today is my paper of DC machine of 6th semester EE and i didnt know any thing about DC machine,then i open the youtube and start searching good lec about the topic and i got your channel....know iam fully prepared for my exams.... love you varun bhai from pakistan :-)
Thank you so much ...I am so happy that I could help you...Please also.do consider sharing the videos with your friends and also anyone who might find them helpful...
22:52 What will happen if we decrease Rf instead of increasing while motor is operating in between the low speed zone? Isn't the speed supposed to increase then? Rf is adjustable right?
Sir as Rf is increased , flux will decrease and speed will increase. But sir what about Ea,Ia and toque induced. Will these remain constant after gaining speed as they were before?
torque induced depends on load torque, for stable operation induced torque will be equal to load torque and current will vary correspondingly so that the ind torque = load torque
At about 14:00, briefly, both torque(induced) and omega increases, whilst torque(induced) > torque(load). Subsequently, Ea increases, Ia decreases, and torque(induced) decreases. But for that brief moment in time, was both torque and omega increasing simultaneously?
I don't think there is any mistake..as load torque increases, the induced torque increase and as per the equation derived the speed drop...that clearly seen in the graph I have drawn...
10:45 Ea=K(fi)(omega) flux is decreasing,as speed is inversly propotional to flux, speed should and increase and Ea will be compensated..why that does not happen...please clarify
The increase in speed you are talking about hadn't reached at 10:45, I am going through the sequence how that happens..it is not correct, to take a conclusion and apply it in between the explanation, I hope it is clear...
I have already given a reply... y = mx + c that is the format of the equation if m is +ve the realtion between y and X will be direct , but in our case m is -ve which shows the realtion between speed and torque is inverse...i think you got confused in that part..hope it is clear now
today is my paper of DC machine of 6th semester EE and i didnt know any thing about DC machine,then i open the youtube and start searching good lec about the topic and i got your channel....know iam fully prepared for my exams....
love you varun bhai from pakistan :-)
Thank you so much ...I am so happy that I could help you...Please also.do consider sharing the videos with your friends and also anyone who might find them helpful...
why not bro!!!
i will do share the videos wd my classmate who r facing same problem :-)
Thank you...
love from Bangladesh
You saved me from my exams. Thanks a lot!!!
Glad to be of help...
You are great sir hat's off
Omega depends on load torque ?.. Induced torque increase omega increse or decrease ?
Love that lesson. Thank you
22:52 What will happen if we decrease Rf instead of increasing while motor is operating in between the low speed zone? Isn't the speed supposed to increase then? Rf is adjustable right?
Sir in which lecture did u derive the omega(speed) equation..??
Sir as Rf is increased , flux will decrease and speed will increase. But sir what about Ea,Ia and toque induced. Will these remain constant after gaining speed as they were before?
torque induced depends on load torque, for stable operation induced torque will be equal to load torque and current will vary correspondingly so that the ind torque = load torque
At about 14:00, briefly, both torque(induced) and omega increases, whilst torque(induced) > torque(load). Subsequently, Ea increases, Ia decreases, and torque(induced) decreases. But for that brief moment in time, was both torque and omega increasing simultaneously?
Whatever I have explained is a for a transient time..which you will not be able to notice in real time..
@@ElectricalisEasy Perfect. Thanks :)
sir, external torque demand and torque induce nature is same? what is the difference between them?
I have a doubt sir how accelarating torqur produce increase in speed ? You said it in 14:25 please clarify me ...
thankyou sir
Very good explanation
Thank you
Is it use for constant power application ?
I still don't quite understand how it's possible for a motor to have a speed even though the torque is zero.. could you help me with that sir?
How flux is directly proportional to the field current ?
IL=If+Ia when vt is constant iL is constant so when If dec Ia should increase
ryt??
Sir is it allowable to increse the speed above base speed?
A margin is there for over speed, but not very high deviation is adjustable and it may damage the mechanical bearings etc.....
sir torque is inversely proportional to angular speed but u said it in reverse manner plz clarify this doubt sir
Can you provide me with the time I mentioned it..it is easier for me then to watch the video again...
I don't think there is any mistake..as load torque increases, the induced torque increase and as per the equation derived the speed drop...that clearly seen in the graph I have drawn...
13:59
10:45 Ea=K(fi)(omega) flux is decreasing,as speed is inversly propotional to flux, speed should and increase and Ea will be compensated..why that does not happen...please clarify
The increase in speed you are talking about hadn't reached at 10:45, I am going through the sequence how that happens..it is not correct, to take a conclusion and apply it in between the explanation, I hope it is clear...
Why this effect accrued in case of lower speed section??
I think flux decrease larger than the armature current exactly opposite compared to upper speed case....
sir plz clarify my doubt
I have already given a reply... y = mx + c that is the format of the equation if m is +ve the realtion between y and X will be direct , but in our case m is -ve which shows the realtion between speed and torque is inverse...i think you got confused in that part..hope it is clear now
@@ElectricalisEasy tqqq sir