Understanding Common Mode Rejection Ratio

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  • Опубликовано: 8 сен 2024

Комментарии • 12

  • @Kenobiii
    @Kenobiii 11 месяцев назад +8

    I'm getting into RF engineering and your videos help me soooooo much to understand many of the concepts a lot better!!!! It's all explained so well and clear, thank you so much!

    • @pauldenisowski
      @pauldenisowski 11 месяцев назад +4

      Thank you! I sometimes tell people that I'm making the videos I wish that I had when I started in engineering :)

    • @Floyd..B
      @Floyd..B 11 месяцев назад +1

      ​@@pauldenisowski And you are doing a perfect job at that.

    • @waferlayout
      @waferlayout 8 месяцев назад

      真強你

  • @stud_mechatronic_polito_22
    @stud_mechatronic_polito_22 4 месяца назад +2

    thank you, now it's clearer; I was getting crazy with that indian accent -_- but apart the indian accent "all about electonics" is a great yt channel.

  • @nareshkumar4207
    @nareshkumar4207 11 месяцев назад +1

    Thanks for this good lecture

  • @KingdomAddict
    @KingdomAddict 9 месяцев назад +1

    Thank you for the lectures; they are very helpful, thank you. Question: Should Vout be Adm(V2-V1) instead of Adm(V1-V2) shown in the video?

    • @pauldenisowski
      @pauldenisowski 8 месяцев назад

      Yes - thank you for catching that. Vout is Adm * (Vplus - Vminus). In retrospect, I should have used Vplus an Vminus instead of V1 and V2. Thanks again for the correction!

  • @user-jc9kn4uy2u
    @user-jc9kn4uy2u 7 месяцев назад +1

    What I don't understand, is that if noise is present in both inputs of the OA, when you subtract them, you should see 0V. So i do not understand why it's amplified.