suryashanmugam4279
    @suryashanmugam4279 5 лет назад

    Nice teaching sir tq for ur teaching sir and tq so much sir

  • @arjunvarma7
    @arjunvarma7 5 лет назад +2

    Well said, i appreciate your efforts 👍

  • @diycraftsandlifehacks3958
    @diycraftsandlifehacks3958 6 лет назад +1

    Thank you sir easy to understand we hope you talk about elgamal cryptosystem and signature for rsa and elgamal best regards❤

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад +2

      Hi night walker thank you and definitely soon I will try to upload them soon.
      Thanks for watching my sessions and supporting our channel.

  • @karthikapragadeeswari1510
    @karthikapragadeeswari1510 4 года назад

    super sir your teaching, but if both sender and receiver uses different q then also they will get same key value(k)??

  • @TheTapan321
    @TheTapan321 3 года назад +1

    Lot of thanks sir

  • @manjuhr1223
    @manjuhr1223 4 года назад

    Understood😊👍 thank you sir

  • @ayushvarshney1925
    @ayushvarshney1925 5 лет назад +1

    i passed my exam only because of u

    • @sundeepsaradhi
      @sundeepsaradhi  5 лет назад

      Hi
      Thank you very much for your support towards our channel share our channel with your friends and keep following our channel

  • @dhachanamurthydhachanamurt8447
    @dhachanamurthydhachanamurt8447 4 года назад

    Super sir.. Keep rocking 🎸🎶🎶

  • @sainath-el3mi
    @sainath-el3mi 5 лет назад

    Good sir after the video u refer the video is ther is any mistake and correct it.nice

  • @askitca
    @askitca 4 года назад

    Very well explained, thank you

  • @remyaunnikrishnan2037
    @remyaunnikrishnan2037 6 лет назад +3

    Thank u sir for this video.. can you explain elliptic curve cryptography?

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад

      hi remya
      thanks for your interest towards our channel and i will try to upload it.

  • @s.pratheevikumar766
    @s.pratheevikumar766 2 года назад

    Thanks a Lot Sir.!! ❣️

  • @jyotirmaypandit4745
    @jyotirmaypandit4745 6 лет назад +1

    Nice lecture good concept very helpful...Keep it up sir....

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад

      hi jyotirmay
      thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.

  • @adithirao1830
    @adithirao1830 5 лет назад

    thanks for the detailed explanation sir

  • @aadilrasheed353
    @aadilrasheed353 5 лет назад

    Very very very helpful
    Thanku very much sir

  • @vishnuvardhan6246
    @vishnuvardhan6246 5 лет назад

    Very helpful sirr tq so much😍😍😍

  • @niharikareddy_ars
    @niharikareddy_ars 5 лет назад

    Good explanation sir that made me feel easy.

  • @AMRKAMAL1111
    @AMRKAMAL1111 4 года назад +1

    Thanks very much for your video , but I have a question we are going to calculate alpha on both sides (the receiver and the sender) this may lead with two different alpha values on both sides will the final result will be the same ?

  • @sabbineediveni4579
    @sabbineediveni4579 6 лет назад

    thank you very much Sir... Most useful

  • @sechaf
    @sechaf 6 лет назад

    thank you sir...... please make more tutorial on Network Security....

    • @sechaf
      @sechaf 6 лет назад +1

      also..... your methodology is superb as compared to other,s

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад

      hi hafeez
      thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.

  • @reemaroychaudhary3882
    @reemaroychaudhary3882 2 года назад

    Kindly make a video on ECC algorithm

  • @SDIVYAMIS
    @SDIVYAMIS 4 года назад

    You are awesome sir !

  • @priyansh02chawda
    @priyansh02chawda 6 лет назад +1

    So basically summary is that
    => 2^8*4 mod 11 (where 8 is private key of A. and 4 is private key of B)
    => 2^32 mod 11
    => 4

  • @pavanrudhramahanti
    @pavanrudhramahanti 6 лет назад

    thank you so much sir !! best lecture ever

  • @danaratnakishorelakshmipur7566
    @danaratnakishorelakshmipur7566 6 лет назад +1

    Thanks sir Please up date More videos Network Security

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад

      hi kishore
      definitely i will upload almost all concepts of security.

  • @sandipdeb6550
    @sandipdeb6550 5 лет назад +1

    Sir I have watched your video and it is very helpful for me my one query is, by using this calculation any one can get the key and any one can decrypt massage so how it is safe to exchange key

    • @TimeLoop01
      @TimeLoop01 5 лет назад

      others don't have the private keys.. hence cannot generate the same key.

  • @shohag402
    @shohag402 6 лет назад +1

    Thanks your video in Network security is awesome and very easy to understand. In this video i think Ya is the public key of A not B.(May be a writing mistake of you). please clarify.

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад

      hi saleh
      you are correct and thanks for observation and correction.
      thanks for your interest towards our channel and share my sessions with
      your friends and subscribe to our channel.Keep following our channel.

    • @shohag402
      @shohag402 6 лет назад +1

      Thanks for quick reply and clarification.

  • @vikki153
    @vikki153 6 лет назад

    In the example problem, how did you find XA=8(private key), or is it like, you have assumed it to be 8?.. please clarify 24:10

  • @shikhargupta9620
    @shikhargupta9620 4 года назад +2

    It uses Asymmetric encryption method ,right?
    So,why you said it uses symmetric encryption method at the end of the video??

    • @sundeepsaradhi
      @sundeepsaradhi  4 года назад +1

      Hi
      This method is used to find symmetric key using asymmetric method.
      Hope your doubt has been clarified.

    • @shikhargupta9620
      @shikhargupta9620 4 года назад

      @@sundeepsaradhi Yes
      Thankyou so much for the video. :)

  • @amskhadhiri4636
    @amskhadhiri4636 6 лет назад

    super explaination sir

  • @vedantsingh7011
    @vedantsingh7011 4 года назад

    Sir, I want to know how many values will be shared in network? q,alpha will be shared with each-other on network?Is there any feasible technique to calculate primitive number for huge prime number(q>100)

  • @davidben8118
    @davidben8118 5 лет назад

    Thank u sir.... Very useful

  • @belalrashed8263
    @belalrashed8263 4 года назад

    Thank you 💐💐💐

  • @Binunb2011
    @Binunb2011 5 лет назад

    sir can you explain about the difference between the diffie hellimen and man in middle attack

  • @ashwinir5110
    @ashwinir5110 3 года назад

    Sir, values of q & alpha are shared between sender n receiver

  • @alirezanabavian771
    @alirezanabavian771 2 года назад

    Wonderful..thanx a lot

  • @sykbot
    @sykbot 5 лет назад

    Sir Which calculation is done on sender side and which is done on receiver side?
    Like how much part of calculation is done on sender side and receiver side in your explanation.
    Please respond sir

  • @nelsondarwinpaktech3954
    @nelsondarwinpaktech3954 5 лет назад

    great explanation,,,,,,,,

  • @amc1516
    @amc1516 5 лет назад

    Great Video !!!!!!!!!!!!!!!!!!!

  • @amitb7611
    @amitb7611 4 года назад

    now the k vale will be used for sending the Symmetric key across VPN? m i right?

  • @sammy5413
    @sammy5413 5 лет назад

    Sandeep you the man. Keep up the excellent work and keep on helping losers like me pass.
    Cipher - davqkxUx
    Key - sandyrox

  • @adithyavarma758
    @adithyavarma758 2 года назад

    Thank you sir..

  • @shivakumarshetty6316
    @shivakumarshetty6316 3 года назад +1

    thankyou sir

  • @arathithamban2542
    @arathithamban2542 5 лет назад

    Well explained

  • @shuvoislam8404
    @shuvoislam8404 5 лет назад

    Sir I think you should use calculator because It will decrease the length of your video ...Thank you

  • @JDRTechnologies
    @JDRTechnologies 5 лет назад

    Thank you very much sir

  • @nagdevineni6823
    @nagdevineni6823 5 лет назад

    Excellent

  • @mohanlalitha7564
    @mohanlalitha7564 4 года назад

    How the same q value ie prime number is selected between sender and receiver

  • @KrupalGhorpade
    @KrupalGhorpade 6 лет назад +4

    Thanks for the detailed explanation. Much needed one. Could you please explain PBES Encryption too? I need this much.

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад +2

      hi Krupal
      thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.

  • @aminazubair6482
    @aminazubair6482 6 лет назад

    Thanks a lot sir but my question is that in my question paper p and q value are mentioned how to handle it

  • @HIMANSHURISHUSINGH
    @HIMANSHURISHUSINGH 6 лет назад +6

    Sir, at 9:18 its public key of user A and at 25:01 its xB power not xA :-)

    • @sundeepsaradhi
      @sundeepsaradhi  6 лет назад +3

      hi Himanshu
      You are absolutely correct and thanks for your correction.

  • @mukundhandhayalandhayalan8563
    @mukundhandhayalandhayalan8563 2 года назад

    Sir I have one doubt
    Can we assume wheather any value for Xa and Xb