Permutations & Combinations. Ex. 5 (B) Q. 1 to 7. CA foundation. Maths by Pradeep Soni

[@smarthbajaj378]

Sir, Q-6 me pehle apne bola ki permutation lagega phir apne combination laga diya.

[@dileepupkekaushambise7198]

Sir app mahan hai

[@khyatiparekh6323]

Easy teaching sir..🥰🥰😍🥳

[@TechnicalMathsbyPradeepsoni]

Thanks

[@mehulpandya5141]

Sir question 3 ka dosra formulae batao plzzz

[@Randomfact900]

Sir question ko kese pehchanege
p bol rah a h ya c

[@solankidipika6037]

Sir, questions 4 ka dosra method batao na please

[@yuktaagarwal9253]

Yes sir question 4th ko vapas second mathod se bta do please😫🙏🙏💓 sir ye samej nhi aaya

[@shivachaitanyakusuma2350]

Easily understood hora hai sir thank you

[@TechnicalMathsbyPradeepsoni]

Welcome

[@mr.b_kool7099]

Thank you sir

[@TechnicalMathsbyPradeepsoni]

Welcome

[@10.chauhanaarchi63]

Sir thank you so much

[@ankitkumar-ew6uq]

Please again explain question no. 4

[@mamtamm1884]

Thanks a lot sir 🙏

[@TechnicalMathsbyPradeepsoni]

Welcome

[@NehaSharma-pl6ps]

Sir how we ll get to know ki p apply krna h ya c

[@devikasharma8869]

Sir please upload equations ca foundation within this month! A humble request sir. Because your teaching helps a lottt.

[@TechnicalMathsbyPradeepsoni]

Ok

[@sudharsans1487]

Sir ur teaching style is super

[@lokendrasinghchouhan156]

Bhai Mtlb kese?😐

[@siddhidesai7959]

Sir please question no 4 dusri method se bataiye na

[@umeshbhavsar6663]

Sir, very good efforts

[@TechnicalMathsbyPradeepsoni]

Thanks

[@nexevolsegaming]

@@TechnicalMathsbyPradeepsoni love you so much sir ❤️ ❤️ 💯 💯 😍 😍 😍 😍 😍 😍 😍 😍 😍 😍 😍

[@TechnicalMathsbyPradeepsoni]

Welcome

[@sharmisthamukherjee3650]

Thank u so much sir...❤️......

[@TechnicalMathsbyPradeepsoni]

Welcome

[@a.sfoundation8553]

Hii

[@sharmisthamukherjee3650]

@@a.sfoundation8553 hlw

[@a.sfoundation8553]

Or kesi ho

[@rahulkumargupta9173]

Sir I am your new subscriber..

[@TechnicalMathsbyPradeepsoni]

Welcome

[@ffbrothersgaming702]

Sir question 4 ko kisi different methods se samjhiye please

[@surajjayaswar8686]

sir kya apane permutation and combination ke concept ki video dali hain kya

[@TechnicalMathsbyPradeepsoni]

Concept ki alag se video nhi dali. Concept question k saath saath clear kiye h.

[@TechnicalMathsbyPradeepsoni]

Kuch videos me kuch concept clear h

[@TechnicalMathsbyPradeepsoni]

Or Additional question bank complete h with concept

[@surajjayaswar8686]

sir kya aap 5 a all exercise dal sakte hain kya please

[@surajjayaswar8686]

esi chapter main thoda help kar dete to achha ho jata

[@shyamsunder1292]

Sir Q 4smjh nhi aaya.konsa video mein dusra method daala aapne?

[@lmaobra]

Sir 4th question karne ka koi aur method ha kya?

[@siddharthmishra5768]

Sir I'm Siddharth from Delhi..first of all sir thanks a lot...u r really great teacher u r god of maths...sir can I get any what's app no to query the questions which I have doubt

[@TechnicalMathsbyPradeepsoni]

Please your number

[@TechnicalMathsbyPradeepsoni]

Switch off h phone

[@siddharthmishra5768]

@@TechnicalMathsbyPradeepsoni yess sir ho ga uss time but ab nai hai and maine aapko call bhi ki thi

[@siddharthmishra5768]

Sir plz no.

[@DEEPAKKUMAR-pf3bj]

Sir him question no.6 mai direct permutation ka formula laga kar ku nahi bana sakte hai.i.e n-1Pr-1=9P3.

[@mustafadahod9469]

God bless u sir ❤️

[@TechnicalMathsbyPradeepsoni]

Thanks, welcome

[@Hippyhoppy]

9:37 why did we took combinatios instead of permutations sir?

[@yonder07]

I was wondering the same 😂

[@adi8689]

@@yonder07 well ... suppose you need to find 5p3
you can also write "5p3" as "5C3 X 3!"
as ... 5C3 X 3! = 5!/(3! X 2!) X 3! = 3! will cancel out so = 5!/2! which is equal to 5P3

[@moosakulamullaparambath6677]

Super class

[@TechnicalMathsbyPradeepsoni]

Thanks

[@arbazshaikh7655]

Thanks sir

[@arbazshaikh7655]

Next video

[@TechnicalMathsbyPradeepsoni]

Welcome

[@princegoyal9935]

Sir necklace mai 1/2 kyo lga

[@TechnicalMathsbyPradeepsoni]

Because usme Right Left nhi hota

[@Shreya_chaurasiya_here]

Sir can u plz make one video dedicated to one whole excercise.. Like 5(b) all the question in one video.. It saves our time sir

[@sureshbansal7572]

Thanks sir.

[@vartikakothari5453]

💯

[@kanikaagg8374]

Sir question 4 samajh nahi aaya

[@rakeshsharma5978]

i m unable to understand questions no 6 and 7

[@TechnicalMathsbyPradeepsoni]

Ok, I will try again

[@sudhirmandal143]

sir 4th question samaj nahi Aaya please bta do Aapna apni video mai kha hai ki Aap bta doga to please apni commitment puri karia
😀 😀 😀 😀 😀

[@qasimshaikh7152]

Sir 2 ladies jab 2 jagah me bhatege toh 2p2 aayega na

[@TechnicalMathsbyPradeepsoni]

3 ladies me se 2 ko bithana h. Isliye 3p2 aayega

[@qasimshaikh7152]

@@TechnicalMathsbyPradeepsoni sir lekin 2 ko bitha chuke aur 3 ladies ka toh uska alag formula aayega na

[@qasimshaikh7152]

Sir plz 1 bar easy way me samja dijye

[@priyankahemnani]

Sir B and C exercise kab daaloge? Pls sir zaldi dalo.. June m exam h

[@TechnicalMathsbyPradeepsoni]

Ok

[@priyankahemnani]

Humble request sir .. Pls permutation combination ka weightage bhaut zyada hai

[@TechnicalMathsbyPradeepsoni]

Ok

[@pankajkumarkhatuwala8859]

Sir I didn't understood quest 6 n 7

[@TechnicalMathsbyPradeepsoni]

Aaj 8 may 2020 ko 6 pm online class hai

[@Ankitkumar73240]

Explain the situation 4

[@TechnicalMathsbyPradeepsoni]

Ok

[@shubhamchaudhary4092]

Sir please repeat questions no 4

[@TechnicalMathsbyPradeepsoni]

Ok

[@qasimshaikh7152]

Q.4)me 2 ladies jab 1 saat bheti toh 2p2 aayega na....3p2 q likh diye aapne.
Tesri ladies ka formula toh alag likhe hi na

[@harshadmeheta3211]

Total3 ladies to 2 ladies sit together so 3p2

[@mohitgaur9513]

Questions 6 or 7 me permutations bolke combination ka formula q apply kar rhe ho

[@Yashkadam-ul3ph]

Ha na yaar samj nhi aaraha

[@cricketandfun7803]

Bhai iska formula hai
n-1Pr-1 ✖ r

[@cricketandfun7803]

Aur 7 me formula lagega
n-1Pr

[@trushaparmar148]

Sir 3rd me 1/2 kyu aayega???

[@TechnicalMathsbyPradeepsoni]

Necklace me right or left nhi hota h. Isliye formule me 1/2 aata h.

[@ritikjha3922]

Sir Q.4 kuchh samajh mai nhi Aaya sir

[@TechnicalMathsbyPradeepsoni]

Ok

[@Triptrekker_05]

Sir Question 3 dusare formulame batavo

[@TechnicalMathsbyPradeepsoni]

Ok

[@Raksha_G.]

Is question ke liye yahi formula use hota h ab dusra Kahan se btayege sir

[@ankitkumar-ew6uq]

Hello sir

[@kajalthakur9161]

Sir questions no.4 smj na aaya

[@Yashkadam-ul3ph]

Same😶

[@jaiminraval1788]

Nice

[@TechnicalMathsbyPradeepsoni]

Welcome

[@anilankit1493]

sir plese4 no question

[@akhileshpandey5345]

Sir 4 th questions repaet one more time

[@TechnicalMathsbyPradeepsoni]

ok

[@Surajmehto641]

Sr 4 questions samajh nahi aaya 😟😐

[@sunnypoddar2860]

Sir question no.4 proper samaj nahi aaya

[@amitvermamonuverma8259]

7 smjh ni aaya sir

[@TechnicalMathsbyPradeepsoni]

Why

[@amitvermamonuverma8259]

@@TechnicalMathsbyPradeepsoni sir, maine baad mein try kiya smjh aa gya thankyou sir

[@aanchal8112]

Q4 th book m ans b de rkha h that is 27 🙄

[@MrAjitPrasad]

3 no. Ni smj me aaya sir

[@nitinsomani3601]

Q6 mein kuch bhi hogaya lag raha hein sie 🤣😭

[@TechnicalMathsbyPradeepsoni]

Kya samagh nhi aaya

[@qasimshaikh7152]

Bhai Q.6) me 1 trick hai sun .......10 cricketers hai jin me se coach ko 4 select karna hai par usme se 1 cricketer aisa player hai jo best hai toh woh already selected hai toh 1 player hogaya always occurs ka toh 10 me se 1 selected 9 bache toh teko 9 me se 3 select karna hai toh 9c3 agaya × 4! Answer agaya

[@blank69690]

@@qasimshaikh7152 bhai nice example

[@rakeshsharma5978]

plzz reply

[@CA.Faizan_Yafai]

Op sir 🔥🔥

[@sunilkandoi7474]

4 qus. Smj nahi aaya

[@vaidikgandhi5716]

It's not concept base

[@PoojaGupta-zg5jm]

Thank you sir

[@Ankitkumar73240]

Thanks sir

[@Anshul_Thakur_]

Sir 4th question samj ni aya

[@Strangercouple_]

Sir 4 question samjh nahi aya

[@rohitbihani05]

Sir 4 no. Ques samj ni aaya

[@rohitrv7363]

Sir question 4 ni aaya