Redox Titration Calculations with Potassium Manganate (VII) | A-Level Chemistry

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  • Опубликовано: 3 ноя 2024

Комментарии • 31

  • @LiA-tt6rp
    @LiA-tt6rp 4 года назад +3

    YOU ARE OUR SAVIOUR!! so grateful that you make videos like that! They are so informative and easy to understand. ❤️

  • @jeancena2002
    @jeancena2002 5 лет назад +4

    I had my practical yesterday and I'm so glad I came across your channel just before it. Thank-you so much for helping us students all over the globe(I'm from Pakistan). Your videos are really helpful and I can't thank you enough for making life easier for us all. *thumbs up*

  • @zas3362
    @zas3362 4 года назад +1

    great video, clears concept
    helped me out for tomorrows practical

  • @lallib.3968
    @lallib.3968 5 лет назад +3

    Thanks for saving my a level! Can you do videos on buffer calculations please?

  • @Perpetualugochi
    @Perpetualugochi 12 дней назад

    Thank you so much but i did not understand the calculation and the equation balance

  • @deggs6960
    @deggs6960 5 лет назад +1

    This is excellent! Thank you

  • @laurennewman6301
    @laurennewman6301 5 лет назад

    Thank you so much! This was such a helpful video!

  • @STICKY_
    @STICKY_ 3 года назад

    Thank you so much!! :)

  • @zarrintasnim4687
    @zarrintasnim4687 5 лет назад

    Also can you do some back titrations ?

  • @zarrintasnim4687
    @zarrintasnim4687 5 лет назад +1

    Hey can you add some practise questions

  • @hamzanyambi9367
    @hamzanyambi9367 4 года назад

    Well explained and nice Voice

  • @nhasan710
    @nhasan710 4 года назад +1

    i dont understand whats actually going on in the titration, why doesnt the excess hydrogen ions interfere with our experiment?

    • @connorgibson6014
      @connorgibson6014 4 года назад

      Hydrogen ions from the acid are the catalyst

  • @Nataliakennerley
    @Nataliakennerley 3 года назад +2

    7.12 why did you x40???

  • @wardahmoosun9655
    @wardahmoosun9655 5 лет назад +1

    lol I'm doing my GCSEs and ngl I'm so grateful I haven't hit a levels

    • @wardahmoosun9655
      @wardahmoosun9655 5 лет назад

      Omggg I love you primrose xxx thank you

    • @arunahardath4896
      @arunahardath4896 4 года назад

      Dude, GCSEs are much harder than A levels (so I've heard)

    • @arunahardath4896
      @arunahardath4896 4 года назад

      I'm in A levels and it is already hard. Farless for GCSEs

  • @rocknroll5569
    @rocknroll5569 5 лет назад +1

    hard to understand. where did she get 40?

    • @Primrose_Kitten
      @Primrose_Kitten  5 лет назад +1

      Multiply by 10 to go from 25cm^3 to 250cm^3, and then by 4 to go from 250cm^3 to 1000cm^3

    • @teknitsma9553
      @teknitsma9553 5 лет назад +2

      But you had already multiplied by 10 in the previous step?

    • @dnxkkal4306
      @dnxkkal4306 4 года назад

      @@teknitsma9553 I think it is because the question asks for grams per dm^3 so you had to convert it (1000cm in a dm)

  • @zarrintasnim4687
    @zarrintasnim4687 5 лет назад +6

    I don’t get why you multiplied by 40

    • @Primrose_Kitten
      @Primrose_Kitten  5 лет назад +1

      x10 to get from 25cm^3 to 250cm^3 then x4 to get from 250cm^3 to 1000cm^3

    • @dnxkkal4306
      @dnxkkal4306 4 года назад

      @@Primrose_Kitten why does it have to be converted to 1000cm^3 since it only states 250 in the question?

    • @koko-ph8dr
      @koko-ph8dr 4 года назад +1

      dnxk kal it’s because the answer needs to be in terms of grams per dm3, and 1000cm3 is 1dm3. So she had the concentration in 25cm3, she multiplied by 4 to get the conc in 250cm3, then she multiplied by 4 to get 1000cm3 which is 1dm3. Hope this helps (:

    • @koko-ph8dr
      @koko-ph8dr 4 года назад

      dnxk kal it’s because the question asked for it in g per dm3 so you would need to convert. If it doesn’t ask for it then you don’t need to x40 !

    • @abhiraja3578
      @abhiraja3578 4 года назад +1

      @@Primrose_Kitten
      You’ve already multiplied by 10 to get moles in 250cm^3