An AM wave consists of carrier, lower side frequency and upper side frequency component of peak values 10V, 4V, and 4V respectively. If the AM wave drives a 5 KW resistor. Find the power delivered to the resistor by the carrier and each side frequency components.
Better then 2 hours lecture that i face everyday.
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Well explanation mam, I used to search the formulas for AM but i did not found but i saw ur class i found the all formulas related to AM thank you mam
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An AM wave consists of carrier, lower side frequency and upper side frequency component of peak values 10V, 4V, and 4V respectively. If the AM wave drives a 5 KW resistor. Find the power delivered to the resistor by the carrier and each side frequency components.
You are the best ma I love your teaching so much ❤❤❤❤❤❤❤❤❤❤❤❤ continue doing what you are ma I love you
Finally found one of the only compact Communication engg subject playlist for csce sem exams🤩🙏
Really a good explanation.
Better than our clg teacher.
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Thanks you so much for this, I understand it very well. Good Job
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Upload important topics for all units in communication system
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You dropped this 👑
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Thank you mam, your videos are very helpful 🙂
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such a nice explanation mam and i have one dought mam same like this problems will be asked right in the exam means same method ?
plz replay me mam
Yes pa
Awesomely explained
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It is what I was looking for
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if m(t)=5cos(2x10^3pi t)+10cos(1x 10^3pi t) and c(t)=15cos(2x10^6pi t).....how to find modulation index..plz give us hint
First time carrier and usb and lsb then find
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mam in previous video
modulating signal=Am cos 2pi Fmt
but in formula for problem u used as Am sin 2pi Fmt why mam?
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Can we use message signal m(t)instead of modulating signal
Message signal and modulating signal both are same.... Message signal is also called as modulating signal...👍
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@@PadmasriNaban awesome explanation sir
Thankyou maam helped a lot
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Anyone 2025 coming
U told Pusb= m²Ac²/8R at the formula part and in the last problm u told Pusb=m²Pc/4?????
Pc=Ac2/2R
Not Pc mam
I asked for Power of upper and lower side band mam please help me
It will be 4 not 8, It's a mistake.
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in search of gold i got diamond
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