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This method works great, but it seems to be limited for reactions with more than 4 components. It works when a reaction has 4 or fewer reactants/products, but the ABCD rule does not seem to extend to other E or F. Is there another method that does work on reactions with more than 4 components?
Mam, Thank you for helping me master such a unique and easy technique(far easier compared to our textbook techniques), it has truly been and will be helpful in the present and the upcoming times!
I really like Byju's specially Kriti maaam .She teaches everything very deeply and clearly. Mujhe jyada English nhi aati so Byju's kya aaap Hinglish mein padha sakte hai please
Thank you, mam, for introducing that helpful shortcut during the lesson. The time-saving technique you demonstrated has proven invaluable in optimizing my workflow. I appreciate you taking the time to share your expertise and provide us with such a practical learning experience.
Ma'am according to my observation if value of A or B or C or D becomes a fraction then we have to make it whole number by multiplying the denominator with both the sides
Divya mam,a awesome teacher.......❤ when she is teaching my whole mind is gonna concentrate on her.....😊..... I really proud to be a byju's student....... Vinay sir is so serious while teaching😅😊
Ma'am I tried to use this trick for the following equation :- CO+O2 →CO2 However, the Trial And Error method is working for this equation, but the ABCD rule is not working here. It is resulting in a decimal value. Please help ma'am
aCO + bO2 --> cCO2 Trial and error is better for this one as it's a simple equation, but you can do a bit of algebra like this: C: a = c (1) O: a + 2b = 2c (2) Sub (1) in (2), c + 2b = 2c --> 2b = c cCO + (c/2)O2 --> cCO2 Then you can do some simple algebra: Divide through by c, and multiply through by 2 2CO + O2 --> 2CO2
@@cricup3835 Yes, you can do that. aNaHCO3 + bH2SO4 -> cNa2 + dSO4 + eCO2 + fH2O Na: a = 2c (1) -> c=a/2 H: a + 2b = 2f (2) C: a = e (3) O: 3a + 4b = 4d + 2e + f (4) S: b = d (5) Then sub for e and b in (4) using (3) and (5) 3a+4d = 4d + 2a + f -> f=a Now sub for f = (2) b = a/2 Then we have: a b=a/2 c=a/2 d=a/2 e=a f=a aNaHCO3 + a/2H2SO4 -> a/2Na2 + a/2SO4 + aCO2 + aH2O Then multiply through by 2 and divide through by a 2NaHCO3 + 1H2SO4 -> 1Na2 + 1SO4 + 2CO2 + 2H2O As the equations get more complex, linear algebra/matrix methods make it easier to solve a system of equations Also, you can alternatively recognise that SO4 is an ion and equate coefficients for SO4
Actually this is so long than the original method🥲 but I can use this to cross-check if necessary. And also is this method valid if there are more than 2 reactants and products ( like E and F is also there!?)
📢 Have you tried BYJU's Mini Learning Program yet 🔔
Key Features:
• 3 live classes with 2 teacher advantage
• 15 days Free access to unlimited content on Think and Learn Premium App
• One on One Mentor Support
👉 Link: byjus.com/mlp-partner/?partner=you_tube
Do not miss this chance ⚠
I have been working on a equation for alomst two hours and I was almost about to cry. This video saved my tears.
This works out really quick than using the methods in textbook consuming lot of time
Tq mam I am feeling this so easy to balance
Tq mam...
Thank u so much mam for this amazing trick 🎉❤
Really helpful amazing trick
This method works great, but it seems to be limited for reactions with more than 4 components. It works when a reaction has 4 or fewer reactants/products, but the ABCD rule does not seem to extend to other E or F. Is there another method that does work on reactions with more than 4 components?
Can we solve this chemical equation by using abcd method?
NaHCO3 + H2SO4 → Na2 + SO4 + CO2 + H2O ?
@@cricup3835 no
No we can solve'em it's easy ...... We are just using the mathematics to equate both the sides
simultaneous linear equations will solve the problem
ya, I also have the same doubt....
Ma'am Thank u so much ....I tried it in my exam paper and I got full..,...Please post more videos
Thanks so much
Thank youu so much ma'am 😊
Thank u so much mam......
Thankk youu for your trick at end of my 10th I realise how to balance eqauation
Wow mam thank you 😀 so much for this giving this golden rule well I'm missing you
Thank u so much mam. This have helped me a lot. I'm
Really grateful to byjus 🎉😊
mam how to do if there are 2 large numbers and there coefficients are different
Thank you so much mam
Thanks a lot😊🙏🏻
😊🎉
Very good technique
Thank you mam
How can we apply this method fr photosynthesis reaction
Thank you mam🎉
Mam I really like ur teaching bcz u always be happy while teaching and we feel like studying ❤
Mam can you explain balancing of chemical equation of photosynthesis by this method
Thankyou mam. It helped a lot
Hey, Glad to know our session was helpful! Please subscribe our channel for updates on upcoming sessions!👍
You're a lifesaver!
youre a wonderful teacher mam 💯💯💯
Mam, Thank you for helping me master such a unique and easy technique(far easier compared to our textbook techniques), it has truly been and will be helpful in the present and the upcoming times!
VERY HELPFULLY session 😢😊
That's amazingggg
Thanks a lot
It's good mam
Just wow ❤🎉 amazing
It Was helpful in my exam Ma'am😇😇
What if reactants or products are 1 or more two or three
Thank you so much
Thank u mam❤❤❤
I really like Byju's specially Kriti maaam .She teaches everything very deeply and clearly. Mujhe jyada English nhi aati so Byju's kya aaap Hinglish mein padha sakte hai please
no
Byjus is really good and best way to learn
Thanks Hari, Glad to hear that, Keep Learning with us😊
You are a genius
Thank you mam I just loved the trick
Most welcome 😊 Please subscribe for more Interesting classes!
@@BYJUSClass910 sure already subscribed and thanks for replying 🤩🤩🤩
Great !!! Perfectly Explained !!!
Thanks vv much 😁🌝
Thank you, mam, for introducing that helpful shortcut during the lesson. The time-saving technique you demonstrated has proven invaluable in optimizing my workflow. I appreciate you taking the time to share your expertise and provide us with such a practical learning experience.
Ohh thank you so much mam for this all tricks I liked and useful also 😇💜
Most welcome 😊 Please subscribe for more Interesting classes!
Thanku mam❤
Shut up, it's just hit and trial method, go learn logical method u fool
Wow ! This trick was amazing . Any equation can balance from this trick . 👍👍🙏🙏😊😊😊
Hello Neeraj, Glad you enjoyed it, Stay tuned for more😊
Ma'am according to my observation if value of A or B or C or D becomes a fraction then we have to make it whole number by multiplying the denominator with both the sides
Amazing! Stay tuned to our Channel for further updates on upcoming Amazing Sessions! 👍
And after multiple also we won't get it bro
Then try this CO2 +H20 = C6h12o6+ o2
@@Suguna1978
Can we solve this chemical equation by using abcd method?
NaHCO3 + H2SO4 → Na2 + SO4 + CO2 + H2O ?
@@cricup3835 yes you can....
Can we use this method in our boards or not?
One doubt mam why the formula in the product should be mention with subscript
Very good explanation thanks ma'am myself shaurya
Thanks and welcome, Keep Watching for more Amazing sessions👍🏻
Thanyou so much mam amezing trick
Most welcome 😊 Please subscribe for more Interesting classes!
Can we solve this chemical equation by using abcd method?
NaHCO3 + H2SO4 → Na2 + SO4 + CO2 + H2O ?
Very easy trick mam
Mam can we use this trick in boards ??
inever understood this equation but thanks toyou my kid is good👌👋💥
wt if there are 2 same numbers and they are the highest number like 2 is highest and b and d both have 2 then wt shud we do?
ma you are a literal saviour mam thankyou so much mam thankyou so much
MAM CAN WE APPLY THIS IN OUR BOARD EXAMS
Abcd rule was given by alakh pandey sir already ❤😊don’t copy byjus
This method has not been invented by him...And these are some particular topics..No one is copying the other.
Who is copying there helping others ?
A mentel
This is a method no one is copying from anyone are u mad?
If U've learnt already from alakh pandey then y have u come here to learn? 🤣
Divya mam,a awesome teacher.......❤ when she is teaching my whole mind is gonna concentrate on her.....😊..... I really proud to be a byju's student....... Vinay sir is so serious while teaching😅😊
💀
@@krutzart2999 Naah bro he is just showing his respect
nothing elseeee
@@alphateam2816 ok bro
Keep it up!Don't ever give up💯
Ma'am if two number are equal then what we should take the largest number????????
❤
Mam can we do this is in 7th exam
Please balance Al + HCl →AlCl3 +H2 by ABCD rule
Maam,what we'll do if the same greatest number is repeating?Which letter we will choose as 1?
Oh I got it now, we can consider which letter is coming first.Then the answer is right.
And thankyou so much for this shortcut.😊😀
Thanks a lot ma'am 😊
Check out this equation KO2 +H20>KOH+O2
Thank u so much Divya man 💓 i had been not understanding this concept
But u have made it easy now
Thank you mam. It is very useful
Keep watching Praneeth 😊
Mam is it all OK if we use this ABCD rule in examinations?
wtf who caress just do it maan
If more than one's coefficients are same then how to solve 😢???
What a explanation😮.....
Thanks a lot mam....
Love you too mam
The trick does not seem to work for me for this equation:
Cu + H2SO4 = CuSO4 + SO2 + H2O
I have been trying for almost an hour
😢
Exactly
😮 thank you mam u just saved me 😅from tomorrow's chemistry👨🔬 exam 😂
1:09:28
what if BaCO3 + HNO3 --> Ba(NO3)2 + CO2 + H2O. What should we do when they ask twice or thrice in a chemical equation. could you please explain it.
Can we solve this chemical equation by using abcd method?
NaHCO3 + H2SO4 → Na2 + SO4 + CO2 + H2O ?
Ma'am I tried to use this trick for the following equation :-
CO+O2 →CO2
However, the Trial And Error method is working for this equation, but the ABCD rule is not working here. It is resulting in a decimal value.
Please help ma'am
aCO + bO2 --> cCO2
Trial and error is better for this one as it's a simple equation, but you can do a bit of algebra like this:
C: a = c (1)
O: a + 2b = 2c (2)
Sub (1) in (2), c + 2b = 2c --> 2b = c
cCO + (c/2)O2 --> cCO2
Then you can do some simple algebra:
Divide through by c, and multiply through by 2
2CO + O2 --> 2CO2
@@drofeng
Can we solve this chemical equation by using abcd method?
NaHCO3 + H2SO4 → Na2 + SO4 + CO2 + H2O ?
@@cricup3835 Yes, you can do that.
aNaHCO3 + bH2SO4 -> cNa2 + dSO4 + eCO2 + fH2O
Na: a = 2c (1) -> c=a/2
H: a + 2b = 2f (2)
C: a = e (3)
O: 3a + 4b = 4d + 2e + f (4)
S: b = d (5)
Then sub for e and b in (4) using (3) and (5)
3a+4d = 4d + 2a + f
-> f=a
Now sub for f = (2)
b = a/2
Then we have:
a
b=a/2
c=a/2
d=a/2
e=a
f=a
aNaHCO3 + a/2H2SO4 -> a/2Na2 + a/2SO4 + aCO2 + aH2O
Then multiply through by 2 and divide through by a
2NaHCO3 + 1H2SO4 -> 1Na2 + 1SO4 + 2CO2 + 2H2O
As the equations get more complex, linear algebra/matrix methods make it easier to solve a system of equations
Also, you can alternatively recognise that SO4 is an ion and equate coefficients for SO4
Can we solve na +h2o = naoh +h2
By this method
What if there is no highest number
How to balance equations in *10min
why byjus app is not in pakistan
Can we do this method in Bord Exam
?
I am not getting the answer
On I can't understood
Hi Mem 👌🏻👌🏻👌🏻
Hello Mem 👌🏻👍🏻👍🏻👌🏻
Hello Sanjay😊
Faulty, doesnt work
I got a fraction
Jitne mam ne time lagaya usse aadhe time meh mene solve kr diya 😂
Still facing problem. No use 😢😢
Balance photosynthesis using this and enjoy yourself getting screwed 🤣🤣🤣🤣🤣
It's somewhat confusing 😢😢
Did not understand
It is to long and to much lagging.
mam your voice is slightly reduced
Who else are watching this video before the examination day ? 😂
actually i cant understand
Actually this is so long than the original method🥲 but I can use this to cross-check if necessary.
And also is this method valid if there are more than 2 reactants and products ( like E and F is also there!?)
𝖵𝖾𝗋𝗒 𝗀𝗈𝗈𝖽 𝗍𝗋𝗂𝖼𝗄 😮😮❤❤
It's just hit and trail method, I wanna learn logical method bruh
Mam but this trick doesnt work for CO(g) + O2(g)⟶CO2(g)
Can we solve this chemical equation by using abcd method?
NaHCO3 + H2SO4 → Na2 + SO4 + CO2 + H2O ?
Just use hit and trial method 😅