Insert Update Delete In Php With Ajax Jquery

[@renrevz8140]

Finally someone explain the ajax perfectly thank you so much sir

[@burkertmedinabob4705]

Bro u have made me a good developer... Thanks for this, u really knows how to teach... Keep it up bro

[@hrf4711]

superb its like java we use classes like here you used functions.so clean thank you

[@polycarpokot8310]

Thanks for the great work.
When using myjs.js file; creating the view_record function, on the data=$.parseJSON(data). Am receiving this message error.
Uncaught snytaxError:JSON.parse: unexpected character at line 1column 1 of the JSON data. Could you and anyone else here please help me out?!

[@mcmyles-j5p]

good am following this

[@riadhcoding]

you have one problem in your code brother your code for delete it's just delete the first item only try to click last item or before you can't remove it

[@lucasjohn3014]

Its good and simple to understand let me try to practice.

[@yadvendersharma1576]

This is really great and useful content

[@TechBowl]

If someone is looking for PHP PDO CRUD using Ajax ruclips.net/video/LBxSYZ6Z4ng/видео.html

[@limffilm1892]

Thank you very much its really helpfull

[@mcmyles-j5p]

my function fetches only one character from each record in the database kindly advice what could be the problem

[@ogundelebabatunde9190]

very detailed explanation, thanks

[@MultiMaN95]

so clean and very easy to understand, thank you

[@eliaspbareia]

Very good and complete. The results were not paged.

[@seleman-MW]

how retrieve the specific id of the user for example when i click on user id 1 and display the only one records of user 1??

[@SuperPooja45]

don't use the while loop we you fetching the data from the table stored it in the single variable.

[@PardeepKumar-im6ij]

Sir ajax ke code se bnana ek vedio please 🙏

[@bogdanos0]

great job, thx!

[@moomenaldahdouh]

Execlant, Thanks :)

[@phamngocthang6649]

nice! bro

[@adilsonsf]

Thank you so much! Awsome tutorial👍👍👍

[@oussamaelharmali2294]

Hi, you don't have a syntax error at data=$.parseJSON(data) ???

[@j4vlon]

good job

[@Neverm0re_]

@telugu tolly63 Hey! Have you solved your problem? I'm not getting any output as well

[@netkongen]

Can't find the code via the link ?

[@liemthegreat]

the script not found at the website :(

[@divyaranisutar4116]

hello sir how to upload image along with this

[@mohammedhamid5]

it says data is not defined when I click on the Edit button! can someone help me???????

[@davinunesvit]

Thanks bro! Worked for me!

[@oussamaelharmali2294]

Hi bro, Do you found the solution of that ?

[@davinunesvit]

@@oussamaelharmali2294 post your code here

[@oussamaelharmali2294]

@@davinunesvit data = $.parseJSON(data); a error shows : Unexpected token < in JSON at position 0 I search but with no result

[@davinunesvit]

@@oussamaelharmali2294 try to console.log(data) to check your JSON structure

[@davinunesvit]

@@oussamaelharmali2294 show me your PHP code and your js

[@eduardkoshkelyan8670]

Pls help author
syntax error ...console log -- ' Uncaught SyntaxError: Unexpected token < in JSON at position 4
at Function.parse [as parseJSON] ()
at Object.success (myjs.js:43) '

[@aasharazeem5735]

Hello, You need to remove this line data = $.parseJSON() under your view record function in myjs.js file and write outside of success dataType: 'JSON', JQuery will do the same thing for you it worked for me

[@johnlark00]

in functions.php
function get_record()
$User_data = ""; should be like this --> $User_data = array();

[@jaironaranjo3654]

Thank you my friend you are the best!

[@aiwaheed3902]

this help for the editing part, else it will show initials

[@jaironaranjo3654]

please on 1:04:48 timestamp $User_data =" " ; DOES NOT WORK it shoulb be -> $User_data = array();

[@arjunm.r8641]

Brother I got a syntax error at data=$.parseJSON(data);
Can u please help me to avoid that error.Please.

[@oussamaelharmali2294]

What about now brother ?

[@ibtissembendouhou3274]

Same problm today , did u fix it?

[@oussamaelharmali2294]

@@ibtissembendouhou3274 facebook.com/ElharmaliOussama/ contact me I will give a folders contains all about webDev (Udemy) don't follow like those tutorials

[@aasharazeem5735]

@@ibtissembendouhou3274 Hello, You need to remove this line data = $.parseJSON() under your viewrecord funtion in myjs.js file and write outside of success dataType: 'json', JQuery will do same thing for you it worked for me

[@md.salehinkabir5461]

syntax error ...console log -- ' Uncaught SyntaxError: Unexpected token < in JSON at position 4
at Function.parse [as parseJSON] ()
at Object.success (myjs.js:43) ' ....plz fix it..

[@oussamaelharmali2294]

Hi bro, Do you found the solution of that ?

[@WPANDSEOTUTORIALS]

@@oussamaelharmali2294 Do you want to get your problem solved ?

[@oussamaelharmali2294]

@@WPANDSEOTUTORIALS yes of course

[@aasharazeem5735]

Hello, You need to remove this line data = $.parseJSON() under your viewrecord funtion in myjs.js file and write outside of success dataType: 'json', JQuery will do same thing for you it worked for me

[@polycarpokot8310]

@@aasharazeem5735 hello mine has jam

[@kojakeugenio1064]

For those who are having data=$.parseJSON(data) error replace that with this
data = JSON.parse(data);

[@antoniofuller2331]

True

[@amilamadushan6840]

can you send me source code of this code ?

[@terlumunjoseph6779]

your code view is looking too small i cant see what youre typing

[@OnlineITtuts]

Please increase video resolution, then you will able to see each code..

[@polycarpokot8310]

@@OnlineITtuts hello please help

[@santhoshkumar-sf4bc]

Sir, could you provide source code...?

[@adilsonsf]

You can learn following his steps

[@angryrussianhd2470]

@@adilsonsf Go fuck yourself, I can learn by playing with the code directly.

[@WPANDSEOTUTORIALS]

@@angryrussianhd2470 :P You people are really fuckin :P

[@nickobalute6656]

Help echo json_encode(['status' => 'success','html'=>$value]); syntax error, unexpected '[', expecting ')'

[@amhatesfaye315]

Thanks for the great work.
When using myjs.js file; creating the view_record function, on the data=$.parseJSON(data). Am receiving this message error.
Uncaught snytaxError:JSON.parse: unexpected character at line 1column 1 of the JSON data. Could you and anyone else here please help me out?!

[@bogdanos0]

great job, thx!