RLC circuit and the control system block diagram

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  • Опубликовано: 14 ноя 2024

Комментарии • 13

  • @Aspire_designs
    @Aspire_designs 3 года назад

    You are the best tutorial teacher here pls keep it up

  • @amirriaz2424
    @amirriaz2424 4 года назад +1

    Your channel is really helpful the way u explain clears the concept much faster

    • @ad.academy3779
      @ad.academy3779  4 года назад +1

      amir riaz Thanks a lot for your feedback and it’s great to hear that my video has helped you well.

  • @chrishadjipetris6059
    @chrishadjipetris6059 2 года назад +2

    You could also use the laplace transform, in order to work with multiplication and division only. That way, the output for block VL(1/L) would be I*S and the two integration blocks would be 1/S.

  • @axmayn
    @axmayn 4 года назад

    thanks a lot, it was a very helpful video after watching 4-5 another videos

  • @elonmask8433
    @elonmask8433 3 года назад

    It'd be really helpful if you make videos for more complicated circuits.
    Not for me, I am going to pass this lesson next week :) but I wanted to say that people need them.

  • @bosats3502
    @bosats3502 4 года назад +1

    Thank you so much fot this video.

    • @ad.academy3779
      @ad.academy3779  4 года назад +1

      Thanks for your feedback and please let me know the contents that you would like to be explained. I’ll do my best to explain them.

  • @kevmck39
    @kevmck39 2 года назад +2

    Gotta get that smoke detector a battery lol

  • @nayyabarif2935
    @nayyabarif2935 4 года назад

    Explanation ❤

  • @ZainabNisa2023
    @ZainabNisa2023 4 года назад

    Thank you!! Can you also pls explain the transfer functions too?

  • @nicolen9216
    @nicolen9216 4 года назад +1

    Is there any chance you could do an example with, say, a voltage input and a current output?

    • @chrishadjipetris6059
      @chrishadjipetris6059 2 года назад

      For series circuits it's easier to add the impedance you have in series and multiply it by current in order to find the voltage. For parallel circuits, it's easier to add the admittance (admittance is equal to 1/impedance), and then multiply it by the voltage to find the current. For the second case, it would be easier to work with input and output current