I understand specific gravity. Thought this was going to be another video explaining the basics. Being specific to gold, this took an awesome, unexpected twist. Glad I watched. Subbed. Thanks for sharing... Now, I'm going to be stuck trying to understand how this formula actually works and why these paticular constants were established
Thank you for the video. I have come up with another formula for you that determines the weight of gold in a specimen. The formula is:- Gold = Ws[Dg(Ds-Dq)]/[Ds(Dg-Dq)] - formula (1) or Gold = Vs[Dg(Ds-Dq)/[Dg-Dq] - formula (2) Dg=Density of gold Dq=Density of quartz Ds=Density of specimen Ws=Weight of specimen Vs=Volume of specimen To use your example: Dg=19.3 g/cm^3 Dq=2.63 g/cm^3 Ds=2.975 g/cm^3 Ws=1574.5g Using the formula (1): Gold=1574.5[19.3(2.975-2.63)]/[2.975(19.3-2.63)] Gold=1574.5[19.3×0.345]/[2.975×16.67] Gold=1574.5[6.66/49.59] Gold=1574.5×0.1343 Gold=211g (rounded off) Like any formula this is only as accurate as the numbers plugged in but gives a more accurate gold weight than equations using constants. If the volume of the specimen is being used instead then formula (2) can be applied. For more accuracy I suggest determining the density of a quartz sample from the region your specimen was found using the methods already presented. If gold in the area is not pure this can be accounted for by altering the density of the gold accordingly. This formula in fact can be used to calculate the content of anything within something else if their densities are known. Hope this helps.
@@jackojeep8276 I calculated the gold content to be about 11.3 (g?). That's about a 1/3 gold content by weight. As mentioned this number will change if the densities of the gold and quartz are different but gives a fair estimation.
specific gravity is used by distilleries to calculate alcohol percentage based on volume. Would love to have this calculation. Please do print formula in Gold Prospectors Mag
Interesting the difference between the dry and wet weight 529.3grams. Perhaps that is the volume 529.3 mls or ccms... x+y= 529.3, x19+ y2.63 =1574.5 solve for x the volume of gold in ccms. Is called a simultaneous equation. Also if ironstone present in quartz use a higher sg. for quartz.
Informative video...Thanks. Actually it confirmed some of what I knew. Being a Physicist (Materials Science) I am aware of what a constant is. What is the name of that constant that you did not go into so that I may research it please. (I am assuming that you are estimating an assay of 18K Gold alloyed with Silver and Copper and it corrects for that.., What percentage of Silver and copper are you estimating?) How is Prescott Valley these days? Still growing like a weed as it was in the early 2000s?
I think it should be "augmented" in other words they should burn off some of the quartz to really reveal the crystaline gold inside... i don't think they should crush such a rare beauty as that...
yeah but the formula actually only compensates for non quarts minerals not strictly gold. It is Very helpful in the long run to give approx value to a piece. Thank you For this demo!
Thank you! I have saved and copied n repeated this so many times now I should have it memorized by now but ....drat!🤦♀️I’m getting too old I guess🤣I’m so grateful for your video🙏❤️
Great video, if you dont mind id like to do it in spanish, all i need is a gold specimen and thats gona be the hard part, im gona have to go vist a friend in Real del Castillo and see what he has. Gl and be safe.
I am confused. Not by the math but by the answer I got . Which simply put me right back where I started. See, I know what I have is a piece of quartz and gold. I know this. Thing is, I have never had anything like this before, and I don't understand why the gold part of the rock completely encompasses the quartz part, I guess you'd say. It looks like this was dipped in gold. The entire surface is covered except for a very small patch. I don't want to break the rock to see the inside. Okay the problem. My math brought me almost exactly to the original dry weight, except for 1 3333/20000 I checked it twice. I don't know what I am doing wrong. I feel stupid.
It's so weird because you definitely look like a relative of mine!! My last name is Bull, js! Anyway I'd like to say thank you and God bless you for all you do!! I can tell you are a Great man but one should never cross you!! (They will lose) I heard about you from "Ask Jeff Williams" I really like his show! This is the 1st video I have seen of yours and it's awesome! P.S. you should do another video with a rock of the same size with no G in it!! That would be awesome!! Anyway keep up the Great work and Thank You so much for all you do!!
Well I'll have to admit - this guy seems legit - unlike that Gold Hog guy who obviously plants gold flakes in his equipment - aka salting the "mine" No wonder he doesn't allow comments on his videos.
This was kind of hilarious. The fellow in the video seems sincere but he just doesn't know what he's talking about despite the white board and big talk. Hasn't anyone wondered what the purpose is of submersing the piece in water? he never explains it and he never shows it, probably because he doesn't understand it himself, but the whole purpose of submersing the item in water is to determine how much water the item displaces (including the gold and the quartz). That means he would have needed to take a measurement of the water levels before and after submersing the item and take the difference to determine the cubic area/volume of the item. he never did that and he never even alluded to it. He never did it because he couldn't have done it using the bucket he had, which had no measurement scale on it to show how much the water level rose when he put the item into it. Besides, that bucket was far to large anyway. He needed to use a large beaker for that exercise, one with a standard volume scale on the side, which would have given him a delta of X number of liquid ounces. That would translate to a cubic volume. The expected weight of pure quartz would be obtained from that volume. Then the actual piece would be weighed (dry) and the difference would suggest the weight of other, heavier, elements, including gold, are embedded in the item. Again, it's only an approximation and depends on many variables. Just looking at the item, I doubt it contained 7 ounces of gold unless there was a lot of gold embedded at the core of the piece - unlikely but possible. We really won't know since the specific gravity test was never done properly.
Here is a easier method using his figures. X+Y= 529.3 cubic centimetres. Now X19.3 +Y2.63=1574.. Solve for X =10.91 cubic centimetres of gold. 210 grams of Au. Close enough. Assuming pure gold in sample. 95 % pure means 5 percent less is 200 grams Au. From Aust.
It would be useful if you at least told us what the "mathematical constant" is describing. The way you have introduced it is like a magical number that we must trust you with. That is hardly scientific. A complete explanation may not be necessary but at least give us a chance to check out your math for ourselves. Unfortunately this omission undermines the credibility of your video. The rest of your video is helpful. Thank you for that. Now I need to find out about this magic constant elsewhere.
You are using way too much precision in your calculations (your instruments don't support more than two decimal places). And you CANNOT determine the exact amount of gold in ANY specimen without extracting the gold first. Your method give an APPROXIMATE mass of gold in the specimen.
I would not crush that. No way. That is beautiful and Gold Mines are going to be exhausted in the next 20 years. Mother Nature is not creating any more of those!!!
I understand specific gravity. Thought this was going to be another video explaining the basics. Being specific to gold, this took an awesome, unexpected twist. Glad I watched. Subbed. Thanks for sharing... Now, I'm going to be stuck trying to understand how this formula actually works and why these paticular constants were established
Thank you for the video. I have come up with another formula for you that determines the weight of gold in a specimen. The formula is:-
Gold = Ws[Dg(Ds-Dq)]/[Ds(Dg-Dq)] - formula (1)
or
Gold = Vs[Dg(Ds-Dq)/[Dg-Dq] - formula (2)
Dg=Density of gold
Dq=Density of quartz
Ds=Density of specimen
Ws=Weight of specimen
Vs=Volume of specimen
To use your example:
Dg=19.3 g/cm^3
Dq=2.63 g/cm^3
Ds=2.975 g/cm^3
Ws=1574.5g
Using the formula (1):
Gold=1574.5[19.3(2.975-2.63)]/[2.975(19.3-2.63)]
Gold=1574.5[19.3×0.345]/[2.975×16.67]
Gold=1574.5[6.66/49.59]
Gold=1574.5×0.1343
Gold=211g (rounded off)
Like any formula this is only as accurate as the numbers plugged in but gives a more accurate gold weight than equations using constants.
If the volume of the specimen is being used instead then formula (2) can be applied.
For more accuracy I suggest determining the density of a quartz sample from the region your specimen was found using the methods already presented. If gold in the area is not pure this can be accounted for by altering the density of the gold accordingly. This formula in fact can be used to calculate the content of anything within something else if their densities are known.
Hope this helps.
Hi. Would you mind if i asked for help here?
Dry weight 35.56
Wet weight 25.74
???
Thanks
@@jackojeep8276 I calculated the gold content to be about 11.3 (g?). That's about a 1/3 gold content by weight. As mentioned this number will change if the densities of the gold and quartz are different but gives a fair estimation.
specific gravity is used by distilleries to calculate alcohol percentage based on volume. Would love to have this calculation. Please do print formula in Gold Prospectors Mag
that quartz specimen is there no other minerals in it like iron or copper or etc? just curious
You just got a fan and subscriber! You just saved me so much brain pain!!!
Interesting the difference between the dry and wet weight 529.3grams. Perhaps that is the volume 529.3 mls or ccms... x+y= 529.3, x19+ y2.63 =1574.5 solve for x the volume of gold in ccms. Is called a simultaneous equation. Also if ironstone present in quartz use a higher sg. for quartz.
Very informative. Thank you. Do you mind telling where to find such a good specimen?
soo wait, what about items you weighed? do you subtract that from your total? you never said
Excellent
Video. Thank you very much. I have to save it and make my Excel table. That
makes the handling of the big numbers easier.
Informative video...Thanks. Actually it confirmed some of what I knew.
Being a Physicist (Materials Science) I am aware of what a constant is. What is the name of that constant that you did not go into so that I may research it please.
(I am assuming that you are estimating an assay of 18K Gold alloyed with Silver and Copper and it corrects for that.., What percentage of Silver and copper are you estimating?)
How is Prescott Valley these days? Still growing like a weed as it was in the early 2000s?
Thank you for this informative video and help regarding my ironstone / gold piece👍
What issue of GPAA issue did that get into?
Also if a similar piece of quartz can found determine its specific gravity.
Liked the video, liked the specimen piece even better! Wow, what a beauty!
x= 11.144 ccms multiply by the sg of gold.19= 211.8 gms of gold. Probably less because of the presence of ironstone in specimen.
Where did you come up with 1.9 and 3.1 for your dry and wet weight ??????????????????????????
Thank you Kevin, excellent video. Will that piece be left as a specimen, crushed, or the quartz dissolved in acid?
I think it should be "augmented" in other words they should burn off some of the quartz to really reveal the crystaline gold inside... i don't think they should crush such a rare beauty as that...
yeah but the formula actually only compensates for non quarts minerals not strictly gold. It is Very helpful in the long run to give approx value to a piece. Thank you For this demo!
Great job Kevin
Thank you! I have saved and copied n repeated this so many times now I should have it memorized by now but ....drat!🤦♀️I’m getting too old I guess🤣I’m so grateful for your video🙏❤️
Does anyone know where he came up with multiplying 1.9 with the dry weight ? And where he came up with multiplying the wet weight with 3.9 ?????????
Great video, if you dont mind id like to do it in spanish, all i need is a gold specimen and thats gona be the hard part, im gona have to go vist a friend in Real del Castillo and see what he has. Gl and be safe.
Feel free to translate
I am confused. Not by the math but by the answer I got . Which simply put me right back where I started. See, I know what I have is a piece of quartz and gold. I know this. Thing is, I have never had anything like this before, and I don't understand why the gold part of the rock completely encompasses the quartz part, I guess you'd say. It looks like this was dipped in gold. The entire surface is covered except for a very small patch. I don't want to break the rock to see the inside. Okay the problem. My math brought me almost exactly to the original dry weight, except for 1 3333/20000
I checked it twice. I don't know what I am doing wrong. I feel stupid.
It's so weird because you definitely look like a relative of mine!!
My last name is Bull, js!
Anyway I'd like to say thank you and God bless you for all you do!!
I can tell you are a Great man but one should never cross you!! (They will lose)
I heard about you from "Ask Jeff Williams" I really like his show!
This is the 1st video I have seen of yours and it's awesome!
P.S. you should do another video with a rock of the same size with no G in it!!
That would be awesome!!
Anyway keep up the Great work and Thank You so much for all you do!!
Fantastic video. I definitely learned something.
Can you cover source of the constant 25.97.
Excellent video. Thanks!
I was wondering about this question just yesterday. :-)
How to identify purity of gold
Thank you great job.
Very informative .....kudos!
that was very informative video I know there was I way to do that but didn't know how thanks
Well I'll have to admit - this guy seems legit - unlike that Gold Hog guy who obviously plants gold flakes in his equipment - aka salting the "mine" No wonder he doesn't allow comments on his videos.
Great job! Really appreciate it.
and then what if there's pyrite and calcite in the specimen?
This is to give you a estimate of the amount of gold. Not the precise measurement. To do that you would have to extract all the gold, then weigh it.
Where might I find that formula is printable format??
The formula should be in the next issue of gold prospectors magazine
David It has been moved to the Pick and Shovel.
"in" printable format of course
Of course you are assuming no sulphides or carbonates.
This was kind of hilarious. The fellow in the video seems sincere but he just doesn't know what he's talking about despite the white board and big talk. Hasn't anyone wondered what the purpose is of submersing the piece in water? he never explains it and he never shows it, probably because he doesn't understand it himself, but the whole purpose of submersing the item in water is to determine how much water the item displaces (including the gold and the quartz). That means he would have needed to take a measurement of the water levels before and after submersing the item and take the difference to determine the cubic area/volume of the item. he never did that and he never even alluded to it. He never did it because he couldn't have done it using the bucket he had, which had no measurement scale on it to show how much the water level rose when he put the item into it. Besides, that bucket was far to large anyway. He needed to use a large beaker for that exercise, one with a standard volume scale on the side, which would have given him a delta of X number of liquid ounces. That would translate to a cubic volume. The expected weight of pure quartz would be obtained from that volume. Then the actual piece would be weighed (dry) and the difference would suggest the weight of other, heavier, elements, including gold, are embedded in the item.
Again, it's only an approximation and depends on many variables. Just looking at the item, I doubt it contained 7 ounces of gold unless there was a lot of gold embedded at the core of the piece - unlikely but possible. We really won't know since the specific gravity test was never done properly.
My stone sg 2.80 and %6 includes gold😊 very nice. Sir, İ would like to see my stone to you
now if you can find one of those a month you would be set.
Thank you.
Here is a easier method using his figures. X+Y= 529.3 cubic centimetres. Now X19.3 +Y2.63=1574.. Solve for X =10.91 cubic centimetres of gold. 210 grams of Au. Close enough. Assuming pure gold in sample. 95 % pure means 5 percent less is 200 grams Au. From Aust.
Thank your mother for the rabbits.
Yay, first semester chemistry!!!
It would be useful if you at least told us what the "mathematical constant" is describing. The way you have introduced it is like a magical number that we must trust you with. That is hardly scientific. A complete explanation may not be necessary but at least give us a chance to check out your math for ourselves. Unfortunately this omission undermines the credibility of your video.
The rest of your video is helpful. Thank you for that. Now I need to find out about this magic constant elsewhere.
thanks!!
Nice Video. Should the number at time ruclips.net/video/zE3kG9N7OyI/видео.html 5.11 be minus 248 since you are subtracting a larger from a smaller ?
28.3495 grams to an ounce.......
It's a Troy ounce: en.wikipedia.org/wiki/Ounce
You are using way too much precision in your calculations (your instruments don't support more than two decimal places). And you CANNOT determine the exact amount of gold in ANY specimen without extracting the gold first. Your method give an APPROXIMATE mass of gold in the specimen.
I lost you after the oz$.
Ridiculously complicated.
Man nearly 5000toz a ton
Thank you Kevin, excellent video. Will that piece be left as a specimen, crushed, or the quartz dissolved in acid?
I would not crush that. No way. That is beautiful and Gold Mines are going to be exhausted in the next 20 years. Mother Nature is not creating any more of those!!!
Jeffery, NEVER crush a speci piece like that. I have sold specimen pieces for three times spot.