Para doon sa mga nagtatanong paano nakuha yung 3√ 3/4 horizontal distance sa member AB... Yung force kasi na 20kN, perpendicular sa member AB, so yung horizontal distance from A to B ang kukunin para magkaroon ng moment. Ang first step ay solve for the length of member BC by √ 3(sin30). Equal yan sa √ 3/2 Then draw a perpendicular line from point B to line AC. For example, let the point of intersection be O. Therefore, pag sinolve natin yung length ng OC at sinubtract natin sa AC, makukuha natin yung hinahanap na horizontal distance. So para makuha natin ang OC (from right triangle BOC), use (√ 3/2)cos60, which is equal to √ 3/4. Finally, (√ 3) - (√ 3/4) = 3√ 3/4
wag nyo eh shortcut sir para lalong maintindihan,, salamat.. step by step lang kc may mga low gets ksing viewers tulad ko na kailangan ng maraming discussion para maintindihan..
Thank you Sir. Hoping po for more examples and explanations about truss analysis. Nasa part ako ngayon ng buhay ko na nasa dilim ako. Kayo nagpaliwanag ng lahat salamat po Sir!
this reignited my love for math especially Engineering mechanics. Thought I hate math but since college for no reason, I was shocked how easy this subject can be.
11:11 I think force EG should be positive, since the moment is counterclockwise 🔄 ⬆️ ⬅️ Will be positive 🔁➡️⬇️ Will be negative So force EG will be in compression Am I right?
Good day, may I ask what software you're using for your videos? Maybe at some point of my journey I'd start making videos for engineering also. Thank you
Pag nakuha mong value ng isang member is POSITIVE "TENSION yun ( bale Yung direction is papalayo sa point or yung napili mong joints... Pay NEGATIVE naman yung value nya COMPRESSION yun( kabliktaran lang ng tension yung direction ng compression)😁
if negative ung value nya, then yung direction is opposite sa inassume mong initial direction. Bale baliktarin mo lang ung direction. If negative nakuha mo sa compression, then tension dapat sya, and vice versa. Ibig sabihin lang ng negative is mali ung direction na inassume mo, baliktarin mo lang
Yung force kasi na 20kN, perpendicular sa member AB, so yung horizontal distance from A to B ang kukunin para magkaroon ng moment. Ang first step ay solve for the length of member BC by √ 3(sin30). Equal yan sa √ 3/2 Then draw a perpendicular line from point B to line AC. For example, let the point of intersection be O. Therefore, pag sinolve natin yung length ng OC at sinubtract natin sa AC, makukuha natin yung hinahanap na horizontal distance. So para makuha natin ang OC (from right triangle BOC), use (√ 3/2)cos60, which is equal to √ 3/4. Finally, (√ 3) - (√ 3/4) = 3√ 3/4
Itama nyo nalang ako pag mali,minultiply po ata sa area=1/2(bh), where,b=b/2(para makuha is centroid ng triangle which is perpendicular sa distance a=(3√3/4)). b=√3/2 h=3 a(distance)=1/2[(√3/2)(3))
@@nikotorralba4936 pagkukuhain po ang centroid,pero kung medyo naguguluhan po kayo search nyo po yung properties of the centroid of triangle malalaman nyo po yan kung bakit yung base naging b=b/2.
Example 2: 1.Find the Hypotenuse Dahil perpendicular yung angle na nakatapat sa √3 m so 90° at sya din ang highest angle and hypotenuse. 60° naman yung nakatapat sa opposite or line AB. Use law of sine to get line AB/opposite: sin 90/√3=sin 60/o o=(sin 60√3)/sin 90 o=3/2 - opposite 2. Perform another law of sine to get the horizontal distance of B. -Para magawa ang law of sine gumawa ng guhit from B hanggang base, so yung new angle ng nakatapat sa line AB ay 90° so sya na yung bagong hypotenuse at yung nakatapat naman sa dating hypotenuse na √3 m ang new distance(x) ay 60° naman ay siya yung bagong opposite/adjacent. To get new distance (x) use law of sine: sin 90/h=sin 60/x x=(sin 60*h)/sin 90 x=sin 60*(3/2)/sin 90 x=(3√3/4) m or 1.3 m Ganito nakuha ni sir yung distance sa example number pasensya na kung medyo magulo medyo mahirap magexplain sa chat😅 madali lng sana kung sa personal.
Hello po, sa pagkakaalam ko ay pwede po siya kahit alin basta consistent lang po sa pag gamit sa buong solution 😊 ang clockwise po ay pwedeng positive or negative same answer pa rin po.
Hi! AB is 1/4 of 3m (vertical distance of A-H) and since kinukuha po is moment you have to multiply (1/4 of 3m) to sqrt 3 (horizontal distance from A to B)
Good day sir. Paano po pag colinear yung dalawang joints but hindi kasama yung isang joint sa section na cinut, kasama pa po ba yung length nung section na yun?
usually tignan molang yung length ng kada members po. example yung 3 wc is the height ng member DE, 4 naman yung length ng member EG, tpos 5 naman makukuha mo using pythagorean theorem.
Para doon sa mga nagtatanong paano nakuha yung 3√ 3/4 horizontal distance sa member AB...
Yung force kasi na 20kN, perpendicular sa member AB, so yung horizontal distance from A to B ang kukunin para magkaroon ng moment. Ang first step ay solve for the length of member BC by √ 3(sin30). Equal yan sa √ 3/2 Then draw a perpendicular line from point B to line AC. For example, let the point of intersection be O. Therefore, pag sinolve natin yung length ng OC at sinubtract natin sa AC, makukuha natin yung hinahanap na horizontal distance. So para makuha natin ang OC (from right triangle BOC), use (√ 3/2)cos60, which is equal to √ 3/4. Finally, (√ 3) - (√ 3/4) = 3√ 3/4
(√3/2)cos60 = ✓6/4
ung √3(sin30) solution po ba sya for finding unknown side ng right triangle?
@@eliascomawas7963 3 lang po yung nasa square root then over 2
wag nyo eh shortcut sir para lalong maintindihan,, salamat.. step by step lang kc may mga low gets ksing viewers tulad ko na kailangan ng maraming discussion para maintindihan..
Hindi ito naturo ng statics prof namin, dahil sa pandemic, good thing may ganitong vids sa YT. Thanks, sir!
Thank you po. Grabe, ngayon ko lang naintindihan 'to. God bless po, engr.
Thank you Sir. Hoping po for more examples and explanations about truss analysis. Nasa part ako ngayon ng buhay ko na nasa dilim ako. Kayo nagpaliwanag ng lahat salamat po Sir!
Anong year nyo naop
better than my online class discussion
Pano nalang kaya kaming mga modular 😥
@@charddell9525musta engineering?
this reignited my love for math especially Engineering mechanics. Thought I hate math but since college for no reason, I was shocked how easy this subject can be.
Sanaol
Edi wow
Naol po
lol
thumbs up sir! lahaat ng topic ng engineering from basic hanggang sa katapusan i discuss mo ! galing galiiing !
Dito ko mas naintindihan huhu😭♥️
maganda kayo mag discuss sir,, wag nyo lqng eh shortcut,, hehhe sana gumawa kpa maraming tutorial about mechanics start nyo sa vector..
thank you, mas naging malinaw ang method of section
mas naiintidhan ko pa to kesa sa teacher ko sa statics, dahil jan subscribe kita love you HAHA
Nice thanks po at naintindihan ko na rin yung methods of sections
ang simple at linaw nyo po magturo. mas naiintindihan ko na ngayon 😭 thank you po!
Buti pa po kayo sir, mabagal ang pacing. Prof ko po marathon! Hirap intindihin kasi po ang bilis! :D
sobrang natuto ko dito boss💓
This is better than my instructor hahahaha
ang daling maintindihan sa paraaan mo ng pag eexplain
Thank you po sa videos, it really helps. More example pa po sana sir heheh.
Thank you sir! Big help po, supeerr!
Thank you, Engr.
Sir centroid please!! Solid ng tutorial nyo! Salamat dito
Thank you so much Engr!
Welcome!
@@engrleir sir tanong ko
@@engrleir pwede ba?
11:11 I think force EG should be positive, since the moment is counterclockwise 🔄
⬆️ ⬅️ Will be positive
🔁➡️⬇️ Will be negative
So force EG will be in compression
Am I right?
Napansin ko din po nagassume Ako as positive EG so 105(8)-60(4)+EG(3)=-200 or 200 compression
Yes nalito din ako
Compression ata lahatng force jan boss!!
Sa Methods of joints and sections talaga ako nahirapan sa statics sana nakita ko tong video mo sir last sem hahaha
THANKYOU SIR BIG HELP!
Welcome! Thanks for watching! 🙏
NATUTO AKO NG MATINDI A KAHIT SAGLIT LANG
Napakahusay po
Thank you so much po!
hello po dun sasecond example how come na naging 3square of 3 over 4 po yung distance hihi. enlighten me please
okay po yong discussion ninyo sir wag lang po sana i shortcut. hehhe thank you po.
Milyong Salamat po!!!!
Thank you po! New subscriber here!
thank youuu! 💙
Sir may video po ba kayo pano na solve yung measurements sa last part? Medyo mahina kasi ako sa ratio and proportion
Saan po nanggaling yung (3√3)/4? 13:42
sir gawa kayo tutorial first step para sa truss section.. kung pano sya ma identify ng mas madali,,. salamat.
more examples pa po Sir hehe ganda po manood eh
Sir, more example nga po sa last problem
Sir ask sana ako paano po nakuha ang value na 3square root of 3 / 4
Tumatanggap po ba kayo tutoring services Engr. Leir? Pwede niyo poba kong turuan kahit isang araw lang?
Salamat po Sir.
Thank you sir
pa'no po nakuha yung special triangle na 3-4-cube root?
Good day, may I ask what software you're using for your videos? Maybe at some point of my journey I'd start making videos for engineering also. Thank you
Pano po kunin yung length na 3square root of 3 over 4
salamat po
sir pwede rin po bang gawing assumption sa gantong side ng section is clockwise positive or mas matrabaho po?
Hello sir, ask kolang kung pwede ka rin magmoment sa E para nakuha Forces DG
Thank you💚
na ol ganyan magturo
thank you po
Thanks for watching!😆
sa 11:12 nakuha ko naman sa calcu sa FEG is 208KN
Ask kolang po sa electrical engineering din po ba may solving din po ba sa mga trusses
Lods parequest naman ng tutorial about frame analysis
Salamat master
Sa joint D po, (vertical y), yung DE po ma didisregard ba yung 50kN?
hello sir ask ko lang kung saan galing at paano nakuha yung 4,3,5 na adjacent opposite at hypotenuse
543 triangle tawag dyan para sa slope. Proportional yan if 2 sides ay given. If given kaagad na 543, then yun na ang gagamitin.
bat 3 sq. root of 3 over 4 distance ng AB?
paano nyo po nakuha 3√3/4 ? sana masagot
Re: Problem 2, Summation of Moment with Respect to Point A. Need pa po bang iconsider yung vertical component ng Force BD?
Thank you po💚
Pwede po kayo gumawa ng video pano po ma determine kung tension or compression? Please po🥺 Thank youuuu
Kapag ung force po palayo sa joint tension. Pag papunta naman sa isang joint compression po.
Pag nakuha mong value ng isang member is POSITIVE "TENSION yun ( bale Yung direction is papalayo sa point or yung napili mong joints... Pay NEGATIVE naman yung value nya COMPRESSION yun( kabliktaran lang ng tension yung direction ng compression)😁
if negative ung value nya, then yung direction is opposite sa inassume mong initial direction. Bale baliktarin mo lang ung direction. If negative nakuha mo sa compression, then tension dapat sya, and vice versa. Ibig sabihin lang ng negative is mali ung direction na inassume mo, baliktarin mo lang
@9:48 wala po bang force ang FH?
hindi ba pag clockwise is positive at counterclockwise is negative?
thanks
Pwede pobang malaman yung process kung paano kinuha yung 3√3/4, yung sa last part po moment atm ng 20KN, sana po may maka sagot
Yung force kasi na 20kN, perpendicular sa member AB, so yung horizontal distance from A to B ang kukunin para magkaroon ng moment. Ang first step ay solve for the length of member BC by √ 3(sin30). Equal yan sa √ 3/2 Then draw a perpendicular line from point B to line AC. For example, let the point of intersection be O. Therefore, pag sinolve natin yung length ng OC at sinubtract natin sa AC, makukuha natin yung hinahanap na horizontal distance. So para makuha natin ang OC (from right triangle BOC), use (√ 3/2)cos60, which is equal to √ 3/4. Finally, (√ 3) - (√ 3/4) = 3√ 3/4
Sir paano mag calculate ng bowstring truss vertical nya para mag curve may video kBa nito?
Kuya Engr. May tatanong po sana ako kung paano na come up yung distance ni 20KN na 3squarokt of 3 over 4
Itama nyo nalang ako pag mali,minultiply po ata sa area=1/2(bh),
where,b=b/2(para makuha is centroid ng triangle which is perpendicular sa distance a=(3√3/4)).
b=√3/2
h=3
a(distance)=1/2[(√3/2)(3))
@@kenthjonespaderes9419 hi lodi, ask lng po if yung b=b/2 is standard formula po ba?
@@nikotorralba4936 pagkukuhain po ang centroid,pero kung medyo naguguluhan po kayo search nyo po yung properties of the centroid of triangle malalaman nyo po yan kung bakit yung base naging b=b/2.
Yung last ex po, bakit po hindi kinuha yung BC?
Paano po pag ang pinapahanap ay magkakalayo? Halimbawa po member BD, CE and FG.
sir kahit di na po ba talaga kunin yung reactions? or depende lang sa problem?
eyyyy
Hello sir! Sa section method po ba mag-assume tayo na yung ibang members ay walang forces?
Shear and moment diagram naman sir.
Engr. Paano po nakuha yung (3√3)/(4)?Kindly answer this. THANK YOU
Same question hehe
Example 2:
1.Find the Hypotenuse
Dahil perpendicular yung angle na nakatapat sa √3 m so 90° at sya din ang highest angle and hypotenuse. 60° naman yung nakatapat sa opposite or line AB.
Use law of sine to get line AB/opposite:
sin 90/√3=sin 60/o
o=(sin 60√3)/sin 90
o=3/2 - opposite
2. Perform another law of sine to get the horizontal distance of B.
-Para magawa ang law of sine gumawa ng guhit from B hanggang base, so yung new angle ng nakatapat sa line AB ay 90° so sya na yung bagong hypotenuse at yung nakatapat naman sa dating hypotenuse na √3 m ang new distance(x) ay 60° naman ay siya yung bagong opposite/adjacent.
To get new distance (x) use law of sine:
sin 90/h=sin 60/x
x=(sin 60*h)/sin 90
x=sin 60*(3/2)/sin 90
x=(3√3/4) m or 1.3 m
Ganito nakuha ni sir yung distance sa example number pasensya na kung medyo magulo medyo mahirap magexplain sa chat😅 madali lng sana kung sa personal.
@@princesilva3803 sir pwede po ba patulog mag solve ?
Pano nakuha yung 200kn sir ?
hindi po ba yung distance nung AB sa example 2 ay 3/2 m ?
Yes po. AB is 3/2 m. I used the vertical projection which is ABcos30 so 3/2 x sqrt3 /4
Sir if there is a horizontal force at the joint B, going towards the right.
Do we have to include it in the moment equation or only the 40kn?
Sir pwede po bang kayo nalang prof namin hahaha
pano nyopo nakuha yung Hy?
paano nas solve po yung 3(sqrt 3)/4 na distance?
Good evening sir pano nyu kinuha yung 105KN?pag sa calcu na -1664 yung lalabas
San po nakuha ung 5?
paano po nasolve yung distance ng point A at B
sa poblem 2 nyo po?
(2)
Sir bakit d po pweding 4 ang eh cucut na member?
what if walang tab(y) and tab(x). yung binigay lang is tab?
sir pag method of section kahit saan lang ba pwede mag cut?? I means pwede sa side ng roller support o pwede rin sa kabila??
Yes. Kahit saan pwede.
wait, so going clockwise is negative and counter clockwise is positive? or the other way around?
Hello po, sa pagkakaalam ko ay pwede po siya kahit alin basta consistent lang po sa pag gamit sa buong solution 😊 ang clockwise po ay pwedeng positive or negative same answer pa rin po.
Sir bat po 3 4 5 yung slope hindi 2 ,1.5, at 2.5 since nahati na po yung force EG?
in terms of triangles po, ung 3 4 5 at 1.5 2 2.5 ay similar triangles naman so parehas lang po sila ng angles
Thank you po engr . Pareho pala ng sagot hehe
sir pano po kuhanin yung 3(sqrt3)/4?
Hi! AB is 1/4 of 3m (vertical distance of A-H) and since kinukuha po is moment you have to multiply (1/4 of 3m) to sqrt 3 (horizontal distance from A to B)
@@allylouise thank you po
sir, pa namandesign naman po ng truss na 30 m ang span, salamat po
pano nakuha FDG sa calcu?
Good day sir. Paano po pag colinear yung dalawang joints but hindi kasama yung isang joint sa section na cinut, kasama pa po ba yung length nung section na yun?
Un ung length na icoconsider mo if magmomoment ka doon sa isang joint
Paano po kung walang given na angle sa problem no. 2?
pa request po how to identify zero force members po
Hello po, pano po nakuha yung Hy=105kN 😢 thank you poo
sir, papano po nakukuha yung angle na 3 4 5?
usually tignan molang yung length ng kada members po. example yung 3 wc is the height ng member DE, 4 naman yung length ng member EG, tpos 5 naman makukuha mo using pythagorean theorem.
Square root of 4²+3² or square root of base²+height²
Pano po malaman ung triangle 3/4? Sana po wag nyo ishort cut huhu
13:39 pano po nakuha distance (3√3)/4 dito po
Sa 2nd problem po ba yan idol? I think given lang po siya as a horizontal distance nung force from the point A.
sir spring and suspended rod