Комментарии •

  • @roxannejoypanaguiton2167
    @roxannejoypanaguiton2167 2 года назад +4

    Such a very simple and clear explanation!! I was finally able to understand it. Thank you very much!

  • @luckyuize
    @luckyuize 2 года назад +8

    this is better than my textbook thank you so much

  • @sanaiseed5678
    @sanaiseed5678 Год назад

    Thank you for this video

  • @user-eg8xg4tr4s
    @user-eg8xg4tr4s 8 месяцев назад +1

    Thank you so much ❤

  • @samanthac2216
    @samanthac2216 Год назад

    thank you

  • @sydneymcwhorter2093
    @sydneymcwhorter2093 2 года назад +19

    How did you come up with the reducible representation in the first place? Like how did you know to put 4 for E, 1 for 2C3, and 2 for 3sigma v?

    • @__L563
      @__L563 Год назад +1

      Search construction of character table and any point group you want like c2v or c3v there are alot of helpful videos then after that you do this video.

    • @__L563
      @__L563 Год назад

      Here ruclips.net/video/T1nVUuDDTUw/видео.html

    • @stormingsharks
      @stormingsharks Год назад

      You perform the operations on all the atoms (including the N) to come up with the 4, 1, 2. It's not 3, 0, 1 because that would be excluding the N atom (and only be concerning the Reducible for H atoms), which isn't being done here.

    • @sandyhorton104
      @sandyhorton104 3 месяца назад

      Its the number of atoms that don't move after the operation. In E there is no movement, all 4 atoms stay in the same place so its 4. For 2C3 it rotates around the C3 axis moving all the hydrogens to a different spot but leaving the nitrogen so its 1. For the vertical reflection planes nitrogen and one hydrogen remain the same while the other two hydrogens are reflected to each others position so the number of unmoved atoms is 2.

  • @jkp99999
    @jkp99999 9 месяцев назад

    how do you get an A1 in the first place.