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Clear, informative and well presented. Subscribed. Thank you.
Thanks for watching and for subscribing, so glad it helped! Let me know if you ever have any lesson requests!
Very well represented, I enjoyed this. Thank you!
Thanks a lot, glad it was clear!
Thanks, but why is it that in our lesson, to see that fog is injective, you must show that x=y, while yours is x is not equal to y?
its just the contrapositive of the statement , go to the definition and make the contrapositive
hope you are doing well in college
Contrapositive
Thank you .....Let f : A → c and g : A → B be functions. prove that there exists a functionh : B → C such that f = h◦ g if and only if ∀x, y ∈ A, g(x) = g(y) ⇒ f(x) = f(y).Prove that h is unique.
Why is this video available in 4k?lol
It's for your viewing pleasure!
confusing
Thanks for watching and I am sorry it was confusing, do you have a question I can help clear up?
Clear, informative and well presented. Subscribed. Thank you.
Thanks for watching and for subscribing, so glad it helped! Let me know if you ever have any lesson requests!
Very well represented, I enjoyed this. Thank you!
Thanks a lot, glad it was clear!
Thanks, but why is it that in our lesson, to see that fog is injective, you must show that x=y, while yours is x is not equal to y?
its just the contrapositive of the statement , go to the definition and make the contrapositive
hope you are doing well in college
Contrapositive
Thank you ...
..Let f : A → c and g : A → B be functions. prove that there exists a function
h : B → C such that f = h◦ g if and only if ∀x, y ∈ A, g(x) = g(y) ⇒ f(x) = f(y).
Prove that h is unique.
Why is this video available in 4k?lol
It's for your viewing pleasure!
confusing
Thanks for watching and I am sorry it was confusing, do you have a question I can help clear up?