CIE AS Chemistry 9701 | W16 P21 | Solved Past Paper

[@clarasanchis3346]

really helpful

[@ZNotes]

Glad it helped

[@madiharehman1378]

What about part e?
Where is its answer

[@m.usmankhan3562]

Your Audi voice is too low
hardly I can hear
Q1a doesn't make sense
It is asking for mole of HCL so why we r using concentration and volume of sodium hydroxide ?
i might sound harsh but it just sound because of texting

[@maven8470]

30 cm^3 and 0.20 mol/dm are the moles and conc of hcl

[@mahin2061]

kazi u masud

[@maazahmed9077]

How did you get 0.004 mole of HCl in part e????

[@matthewlean9367]

since the ratio of moles of naoh that reacted with hcl are the same that is why it is 0.004

[@rimyrims1106]

He said something like subtracting tho,it doesn’t make sense

[@4chels]

@@rimyrims1106 Because you had 0.01 mol of sodium hydroxide
The unreacted was 0.006 which you calculated already
So the reacted NaOH is 0.01-0.006=0.004 mol of sodium hydroxide and then from your equation the ratio with HCl is 1:1 so 0.004 mol

[@venom_7_deathstalker_77_6]

Thanks sir

[@ZNotes]

no worries!

[@chusprado89prado97]

thank youu

[@ZNotes]

Welcome 😊

[@haseebarshad2108]

real messed up writing

[@aymanyousuf9352]

illegible handwriting and voice too low :(