I don't think you understand the amount of lives you have saved and the amount of people who have gotten into their first choice uni just because of your video's. I always know if my teacher can't do it, Eliot Rintoul can! But honestly u deserve an award for taking your time to help us very confused kids
[Timestamps] 1:52 - How changing conc. of a reactant could affect rate 5:34 - Orders of reaction 7:43 - Rate Equations 12:22 - Determining the Rate Equation (from a table) 22:25 - Calculating k and its units (+using this to calculate rate) 29:50 - More Exam Questions
@@muniroloko3584 damn. I'm in y13 right now and I'm pretty sure that's going to be me in a few months. did u fail chem or did u not get the grade u needed. if u mind me asking
I just wanted to say how grateful I am to you for helping me with AS Chemistry!!! Today I found out I achieved a grade B for AS Chemistry, and its all thanks to you!! Thank you a lot, and I look forward to A2 to continue watching your videos :). You're a great help.
8 years later and still saving lives, I watch your videos all the time and every time you provide such an easy explanation! You helped me get an A* in my AS level exam and hopefully your videos will help me get that in the real thing! Thank you so much your a legend
Bloody hell! Sat in class unable to do this and suddenly the whole concept just seems so easy to understand! Thank you! Will be using your videos to pass chemistry!
Great video! I started a2 a couple weeks back and quite frankly had no idea what I was doing! This video really has cleared up kinetics for me and I attempt questions with a lot more confidence, I shall be donating!
All your videos are so helpful, I went from an E in AS chemistry to a B in the final exams, thank you for everything, you explain better than my teachers and I understand
Important to note at 18:25 that you can only cancel the x10 to the powers if the powers are all the same (eg in the example they are all to the power of -6 and thus you can just cancel them). great vid though helps explain it really clearly. :)
Hi thank you so much for your videos, they helped me achieve a really high A grade in my AS!! With an A* prediction for this year ... hopefully if I continue watching I will get there! Really appreciate your hard work & efforts..
great way ti recap a topic. Now that I'm getting closer to my A Level exams, I am using these videos to effectively recap the previous content at 1.5X the speed and it is reallly usefullll!!! can't thank you enough
Nicely done I struggled with the working out orders from concentrations that were different in the table but your explanation has fixed it. Thank You :)
I just went from panicking about this topic to now fully understanding and answering questions with correct answers. All after investing just 37.54 minutes Wow-you are a saviour, thank you, sir!
This video saved me. My teacher couldn't explain this well at all (well he barely explained it) and I've failed to chase him up outside lesson so thanks sm
31:38 Order of reaction, with respect to one of the species, is the power to which the concentration of that species is raised in the rate expression. So isn't the answer simply 2?
yeah, he just got a bit lost in his explanation so he forgot to actually state the answer, but he was right in his explanation. Idk why im commenting 7 years later
can not thank you enough - i have a test tomorrow and was shitting myself but i feel so much happier and i think i understand it - i will let you know how i do!
such a great explanation always so helpful is it possible you could make a video on Arrhenius equations and how to rearrange it with experimental data :) thank you for your videos they're always super helpful
Omg ur videos are sooo helpful they've actually saved my life multiple times!!! Could I ask if you can make a video on the Arrhenius equation and its calculations? Thanxxxxxx
You're the reason I'm gonna do well in a levels your videos are so brilliant I understood all the chapters from you thank you so much Just wish you had partition coefficient also
At 24:51 you forget to add the squared to the value in the equation. Not a big issue as you still put the right answer down which can only be derived from squaring it. :)
HI, thank you so much for these videos! I'm currently learning about carbonyl chemistry (carboxylic acid, esters and isomerism), however I couldn't find it in the playlist. I was wondering when you would please upload them?
Hi, Thank you this video is very helpful and somehow you explain it way better than my teacher. Can you please do an Equilibrium video? would really appreciate it thanks :)
I apologize in advance as this question may be badly worded . However, given a scenario when the concentration of one substance is halved and the effect this has is rate X4, but the other side of the table is not constant, how would we then work out the order of the other substance. Instead of multiplying by the initial rate by the orders square , would we then divide by the orders square?
+yusuf christie nah...nvr divide...always times....but since u found a factor of (1/2) in the concentration of first molecule, work out the second one... if concentration change of the second molecule is 4; then order is 0 for first and 1 for second if concentration change of the second molecule is 2; then order is 0 for first and 2 for second if concentration change of the second molecule is 8; then ooder is 1for first and 1 for secoind etc etc etc so bascially Work out the concentration change of the second molecule......i see u saying the con for second is not constant....but u can still work out using the factor u got for molecule1 and some sort of info u'd be given in question or intial rates (or both) to conclude; never divide....just stick to multiplying (if wanna divide... multiply by 1/2)
+yusuf christie I'm sorry that I missed your comment, but massive thanks to Cabdulrahman for helping! Right, so you're looking at a situation where in 2 experiments, each reactant has a different concentration i.e. no constants to make it easy. But you know that the rate is x4 when looking at the 2 experiments and that the first (which I will call A) is halved. In this case, you would need to know the order with respect to A. If it was 0 order, A would not affect the rate, 1 would mean that the rate would be halved and 2 would mean that the rate would be quartered (square of half). Once you know what A would have done to the rate, look at how the rate has changed from what A would have done to it and this tells you how the other reactant (which I will call B) has affected the rate based on the order. It's hard to go into too much detail without numbers really, but if you can find an example for me like this, I will try and help!
In regards to the units of the K constant wouldn't it just be easier to remember that 1 order - s^-1 2 order - moldm^3s^-1 3 order - mol^-2dm^6s^-1 Instead of working it out like that, would save time.
Thank-you for the videos, helped me to get an A in AS Chemistry. Just wondering if you have covered all of the AQA A2 topics in your unit 4 and unit 5 videos. Will you be making/ have you made videos on nomenclature or equilibria?
vOzyv My plan is to get all of CHEM4 done at some point this year. If I don't do it all, I'd definitely like to get the rest of the Acids and Bases topic done.
hi at 33 minutes, u explain why its zero order, i thought if its 6^2 to make it times 36, then it would be second order, could u try an explain it pls?
Thank you for this video, really useful for homeschooling Y12s. Just wondering, @31:48 , would you not state the order number e.g. [D]^ or [E]^ ? Thanks
Another useful video! Thanks ever so much for putting the time and effort into making these videos! .. in question 1aii you were asked to work out a value for the initial rate in experiment 2. What if you were asked to work out the conc of one of the compounds instead? How would you do that?
Imran Khan Hey, Imran! A good question! I can't say that I've seen a question like that (I may have missed it...) - but it's possible! Imagine the following rate equation... rate = k [A] [B] If you were asked to calculate the concentration of A, you would just rearrange the equation make [A] the subject. i.e. [A] = rate / ([B] x k) That helped?
E Rintoul Hi Sir, This question had come up in the Jan 2008 paper (question 6ai). I came across it in the summary questions in the Nelson Thornes book. It does make sense now that you have explained it! Thanks again for making these videos, they have been incredibly useful!
I don’t think the answer for question 1 a is right at 24:08 -because you haven’t squared b in the actual calculation but remembered to do the squared for the units. 24:08
Have all the videos for chem4 been uploaded and added to the playlist or are there some yet to be made? what about chem5? is that playlist complete too? thanks
Hello Mr E Rintoul, First of all, thanks for helping me so much in AS, all I did for revision whilst on study leave was watch your videos and do past papers, and I think because of that both my unit 1 and 2 exams went really well, hoping for an A in August :) My question is, which topics in unit 4 and 5 are not covered yet?
skwli I'm glad I was of some help! I'm yet to cover some of the acids and bases stuff in unit 4 and maybe some other bits of structure determination. Unit 5 is a little sparse still; there's electrode potential stuff to do, a load of stuff on complexes, entropy etc. The plan is to get it all done, it's just a slow process!
rdhanda01 Honestly I can't remember which past paper the questions are from! Sorry! I can tell you that it would more than likely be from the start of the paper, but no more than that I'm afraid!
This was good, i watched this too see what a2 is about and not bad. If the rate eq = k[B]^2[C] Does the 2nd order act as a squared? Because when you calculated the value of k i see you did not take the 2 into acc but when calc the rate you did.
E Rintoulhow come you skipped the explanation at 33:29 and also could you have used experiments 4 and 5 to deduce the order of reaction with respect to E
@Eliot Rintoul what software do you use to make these videos.. seems like an effective way for me to jot down key points and definitions without having to use up so much paper and it's something I can look up at on my phone anytime and anywhere, thanks
Govarthan Rrrr he uses photoshop, or has at some point, he mentions it in one video and also some screen recorder ofc. Paint would probably do the same job.......😎
ShortManFilmsLtd I think I'll get Acids & Bases done soon - I need to think how I'm going to separate the various topics. Obviously there is already a video on buffers up!
I was just wondering if you're going to do a video on the equilibrium constant Kp for homogeneous systems anytime soon? It would be highly appreciated!
Hi there, firstly thank you for all your videos... they have helped me and a lot of my friends so much!! secondly, will you continue making videos for the old specification??
sandesh thapa It's definitely one that I'm aiming to do. I'll more than likely do the intermolecular forces first, possibly followed by general bonding at a later date.
I don't think you understand the amount of lives you have saved and the amount of people who have gotten into their first choice uni just because of your video's. I always know if my teacher can't do it, Eliot Rintoul can! But honestly u deserve an award for taking your time to help us very confused kids
[Timestamps]
1:52 - How changing conc. of a reactant could affect rate
5:34 - Orders of reaction
7:43 - Rate Equations
12:22 - Determining the Rate Equation (from a table)
22:25 - Calculating k and its units (+using this to calculate rate)
29:50 - More Exam Questions
@Productivity that's what I'm here for too. Arrhenius equation might be new spec?
@Productivity yh yr13
@@muniroloko3584 how did u 13 go. did u pass?
@@thebigadam7574 hey bro, not so well I’m doing a third year at college unfortunately resitting Chem :/
@@muniroloko3584 damn. I'm in y13 right now and I'm pretty sure that's going to be me in a few months. did u fail chem or did u not get the grade u needed. if u mind me asking
they say he’s still looking for the pen to this day
great video btw thanks
I just wanted to say how grateful I am to you for helping me with AS Chemistry!!! Today I found out I achieved a grade B for AS Chemistry, and its all thanks to you!! Thank you a lot, and I look forward to A2 to continue watching your videos :). You're a great help.
I wouldn't have done so well without your videos! Thanks a lot, for the millionth time! :D
***** Really well done - that's a superb place to be heading into the A2 course!
Splendid explanation. Just wondering, could you please cover The Arrhenius Equation since it is included in the new specification.
Yeah that would be really helpful if you could, I'm very confused by it
^^^^^ this
8 years later and still saving lives, I watch your videos all the time and every time you provide such an easy explanation! You helped me get an A* in my AS level exam and hopefully your videos will help me get that in the real thing! Thank you so much your a legend
thx soooo much. I love the fact I can rewind again and again. I am slow to understand, but once I get it I get it. You are a live saver :)
Spot z No problem :)
Jesus christ you make this twisted subject seem so easyy, Please make more A2 videos :)
+Naruto Uchiha Haha! That is one of my favourite comments! Thanks a lot :)
Blessed be the mighty name of Jesus Christ
When calculating k, you forgot to square the [B] in the calculation. Apart from that, great video, thank you.
Rose Mary [worldwide HANDSOME] thank God it wasn't only me
he did it in the calculation but forgot to write it down in the working out
Thanks for clarifying
Bloody hell! Sat in class unable to do this and suddenly the whole concept just seems so easy to understand! Thank you! Will be using your videos to pass chemistry!
"I've lost the pen again" loooool
anyway thank you so much for this video!!!!!!
Great video! I started a2 a couple weeks back and quite frankly had no idea what I was doing! This video really has cleared up kinetics for me and I attempt questions with a lot more confidence, I shall be donating!
+Nick Patel I'm very glad it's been of some help!
All your videos are so helpful, I went from an E in AS chemistry to a B in the final exams, thank you for everything, you explain better than my teachers and I understand
+Dizem Tekin Wow that's some good going. Remember though, it's down to you that you've gone from an E to a B, not me!
Important to note at 18:25 that you can only cancel the x10 to the powers if the powers are all the same (eg in the example they are all to the power of -6 and thus you can just cancel them). great vid though helps explain it really clearly. :)
Hi thank you so much for your videos, they helped me achieve a really high A grade in my AS!! With an A* prediction for this year ... hopefully if I continue watching I will get there! Really appreciate your hard work & efforts..
+fatima shah Smashed it! That's amazing!
please do more A2 videos! You've helped me so much :D Thanks!
Theresaa Packk More will be on the way soon...
Got an A in as because of these videos and now going to use these videos for A2 to help me get A in A levels... thankyou so much
Diego Costa good luck in the title race XD
Thank you so much! You explained this whole concept in such a short time. Wish you were my Chem Tutor!
great way ti recap a topic. Now that I'm getting closer to my A Level exams, I am using these videos to effectively recap the previous content at 1.5X the speed and it is reallly usefullll!!! can't thank you enough
Nicely done I struggled with the working out orders from concentrations that were different in the table but your explanation has fixed it. Thank You :)
Please make more A2 VIDEOS. THESE ARE AMAZING! ESPECIALLY THAT YOU DID THE EXAM QUESTION AT THE END! THANKYOU
I just went from panicking about this topic to now fully understanding and answering questions with correct answers. All after investing just 37.54 minutes
Wow-you are a saviour, thank you, sir!
This video saved me. My teacher couldn't explain this well at all (well he barely explained it) and I've failed to chase him up outside lesson so thanks sm
17:50 I’m gcse and managed to find the rate equation from this table when I paused the video. TOO EASY
31:38 Order of reaction, with respect to one of the species, is the power to which the concentration of that species is raised in the rate expression. So isn't the answer simply 2?
yeah, he just got a bit lost in his explanation so he forgot to actually state the answer, but he was right in his explanation.
Idk why im commenting 7 years later
can not thank you enough - i have a test tomorrow and was shitting myself but i feel so much happier and i think i understand it - i will let you know how i do!
Please make more videos for unit 4 - you helped me more than my teachers last year and I got a good grade so I hope to replicate that this year :).
+Ayy Keep working hard and I'm sure you will! There will be more videos coming for Unit 4!
1 Hour before AQA A Level Chemistry Paper 2… my Friend just found out he needed to know rate equations. Don’t be like my friend.
This is the best last minute revision no doubt about it!! Thanks so much
25:33 he forgets to square value of B while substituting looks like an error
"I've lost the pen again" thats what she said :)
Seriously tho you are a legend in our school, keep making great videos
Thx e rintoul, your videos have helped a lot. Really thankful and appreciate your work.👍✌️
Thank you for this, without you I wouldn't be able to get a head start on my A2 course :)
THANK YOU SO MUCH SIR YOU ARE AN ANGEL I UNDERSTAND CHEM NOW THANK YOU !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
"I have lost the pen" lol
Im watching these videos from now trying to get a grip of this course early, thanks a lot for the videos man!
***** No worries - I hope they help!
such a great explanation always so helpful is it possible you could make a video on Arrhenius equations and how to rearrange it with experimental data :) thank you for your videos they're always super helpful
This video has just saved me, thank you so much!!
Omg ur videos are sooo helpful they've actually saved my life multiple times!!! Could I ask if you can make a video on the Arrhenius equation and its calculations? Thanxxxxxx
I believe you forgot to write down the squared of a part of a calculation.
So helpful E Rintoul. Equilibrium?
Yes, please A2 Equilibrium. All the kA and ksp and stuff, PLEASE!
You're the reason I'm gonna do well in a levels your videos are so brilliant I understood all the chapters from you thank you so much
Just wish you had partition coefficient also
Very clear and good video although it does not mention anything about the Arrhenius equation
Can someone please explain how in 1.b) for e, how it is zeroth order? I can’t seem to understand. At time 32:09
These videos are so helpful, thankyou!
At 24:51 you forget to add the squared to the value in the equation. Not a big issue as you still put the right answer down which can only be derived from squaring it. :)
HI, thank you so much for these videos!
I'm currently learning about carbonyl chemistry (carboxylic acid, esters and isomerism), however I couldn't find it in the playlist. I was wondering when you would please upload them?
your videos are certified 10/10....thanks
anything on acyl chloride....nucleophilic addition-elimanation??
+Cabdulrahman Mohamed There's nothing as of yet on acyl chlorides, but it's definitely coming! And thanks for the kind words :)
thank you so much! I didn't understand the indices bit at all when my teacher went through it but now I do!
Really helpful. I was struggling to do MCQ questions about this but I got it now
Great video! You might possibly save my life this year
Omg pleaseeeeeeee do a2 videos soon:(((((
Jess245 There are some! In fact I think almost all of CHEM4 is done...?
But chem5 :( your videos are just so helpful!!
Jess245 Thank you for the kind words :) watch this space for more CHEM5!
Hi, Thank you this video is very helpful and somehow you explain it way better than my teacher. Can you please do an Equilibrium video? would really appreciate it thanks :)
this video was very helpful. THANK YOU
Mohammed Choudhury No problem!
I apologize in advance as this question may be badly worded . However, given a scenario when the concentration of one substance is halved and the effect this has is rate X4, but the other side of the table is not constant, how would we then work out the order of the other substance. Instead of multiplying by the initial rate by the orders square , would we then divide by the orders square?
+yusuf christie nah...nvr divide...always times....but since u found a factor of (1/2) in the concentration of first molecule, work out the second one...
if concentration change of the second molecule is 4; then order is 0 for first and 1 for second
if concentration change of the second molecule is 2; then order is 0 for first and 2 for second
if concentration change of the second molecule is 8; then ooder is 1for first and 1 for secoind
etc etc etc
so bascially Work out the concentration change of the second molecule......i see u saying the con for second is not constant....but u can still work out using the factor u got for molecule1 and some sort of info u'd be given in question or intial rates (or both)
to conclude; never divide....just stick to multiplying (if wanna divide... multiply by 1/2)
+yusuf christie I'm sorry that I missed your comment, but massive thanks to Cabdulrahman for helping! Right, so you're looking at a situation where in 2 experiments, each reactant has a different concentration i.e. no constants to make it easy. But you know that the rate is x4 when looking at the 2 experiments and that the first (which I will call A) is halved. In this case, you would need to know the order with respect to A. If it was 0 order, A would not affect the rate, 1 would mean that the rate would be halved and 2 would mean that the rate would be quartered (square of half). Once you know what A would have done to the rate, look at how the rate has changed from what A would have done to it and this tells you how the other reactant (which I will call B) has affected the rate based on the order. It's hard to go into too much detail without numbers really, but if you can find an example for me like this, I will try and help!
i thought i would never understand this, thank you so much
In regards to the units of the K constant wouldn't it just be easier to remember that
1 order - s^-1
2 order - moldm^3s^-1
3 order - mol^-2dm^6s^-1
Instead of working it out like that, would save time.
Vessa Costello it probably is but in the text book it says that it helps to be able to work them out too :)
Why am I in love with ur handwriting
Hello Mr Rintoul, I wanted a quick explanation as to E is 0 order @ 33:37 please. I somehow calculated it as first...
Thank you
Forget that, I missed the 36 bit, thanks 😂
You're seriously a life saver mate, Have you got any videos up going through unit 4 and 5 past papers by any chance?
Thank-you for the videos, helped me to get an A in AS Chemistry.
Just wondering if you have covered all of the AQA A2 topics in your unit 4 and unit 5 videos.
Will you be making/ have you made videos on nomenclature or equilibria?
Just read your replies on other comments.
Thank you for your videos! They're incredibly helpful. For the new AS aqa spec is any of this needed or is this solely for A2? Thank you again :)
These really are helpful, thank you! Could you please do a video explaining chapter 4.2&4.3?
vOzyv My plan is to get all of CHEM4 done at some point this year. If I don't do it all, I'd definitely like to get the rest of the Acids and Bases topic done.
Hi there, just wanted to ask for Chem 4 are you going to complete all the topics? btw your vids are a great help
+Omar Alias I'm going to try to!
hi at 33 minutes, u explain why its zero order, i thought if its 6^2 to make it times 36, then it would be second order, could u try an explain it pls?
Thank you for this video, really useful for homeschooling Y12s. Just wondering, @31:48 , would you not state the order number e.g. [D]^ or [E]^ ? Thanks
I think you would
@24:30 why did you not square the value for b?
Another useful video! Thanks ever so much for putting the time and effort into making these videos! .. in question 1aii you were asked to work out a value for the initial rate in experiment 2. What if you were asked to work out the conc of one of the compounds instead? How would you do that?
Imran Khan Hey, Imran!
A good question! I can't say that I've seen a question like that (I may have missed it...) - but it's possible!
Imagine the following rate equation...
rate = k [A] [B]
If you were asked to calculate the concentration of A, you would just rearrange the equation make [A] the subject.
i.e. [A] = rate / ([B] x k)
That helped?
E Rintoul
Hi Sir,
This question had come up in the Jan 2008 paper (question 6ai). I came across it in the summary questions in the Nelson Thornes book. It does make sense now that you have explained it!
Thanks again for making these videos, they have been incredibly useful!
This video saved me ....
+DiLLZGFX Deep.
+DiLLZGFX yo 0.0
Josiah Campbell Fancy that
I don’t think the answer for question 1 a is right at 24:08 -because you haven’t squared b in the actual calculation but remembered to do the squared for the units. 24:08
Have all the videos for chem4 been uploaded and added to the playlist or are there some yet to be made? what about chem5? is that playlist complete too?
thanks
Sam Crossley There are still some to be made for both Units 4 and 5... Watch this space though!
+E Rintoul I believe organic chem is missing, optical isomerism etc. Roughly when will you be able to make the videos?
Hello Mr E Rintoul,
First of all, thanks for helping me so much in AS, all I did for revision whilst on study leave was watch your videos and do past papers, and I think because of that both my unit 1 and 2 exams went really well, hoping for an A in August :)
My question is, which topics in unit 4 and 5 are not covered yet?
skwli I'm glad I was of some help! I'm yet to cover some of the acids and bases stuff in unit 4 and maybe some other bits of structure determination. Unit 5 is a little sparse still; there's electrode potential stuff to do, a load of stuff on complexes, entropy etc. The plan is to get it all done, it's just a slow process!
skwli Oh and equilibrium from Unit 4!
Do you think you will be making any new videos soon? Could do with some help on the rest of chem4? :)
Your videos are so helpful!
This was really helpful! Thanks! If you ever get chance, could you do an equilibrium one, my CHEM 4 exam is June 2016, so no rush! Haha
Adam Jones I'm definitely going to do one!
At 19:30 I’m not sure why only experiment 1 and 3 used for Y but not 2 and 3?
Thank you for the video. It was very helpful. You are wicked! What past paper is this? The year and month? Thanks in advance
rdhanda01 Honestly I can't remember which past paper the questions are from! Sorry! I can tell you that it would more than likely be from the start of the paper, but no more than that I'm afraid!
Thank you - your videos are so good! Could you please do an Unit 4 Equilibria video? it would be so, so helpful!
+Minzy Garawi I'm going to make that today (hopefully) but it will come under the new AS spec!
This was good, i watched this too see what a2 is about and not bad. If the
rate eq = k[B]^2[C] Does the 2nd order act as a squared? Because when you calculated the value of k i see you did not take the 2 into acc but when calc the rate you did.
Alias DMG Can you link me to which part, please?
+E Rintoul I also noticed this at around @24.22 .
K. Ash Yep - you should see that there's a note that says about the mistake...?
E Rintoulhow come you skipped the explanation at 33:29 and also could you have used experiments 4 and 5 to deduce the order of reaction with respect to E
Arrhenius equation is now added to the new spec
you are an excellent teacher thank you!!!
@Eliot Rintoul what software do you use to make these videos.. seems like an effective way for me to jot down key points and definitions without having to use up so much paper and it's something I can look up at on my phone anytime and anywhere, thanks
Govarthan Rrrr he uses photoshop, or has at some point, he mentions it in one video and also some screen recorder ofc. Paint would probably do the same job.......😎
Please can you do Equilibria and Acids and Bases? These videos are really helpful and possibly the only reason I made it into A2 Chemistry :)
ShortManFilmsLtd I think I'll get Acids & Bases done soon - I need to think how I'm going to separate the various topics. Obviously there is already a video on buffers up!
wait for 33:23 wouldnt E be 2nd order because the rate *changes* and you have to square 6 to get 36 then 36x0.26=9.36
You are wrong, imgur.com/gallery/izgjHTL, read my answer carefully
I used A instead of D and B instead of C
@@JesseDNME yeah thanks my teacher showed me the exact same thing I get it now
@@gasIighter Better get it wrong now than in the exam day, also gl in your chem exam.
@@JesseDNME thank you bro you too
Thank you sir. This video was really helpful 👍
are you going to be doing more videos for unit 4 and 5 of old spec as i am stuck with some of the equilibria parts??
+Ciaran Johnson I certainly am - watch this space!
+E Rintoul You're the best! How can we donate?
Mat R You honestly don't need to! But if you do wish to (and again, you really don't have to!) there's a link on my channel info!
Very very helpful! 👌
Hi! Please could you upload more Unit 4 videos! Thank you so much, you are incredibly helpful!
+Al3108 There aren't that many Unit 4 videos to do... But the rest will be coming! And thank you for the kind words!
Really useful video! Do you have a video on the Arrhenius equation?
u literally teach better than my teacher bye
Are you going to put the A2 new spec videos up?
I was just wondering if you're going to do a video on the equilibrium constant Kp for homogeneous systems anytime soon? It would be highly appreciated!
Hi there, firstly thank you for all your videos... they have helped me and a lot of my friends so much!! secondly, will you continue making videos for the old specification??
+Balraj Pandher Thank you very much for the kind words :) and yes, I shall be making more videos for the current A2 portion of the old spec!
okay thanks, its such a relief having your videos to learn from, especially revise from as my schools chemistry teacher isn't very good
Balraj Pandher I'm sure they're alright... But, if all else fails, fire questions at me!
One word: Lifesaver
your videos are sik! but where is optical isomers???
just a quick question, when you calculate Temperature from Gibbs equation when G =0
What is the significance of this temperature??
thank you
+zannatul Zan That is the temperature that the reaction becomes feasible. I've done a video today on entropy where this is mentioned.
E Rintoul thanks sir
Can you please make videos on Bonding Unit 1 AS please? thank you
sandesh thapa It's definitely one that I'm aiming to do. I'll more than likely do the intermolecular forces first, possibly followed by general bonding at a later date.
Hi, is this in the new AQA spec 2015? or is that from the old spec?
Great video, thanks
***** No problem :)
really well explained! thanks!