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thank you, you saved my semester on chand raat
Very underrated
Excellent teaching !god save u
Excellent teaching sir
Sir why u use the formula 2EI/L for MBC, should it be 3EI/L since it is hinge end? Im confused
In slope deflection equation method this is the standard formula. Here we always have 2EI/L. Check this playslist. ruclips.net/p/PLjJwBYxz7Cym_XRwWlux5KDvALqYpPXi9
sir, it must be 3EI/L for far end pin or roller. So, you are right. But formula changes like that ; 3EI/L (Qi - 3displacement)
Nice explanation... 🥰
Sr cant a clockwise moment mcb occur at rc...in that case mcb cannot be zero right
Not possible. in simply supported end, there will be no moment
bwhy fixed end moment of Bc is negative ??isnot right to be +20 ???
FEM of BC is negative because it is acting in the anticlockwise direction
Sir why are you deleting the videossssssss
Because in the old videos, there are minor errors. So I am updating them with good quality
thank you, you saved my semester on chand raat
Very underrated
Excellent teaching !
god save u
Excellent teaching sir
Sir why u use the formula 2EI/L for MBC, should it be 3EI/L since it is hinge end? Im confused
In slope deflection equation method this is the standard formula. Here we always have 2EI/L. Check this playslist. ruclips.net/p/PLjJwBYxz7Cym_XRwWlux5KDvALqYpPXi9
sir, it must be 3EI/L for far end pin or roller. So, you are right. But formula changes like that ; 3EI/L (Qi - 3displacement)
Nice explanation... 🥰
Sr cant a clockwise moment mcb occur at rc...in that case mcb cannot be zero right
Not possible. in simply supported end, there will be no moment
bwhy fixed end moment of Bc is negative ??
isnot right to be +20 ???
FEM of BC is negative because it is acting in the anticlockwise direction
Sir why are you deleting the videossssssss
Because in the old videos, there are minor errors. So I am updating them with good quality