Tks, this is pretty clear and concise, i would really like to watch chapter 2 and 3 mentioned at 18:20 that continue this discussion can u pls provide those video links , u have 137 videos and im not even which ones im looking for, tks eh.
Note that z is measured upward, i.e. Z2>Z3. You need that term to be positive, since you are moving downward into zone of higher pressure. So it must be Z2-Z3 to get a positive number. You might find it easier to work in terms of DeltaZ, where DeltaZ is always a positive value.
When you jump across from point 1, you remain in the same (pink) fluid at both locations. Think of it this way: If you when down from point 1 instead (into the u-bend of the manometer) the pressure would increase. When you came back up to the same horizontal location in the inclined tube, the pressure would decrease by exactly the same amount. So, you can avoid going down and up, and simply jump across.
I've taken the vertical component of the inclined length, l_2. From basic trigonometry, l_2*sin(theta) is the change in height. So the change in pressure is gamma_2*l_2*sin(theta) is the change in pressure. I hope that helps.
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All the videos for this introductory Fluid Mechanics course are available at: www.drdavidnaylor.net/
Fluid Statics , found it perfect ! thanks again
I love your videos Dr Naylor. This is really helping me understand the content in my course, thank you!!
Glad they are helpful. Thanks for the kind words.
Tks, this is pretty clear and concise, i would really like to watch chapter 2 and 3 mentioned at 18:20 that continue this discussion can u pls provide those video links , u have 137 videos and im not even which ones im looking for, tks eh.
Links to a the course RUclips videos are available (in order) at my website: www.drdavidnaylor.net
Thanks for this lecture Dr Neylor
i have a question though at 11:42 is the height difference not supposed to be (Z3 - Z2) or it doesnt matter
Note that z is measured upward, i.e. Z2>Z3. You need that term to be positive, since you are moving downward into zone of higher pressure. So it must be Z2-Z3 to get a positive number. You might find it easier to work in terms of DeltaZ, where DeltaZ is always a positive value.
Sir at 15:15 you jumped across. How did you do that considering they are 2 different fluids?
When you jump across from point 1, you remain in the same (pink) fluid at both locations. Think of it this way: If you when down from point 1 instead (into the u-bend of the manometer) the pressure would increase. When you came back up to the same horizontal location in the inclined tube, the pressure would decrease by exactly the same amount. So, you can avoid going down and up, and simply jump across.
I was confused how do u get r^2L^2 sino
I've taken the vertical component of the inclined length, l_2. From basic trigonometry, l_2*sin(theta) is the change in height. So the change in pressure is gamma_2*l_2*sin(theta) is the change in pressure. I hope that helps.
Hello Pr have you a book for a fluid mechanics.
In my course we use the book Fluid Mechanics by Frank White. Is that what you are asking?
@@FluidMatters yes, thank you Pr.