I dunno if you were joking, but it really did encourage me. It felt like "yes, even this guy teaching it gets that this is horribly boring, its not just me, i just need to power through it!"
What if you have to shift the floating point to the right (0.125) does that make p < 0 with -3 as p ? and u lower the exponent instead of making it bigger ?
I don't know if I fully understand your question, but when you're finding p you will always shift left. What you want to get is 1.- ideally, or even 0.-. You always want to only have one number to the left of your floating point.
+Tomáš Hrubý Yes, in that case You have to shift the coma to the right as many places as needed to satisfy the rule of 1 in front of the coma. Then the constant of shift amont (in video it is 'p') will be negative number. In example if you shift the coma two places to the right then p = -2. Next when you will calculate the exponent, you should do 127 + (- 2) = 125 in decade. Step four, is as in the video.
I did the fraction part differently but this a good video. This video better explained this concept in 10 minutes than my professor did for an hour in a half.
This is better than the other tutorials cause it explains that u need to add 0's to the end when the result is less than 32 bits. I was looking for an answer. Ty!
1. Turn 0.125 into binary 0.125 = 0.001 2. Shift the decimal point to get the 1.ff format in this case to the right 0.001 --> 1.00 Your p is now equal to the number of shifts you made but since you went to the right instead of left the p will be negative in this case p=-3 3. exp = 127 + (-3) = 124 Turn 124 into binary which is 1111100. When you put that number in the 8-bit register reserved for the exponent you get 01111100. 4. Put everything together and you have 0 01111100 00000000000000000000000
Love that pep talk you use at the beginning to get us amped. ;-)
actually cracked up so hard at the intro
Actually love how honest he is about this, it's fucking terrible... can't wait to get over this bs lol
10 minute demo that covers an hour of university material at ny state level, thanks
they get paid per course so i can see why
Dude you made me burst out laughing within 3 seconds of video, I was slightly depressed about my exams tomorrow.
Thanks for the laugh !
i got 100 on my exam because of this guy. thanks so much
The introduction of this video really encourages you to continue watching
I dunno if you were joking, but it really did encourage me. It felt like "yes, even this guy teaching it gets that this is horribly boring, its not just me, i just need to power through it!"
@@luminousdragon same here, it did encourage me to switch the video to 1.5x speed as well lol
Bruh, you're literally saving lifes, thank you!
A lot more clear than my professor. Thanks!
couldn't get a better explanation. thank you very much
this made it so much easier thank you
I like your teaching style bro :D
And this video saved my life
love your enthusiasm :) especially in the first part of the video. ahah Kidding . Thank you
the way he's as done with this as we are
What kind of application do you use to make this video?
EducationAboutStuff the binary number in step 4 doesn't equal 32-bit in length.
Do you stop at the first 1 because it's negative and that's the sign bit?
+Rockoman100 no, that's because that 1 can be implied, saving one bit of information :D
thank u man this video is the only understandable other guys were talking shiiiit
You are saving my life! Thank you!
Where did the negative sign go...can anyone explain?
The whole 1.c class is thankful
hello, can i ask ? if i had 1100.110 in first step ,so i have to shift point like this : 11.00110 ?
Thanks you so much. I have a little question. Why do you place the last zeros at the end instead of before the 1?
what if you have something like -1.5
is -5 in binary not be two's complament of 5 so 011... no?
If i want to make a special 24-bit float what would be the division of the FRACTION/MANTISSA and the EXP given sign takes 1-bit
What if i wanted to convert it with 64 bit precision? i just fill in the missing zeroes in the exponent and the mantissa?
awesome, thanks for the explanation. You explained more clearly than my teacher hahahaha :D
His laugh 😂🌟 02:43
WOOWWW u really explained it well
so at 4. stage zeroes goes to 32 times when number is negative or?
You just fill the rest of the number with 0s, it doesn't matter if the number is positive or negative
Random Strategy ok thanks
thanks you, the method is very very easy to understand
Best tutorial ever!
thanks from Argentina !
thank you great video
Sweet. *high five* Thanks for the explanation! This definitely helps xoxoxoX
awesome video....thanks
really great work by you :)
but how u know the rest of number is 000000000000. what if is 00110011... or 1111011100...?
then just calculate it all :)
Nejquake yup, but izit possible have another method to do ?😂😂
It makes no sense for the rest of the number to be anything other than 0s. Since you would have a different number
Yup
all i need to do is just calculate 😂
*YOU GUYS MUST KNOW THIS - Special case: The IEEE754 for 0.0 is 0000 0000 0000....(32 digits)
very helpful , thank you
Big like for your video
Thank you
Very helpful
Very helpful
10/10
Thank u brother
ty very much
thanks dude
ty for video :)
Thanks
I LOVE YOU, THANK YOU, SUBSCRIBING, AHHHH
this sound like action scenes of kurtlar vadisi' soundtrack. O.o
+Alp Barazi as bayrakları as as
Thanks you!
ty
0.75 is not 110 its just 11
thank you
This dudes voice is agonizing.
hhahaha lol that intro
(C1F70000)IEEE754−32bit=(?)10
i need to solve this :(:(
Thanks
#line17
What do you mean it can float? What is this, water? /joke
I fell asleep
You sound like a really cool guy
Increase the speed to !.25 or 1.5. thank me later
Thank you
Thanks human
I LOVE YOU, MATE, this 10 minutes video explained better than my professor. Simple and clear.
This is fucking awesome, thank you.
+Tomas Leitch Pretty sure he just saved our grades haha
good video, i like the depressed midnight studying setting/voice
straight to the point, thank you 8 years later
This is so helpful! Some comp sci subjects really lack proper easy to understand documentation, but this is honestly perfect
thank you for this video! you even made me laugh:D
Thank u so much..
really helpful for the night before of my exam.
can't thank enough.
Damn Man!... Cool Teaching ...
thanks in 2020
tnx bro...
honestly, youre my spirit animal bro "look i didnt invent this so im just gonna call it the fraction"
was really helpful
hi does mantista or fraction always starting from 1 or we also do start from 0 as well.....??? anyone
Is the largest dec number in ieee 754 127+127=254 2^127
and smallest 127-126=1 2^-126
255 and 0 are exceptions that don't count.
You're so awesome, thanks.
Excellent example, though a bit complex.
What if you have to shift the floating point to the right (0.125) does that make p < 0 with -3 as p ? and u lower the exponent instead of making it bigger ?
I don't know if I fully understand your question, but when you're finding p you will always shift left. What you want to get is 1.- ideally, or even 0.-. You always want to only have one number to the left of your floating point.
if you have number 0.001 (0.125) u have to shift to right to have format 1.ff
+Tomáš Hrubý
Yes, in that case You have to shift the coma to the right as many places as needed to satisfy the rule of 1 in front of the coma.
Then the constant of shift amont (in video it is 'p') will be negative number. In example if you shift the coma two places to the right then p = -2.
Next when you will calculate the exponent, you should do 127 + (- 2) = 125 in decade.
Step four, is as in the video.
This video is the greatest. Thank you for making it.
I finally understood it... Thanks you
1 more example should be added for more understanding.
thank you very very very much sir i am fully understanded
The whole 1.c class is thankful
The whole 1.c class is thankfull
The whole 1.c class is thankful
Thank you very much .ment a lot♥️
That is a cool trick for converting decimal point to binary point!
I am going to sleeping.........
"#twitter"> "#facebook "
you're an awsome guy
Thanks bro
I did the fraction part differently but this a good video. This video better explained this concept in 10 minutes than my professor did for an hour in a half.
really cool video ! although you might wanna decrease the amount of "cheerness" it gets us very amped ! LOL thanx bro !
Thanks bro this is a godsend, i was going through my lecture notes and I have no idea how they can make this seem so confusin, when its super simple.
thanks broo♥
This is better than the other tutorials cause it explains that u need to add 0's to the end when the result is less than 32 bits. I was looking for an answer. Ty!
THANK YOU
thanks man
Pls Help How to convert 0.125 into IEEE 32 Bit
1. Turn 0.125 into binary
0.125 = 0.001
2. Shift the decimal point to get the 1.ff format in this case to the right
0.001 --> 1.00
Your p is now equal to the number of shifts you made but since you went to the right instead of left the p will be negative in this case p=-3
3. exp = 127 + (-3) = 124
Turn 124 into binary which is 1111100.
When you put that number in the 8-bit register reserved for the exponent you get 01111100.
4. Put everything together and you have
0 01111100 00000000000000000000000
Thanks!