Hi, in 4:37, why did it became {t+1} ? Is it because there is a (t-1)? So we should just write the opposite of its sign? If it is (t-2), does it become {t+2}? What would happen if it is (t^2)?
@@amangoheer8824 A non a-hole would have just described how that is done instead of just being an a-hole, but as you are clearly an a-hole, I guess you were incapable of that. Meanwhile what you said didn't make sense. His back is to a white background while writing on a window, with the camera on the other side of the window facing him. You can clearly see what he is writing in front of his hand, not hidden behind it. Unless you are talking about meshing video layers in post-production (which is also a nice trick), what you described would still come out backwards.
@@amangoheer8824 Fun fact actually, due to the wall being transparent it is actually always going to look the right way compared to something opaque. You can see as such when you write on plastic in front of a mirror, you can read it both in the mirror and from your original position. It's real interesting I think Vsauce did a vid on it once
Super helpful video. I was having a tough time wrapping my head around how to convert piecewise to unit-step and then write its laplace. You made both steps easy and approachable. I am going to use the light switch analogy every-time I get confused, lol.
After searching for every video for unit step function and not understanding a single thing, you made it so much easy to understand( the switch on or off idea make it so easy to grasp😂
Taking differential equations in Summer and my professor (while really good in his work) is rushing pretty fast through the content. Thank You for the video, solved my doubts.
thank you so much for your videos. Examples are how I understand the content best, and you explain this in a much more clear and concise way than my professor.
This is a great video, but when I'm using your method with an example I'm working with, it doesn't really make sense for me. How would you solve the unit step function of f(t)=sin(3t), 0 < t < pi?
sin(3t)*(u(t-0)-u(t-pi)) --breaking it down to the step function = e^-0*s * L{sin(3+t)} --anything raised to the zero is 1 so you just solve the Laplace of sin (3+t) using a trig identity, L{sin (3+t)} turns into L{sin(3)*cos(t)+cos(3)*sin(t)} sin (3) and cos(3) are constants so they can be pulled out you're left with : sin(3)L{cos(t)} + cos(3)L{sin(t)} and the Laplace of sin and cos are direct formulas. That is for the (u(t-0)) now just repeat with t-pi. I haven't worked that out but the pi might actually give some nice cancellations somewhere-- i.e. sin(pi)=0 Thanks for the question! Helped me review for my final tomorrow!
@@christopherpayne7650 f(t)=sin(3t)·[u(t-0)-u(t-π)]=sin(3t)·[u(t)-u(t-π)] L{sin(3t)·[u(t)-u(t-π)]}=L{sin(3t)·u(t)}-L{sin(3t)·u(t-π)} sin(3t)·u(t-π) sin(3(t-π))=sin(3t-3π)=sin(3t-π)=-sin(3t) - Trigonometry L{sin(3t)·u(t)}+L{sin(3(t-π))·u(t-π)} 3/(s^2+3^2 )+(e^(-πs) )·3/(s^2+3^2 ) (1+(e^(-πs) ))·3/(s^2+9) This is the process of the task, I would say I calculated the result correct.
I was so focused on how he setup the camera so that he could write and the letters don't come up backwards, that I had to re-watch the video lol. Good explanation on the building of unit step functions using piece-wise functions, thank you!
This was a lot of help. Its amazing how having something properly explained makes math easier, unlike the magic my "professor" was doing. Thank you so much for clarifying
so I'm a little curious; that thing you did before to the piecewise function before applying the Laplace transform; is that decomposition of the function? Saw a similar lot on a math stack exchange and I just want to be sure I got it right
my textbook does not show any of the steps to get this. They just threw out the step function and how this times the function can get a laplace transformation but for things like the middle part of the piecewise example shown I had no clue how to attack that because I didnt know where this function was coming from and why it was what it was. Thanks for the clarification!
So your going t+1 to counter t-1 then transforming each is the same as me changing the t to (t-1)+1) and distributing that? We were taught that the variable in front of the step function had to equal the step functions on and off, ie t-1 in this case, or if it was a constant it didn't matter, as you did show. Trying to understand this, got exam tomorrow 😅
I could be wrong or my teacher taught me wrong. But I thought you were supposed to shift the t’s by the limits themselves. So say (t+2) for the upper limit, not (t+1)?
For example, if the first piece of the function was t and not 0, what does t*u(t-0) look like? Does this mean that t is on or off at 0? Or does is simply equate to zero?
t*u(t-0) is the same as t*u(t) which also means that there will be e^(-0*s) so its just 1 and for t*u(t) , it will be Laplace of just t which is 1/s^2 so the answer is 1/s^2
How come when he took the transform of 2u(t-2) (at 5:00) it came out to 2e^(-2s)L{1} and not 1e^(-2s)L{2+1}? Isn’t the 2 in front of the u the function? and since c=1 and we are using the form e^-cs L{f(t+c)}?
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Hi, in 4:37, why did it became {t+1} ? Is it because there is a (t-1)? So we should just write the opposite of its sign? If it is (t-2), does it become {t+2}? What would happen if it is (t^2)?
Not only does he explain step functions in a way anyone can understand, he write it all backwards. This man is not human ...
He's obviously writing normally and then inverts the video. Use some common sense
@@amangoheer8824 A non a-hole would have just described how that is done instead of just being an a-hole, but as you are clearly an a-hole, I guess you were incapable of that. Meanwhile what you said didn't make sense. His back is to a white background while writing on a window, with the camera on the other side of the window facing him. You can clearly see what he is writing in front of his hand, not hidden behind it. Unless you are talking about meshing video layers in post-production (which is also a nice trick), what you described would still come out backwards.
I low-key love him
@@amangoheer8824 Fun fact actually, due to the wall being transparent it is actually always going to look the right way compared to something opaque. You can see as such when you write on plastic in front of a mirror, you can read it both in the mirror and from your original position. It's real interesting I think Vsauce did a vid on it once
Others: Writing infront of the board
Him:writing behind the board..
Great explanation tho
Thanks very much!
@@BriTheMathGuy hey ! you are actually writing mirror image or election form haiii !!
reflection*
@@mohit9028 I'm writing normally, it's video editing :)
Super helpful video. I was having a tough time wrapping my head around how to convert piecewise to unit-step and then write its laplace. You made both steps easy and approachable. I am going to use the light switch analogy every-time I get confused, lol.
This makes everything about the Heaviside function seem so simple...Thanks my guy! I really appreciate it!
Excellent video! You really helped me out in my advanced engineering math class; my professor has an "interesting" teaching style.
Glad I could help!
SAME
You guys weren't at U of I, were you?
No
Learnt more in 6min than I did for over an hour with a similar tutorial
Your version of solving it is so much better and coherent. Subscribed
What a freakin stud; made this idea so easy to wrap my head around. Thanks man!
Glad to help ya out!
Thanks so much!!!! I took DE a year ago and now I'm doing Laplace Transforms in mechanical design!!!!!!!!!!!!!!!!!!!!!!!
After searching for every video for unit step function and not understanding a single thing, you made it so much easy to understand( the switch on or off idea make it so easy to grasp😂
Thanks for the help! You really explained the Laplace transform well. I like the "light switch" analogy for the piecewise functions
Glad it was helpful!
This guy has just taught me how to do a problem in 6min that my math lecturer couldn’t teach me in a month
No confusing sketches. Just straight to the point thank you
Taking differential equations in Summer and my professor (while really good in his work) is rushing pretty fast through the content. Thank You for the video, solved my doubts.
You are one of the best few ✨🔥
Legend. Watched 4 other videos explaining this subject but nobody else explained how to do it with a function multiplied by two step functions!
I spent 2 days figuring this out and I finally got it 1hr before my exam starts. Now I’m gonna make sure I don’t forget! Thanks so much for the help
i hope u failed ur exam
I'm late to the party, but this was great. Exactly what I needed as a supplement in a 6-week 4 credit summer class!
Thank you so much for putting out the fire in my head. Super explanation. Thank you sir.
thank you so much for your videos. Examples are how I understand the content best, and you explain this in a much more clear and concise way than my professor.
You're very welcome!
Keep up the great work BriTheMathGuy, you saved me on my assignment! Very understandable and succinct explanation.
Glad I could help!
This is a great video, but when I'm using your method with an example I'm working with, it doesn't really make sense for me. How would you solve the unit step function of f(t)=sin(3t), 0 < t < pi?
sin(3t)*(u(t-0)-u(t-pi)) --breaking it down to the step function
= e^-0*s * L{sin(3+t)} --anything raised to the zero is 1 so you just solve the Laplace of sin (3+t)
using a trig identity, L{sin (3+t)} turns into L{sin(3)*cos(t)+cos(3)*sin(t)}
sin (3) and cos(3) are constants so they can be pulled out you're left with :
sin(3)L{cos(t)} + cos(3)L{sin(t)} and the Laplace of sin and cos are direct formulas.
That is for the (u(t-0)) now just repeat with t-pi. I haven't worked that out but the pi might actually give some nice cancellations somewhere-- i.e. sin(pi)=0
Thanks for the question! Helped me review for my final tomorrow!
all that is wrong nvm ;(
@@christopherpayne7650
f(t)=sin(3t)·[u(t-0)-u(t-π)]=sin(3t)·[u(t)-u(t-π)]
L{sin(3t)·[u(t)-u(t-π)]}=L{sin(3t)·u(t)}-L{sin(3t)·u(t-π)}
sin(3t)·u(t-π)
sin(3(t-π))=sin(3t-3π)=sin(3t-π)=-sin(3t)
- Trigonometry
L{sin(3t)·u(t)}+L{sin(3(t-π))·u(t-π)}
3/(s^2+3^2 )+(e^(-πs) )·3/(s^2+3^2 )
(1+(e^(-πs) ))·3/(s^2+9)
This is the process of the task, I would say I calculated the result correct.
watchin this b4 midterm, Bri mannnn u helped me a lot keep doin ur stuff
wow. very good explanation. something somebody actually needs. bravo good sir
bitch ass. wasnt helpful af
شكرا لك على هذا الشرح لو كانت هناك ميزه الترجمه الى اللغه العربيه لكان رائعا
Thanks for explanation.
Please also explain in detail about laplace of unit step function ..
u(t-1) & t.u(t-1)
Wel explained tutorial really helped
I was so focused on how he setup the camera so that he could write and the letters don't come up backwards, that I had to re-watch the video lol. Good explanation on the building of unit step functions using piece-wise functions, thank you!
This is a nice clear way of solving for the Unit step function. Thank you!
Glad you enjoyed it!
This was the only explanation that I could make sense of... thank u very much bro
you are a savior... thank you so much
thank you so much, I was banging my head against the table trying to figure out how to set it up.🙏
Out of all the videos I watched, this one got the best content.
dude, you dont really have to make applied maths so difficult like in this video. damn!!
This was a lot of help. Its amazing how having something properly explained makes math easier, unlike the magic my "professor" was doing. Thank you so much for clarifying
You are the only guy who explained how to any function to unit step function. Thanks
Glad to help!
You're very articulate , could listen to you all day
so I'm a little curious; that thing you did before to the piecewise function before applying the Laplace transform; is that decomposition of the function? Saw a similar lot on a math stack exchange and I just want to be sure I got it right
Just in time for finals! Thank you so much. Do you have a preferred way of viewers to support you? Patreon or paypal etc
I really appreciate your support simply by watching my videos and commenting :). Have a wonderful day!
Great Video, cleared up so much before my exam tomorrow. Thank you!
Thank you very much.
You have saved my day🙏
You are a lifesaver
Perfect teaching.
Perfect camera view.
GOAT. Better than Dr. Bazett, since instead of giving impossible terms to understand, you have explained it with simple words
I had to miss the class where we went over piecewise functions, this is amazing
thank you!! simple and straightforward!!!
The best start to finish solution I have seen good show thks
Woow.. Just woow... It was very easy to understand. Thank you
Thank you so much sir, very clear explanation 🤩
is no one going to mention this man is writing backwards. what a legend
my textbook does not show any of the steps to get this. They just threw out the step function and how this times the function can get a laplace transformation but for things like the middle part of the piecewise example shown I had no clue how to attack that because I didnt know where this function was coming from and why it was what it was. Thanks for the clarification!
You are a hero
this video made me feel safe ;-;
thanks dude
Never expected this to be this easy.
Thanks man!!
You bet!
You just saved my grade in controls thank you so much!
Glad I could help!
So your going t+1 to counter t-1 then transforming each is the same as me changing the t to (t-1)+1) and distributing that? We were taught that the variable in front of the step function had to equal the step functions on and off, ie t-1 in this case, or if it was a constant it didn't matter, as you did show. Trying to understand this, got exam tomorrow 😅
I could be wrong or my teacher taught me wrong. But I thought you were supposed to shift the t’s by the limits themselves. So say (t+2) for the upper limit, not (t+1)?
Just a little confused on where the (t-1) and (t+1) went because they were distributed. Did they cancel out?
For example, if the first piece of the function was t and not 0, what does t*u(t-0) look like? Does this mean that t is on or off at 0? Or does is simply equate to zero?
t*u(t-0) is the same as t*u(t) which also means that there will be e^(-0*s) so its just 1 and for t*u(t) , it will be Laplace of just t which is 1/s^2 so the answer is 1/s^2
Thank you so much, my teacher doesn't speak good english and is honestly crap at teaching. Book with this unit is very unhelpful.
Great piece of understanding.thank you so much
You're very welcome. Have a great day!
Quick and straightforward, great vid
Thanks so much!!! You're helping me get that good grade in the final stretch, thanks!!
very glad to hear it! Best of luck!
Oh my gah, these problems were giving me a headache until this video. Bless you sir
at 4:22 why you take L{t+1} instead of L{t}
Laplace Transforms!
ruclips.net/video/vtA5xyDZoRU/видео.html
Thankyou man..❤ 🥺
This is an excellent explanation.
thank you man, this really helps
Very glad to hear it. Have a great day!
thank you so much! I have a differential equations paper in 2hrs
you made it so wonderfully easy thank you
Yoh!!!!! you saved me ,i was really getting scared.You made this quite easy.Thanks
No problem 👍
Love it bro. Thanks for the help
You got it :)
You made it so easy, you saved my grades thank you!
Glad it helped!
How come when he took the transform of 2u(t-2) (at 5:00) it came out to 2e^(-2s)L{1} and not 1e^(-2s)L{2+1}? Isn’t the 2 in front of the u the function? and since c=1 and we are using the form e^-cs L{f(t+c)}?
If it was variable it would have been t+2. Since there is no variable shouldn’t it be 2*e^-2s L{2?} instead of L{1}
Thank you so much Sir.. You cleared it out my confusion....
Happy to help!
You earned a subscriber ❤️
Way more easier sir , thank you
Glad it helped!
thanks a lot😊
salute sir. got right into the meat and potatoes unlike others
Saw this 2 hes before my exam..thanks man..it helped a lot
thanks A LOT
Sir how one can thank you for your help you did it in easiest way
Glad it helped!
How did you do the distribution?
Great video! Greetings from Argentina
Thanks very much. Have a great day!
Thankyou. I was really confused on how to use the formula as I came across different form of it.
Very glad to help!
Big help, thank you!!
Thank you!
You saved me buddy 🙌🏼
You’re welcome! Have a great day.
thanks for saving my life
You got it :)
Exceptional Fam!
Appreciate that!
Great video helped me out way better than my professor
Glad it helped!
How are you writing backwards?
final is tomorrow, god bless you brother
You are the best
Thanks :) Have a nice day!
It helped a lot! Thanks bro!
thank you🫶🏻
Excellent video. Thank you!
You're very welcome. Have a great day!
THANK YOU
thank you very much i appreciate it
This guy writing in mirrored for us what a legend
actually, he can write like normal then inverted it later
how would you do if you have .... e 0
e is constant