Proof: Composition of Injective Functions is Injective | Functions and Relations

[@Jinsun202]

Clear, informative and well presented. Subscribed. Thank you.

[@WrathofMath]

Thanks for watching and for subscribing, so glad it helped! Let me know if you ever have any lesson requests!

[@sjukingen5332]

Very well represented, I enjoyed this. Thank you!

[@WrathofMath]

Thanks a lot, glad it was clear!

[@christineelin8900]

Thanks, but why is it that in our lesson, to see that fog is injective, you must show that x=y, while yours is x is not equal to y?

[@bachoundaseddik250]

its just the contrapositive of the statement , go to the definition and make the contrapositive

[@bachoundaseddik250]

hope you are doing well in college

[@adarshsmenon3100]

Contrapositive

[@sinamustafa5955]

Thank you ...
..Let f : A → c and g : A → B be functions. prove that there exists a function
h : B → C such that f = h◦ g if and only if ∀x, y ∈ A, g(x) = g(y) ⇒ f(x) = f(y).
Prove that h is unique.

[@alejandromendoza7778]

Why is this video available in 4k?lol

[@WrathofMath]

It's for your viewing pleasure!

[@satshah1492]

confusing

[@WrathofMath]

Thanks for watching and I am sorry it was confusing, do you have a question I can help clear up?