So the last thing that you mentioned was longer the cable length the more capacitance... I cant discern if this is good bad or neutral to have longer length...def certain that that particular statement was one of the most obscure and insightful nuggets of guitar wisdom I've come across in 30+ hours of researching videos webpages and the minds of techs and luthiers in my obsessive attempt to gain an understanding of the electronic engineering aspect/components of electric guitars and how they affect the output tonality variance....thanks again for taking the time to make this and your other videos
The Resonance Frequency 2.3H and Capacitance .0040uf = 1659.3Khz Resonance Frequency of the pickupThe Volume pot is 250K and the tone is 250K = 150K The Tone rolled down uses a .15uf tone cap If the Resonance frequency is 1659.3Khz how do I "add in" 150K and the .15uf to know the Resonance frequency? what formula do I use
"The Resonance Frequency 2.3H and Capacitance .0040uf = 1659.3Khz Resonance Frequency of the pickupThe Volume pot is 250K and the tone is 250K = 150K The Tone rolled down uses a .15uf tone cap If the Resonance frequency is 1659.3Khz how do I "add in" 150K and the .15uf to know the Resonance frequency? what formula do I use" Again you have to know how to calculate the total resistance and capacitance in a circuit. I've explained adding resistors in parallel (1/R1+1/R2=1/R3; R3 being the total resistance). When capacitors are in parallel you can just add them up. When the are in series you get 1/C1+1/C2=1/C3, C3 being the total capacitance. And one more time: 1/250+1/250=1/125 (not 1/150!).
But what formula did you use to put the "cables capacitance added" to the resonance frequency? Volume pot is 250K ohms and the Tone pot is 250K are wired in parallel = 150K ohm When measuring a single Coil pickup measures the DC resistance is 6K, Inductance is 2.3H, Capacitance is .0040uf 2pie = 3.14 3.14 X F X L 2.3H = Resonance Frequency 3.14 X F X C .0040uf = Resonance Frequency F is the frequency which frequency do you pick to put in the formula?
"But what formula did you use to put the "cables capacitance added" to the resonance frequency? Volume pot is 250K ohms and the Tone pot is 250K are wired in parallel = 150K ohm When measuring a single Coil pickup measures the DC resistance is 6K, Inductance is 2.3H, Capacitance is .0040uf 2pie = 3.14 3.14 X F X L 2.3H = Resonance Frequency 3.14 X F X C .0040uf = Resonance Frequency F is the frequency which frequency do you pick to put in the formula?" Any extra parallel capacitance can be added to the capacitance that is already in the circuit. I'm sorry but I can't really read your calculations (but two parallel resistors of 250 KOhm gives you 125 KOhm, not 150).
Yes true I'm sorry its 125K for the total of the volume pot and tone pot. But how do you "add" the parallel 125K ohms to the Resonance frequency?Ok I will add the cable capacitance, the tone pot capacitance value and the pickup capacitance all together to add in the resonance frequency
@@waynegram8907 "Yes true I'm sorry its 125K for the total of the volume pot and tone pot. But how do you "add" the parallel 125K ohms to the Resonance frequency?Ok I will add the cable capacitance, the tone pot capacitance value and the pickup capacitance all together to add in the resonance frequency " If the resistance of the pickup is 6K: 1/6+1/125=1/Rtotal Give them the same denominator: 125/750+6/750=131/750 Divide enumerator and denominator by 131: 131/750=1/5,725 The resulting resistance in the circuit is 5,725 KOhm.
@@waynegram8907 It's not 750 KOhm, it's simple calculation with fractions. You want to add two fractions, 1/6 and 1/125, and to do that they must have the same denominator. So you multiply the denominators: 6x125=750. To get to the same fractions the enumerators must also be multiplied: 1x6=6 and 1x125=125. 1/6=125/750 and 1/125=6/750. Now you can add them: 6+125=131 devided by 750, or 131/750. Because you need 1/Rtotal (and not 131/Rtotal) you must then devide enumerator and denominator by 131: 131/750 = 1/5,725 (rounded off to three decimals) The 6 and the 125 were KOhm so it is also 5,725 KOhm. When I was young this was taught in primary school.
The science of arguably the most accessible style of instrument in the world today just keeps getting deeper and deeper
So the last thing that you mentioned was longer the cable length the more capacitance... I cant discern if this is good bad or neutral to have longer length...def certain that that particular statement was one of the most obscure and insightful nuggets of guitar wisdom I've come across in 30+ hours of researching videos webpages and the minds of techs and luthiers in my obsessive attempt to gain an understanding of the electronic engineering aspect/components of electric guitars and how they affect the output tonality variance....thanks again for taking the time to make this and your other videos
Thanks for this series of videos, I'm sure it's helped a lot of people.
Excellent. Very well explained.
Thanks Marc - great explanation...sounds like you live in a beautiful place:)
Thank you, very informative, great work.
Excellent !!!!!
The Resonance Frequency 2.3H and Capacitance .0040uf = 1659.3Khz Resonance Frequency of the pickupThe Volume pot is 250K and the tone is 250K = 150K The Tone rolled down uses a .15uf tone cap If the Resonance frequency is 1659.3Khz how do I "add in" 150K and the .15uf to know the Resonance frequency? what formula do I use
"The Resonance Frequency 2.3H and Capacitance .0040uf = 1659.3Khz Resonance Frequency of the pickupThe Volume pot is 250K and the tone is 250K = 150K The Tone rolled down uses a .15uf tone cap If the Resonance frequency is 1659.3Khz how do I "add in" 150K and the .15uf to know the Resonance frequency? what formula do I use"
Again you have to know how to calculate the total resistance and capacitance in a circuit. I've explained adding resistors in parallel (1/R1+1/R2=1/R3; R3 being the total resistance).
When capacitors are in parallel you can just add them up. When the are in series you get 1/C1+1/C2=1/C3, C3 being the total capacitance.
And one more time: 1/250+1/250=1/125 (not 1/150!).
But what formula did you use to put the "cables capacitance added" to the resonance frequency?
Volume pot is 250K ohms and the Tone pot is 250K are wired in parallel = 150K ohm When measuring a single Coil pickup measures the DC resistance is 6K, Inductance is 2.3H, Capacitance is .0040uf 2pie = 3.14 3.14 X F X L 2.3H = Resonance Frequency 3.14 X F X C .0040uf = Resonance Frequency F is the frequency which frequency do you pick to put in the formula?
"But what formula did you use to put the "cables capacitance added" to the resonance frequency?
Volume pot is 250K ohms and the Tone pot is 250K are wired in parallel = 150K ohm When measuring a single Coil pickup measures the DC resistance is 6K, Inductance is 2.3H, Capacitance is .0040uf 2pie = 3.14 3.14 X F X L 2.3H = Resonance Frequency 3.14 X F X C .0040uf = Resonance Frequency F is the frequency which frequency do you pick to put in the formula?"
Any extra parallel capacitance can be added to the capacitance that is already in the circuit.
I'm sorry but I can't really read your calculations (but two parallel resistors of 250 KOhm gives you 125 KOhm, not 150).
Yes true I'm sorry its 125K for the total of the volume pot and tone pot. But how do you "add" the parallel 125K ohms to the Resonance frequency?Ok I will add the cable capacitance, the tone pot capacitance value and the pickup capacitance all together to add in the resonance frequency
@@waynegram8907 "Yes true I'm sorry its 125K for the total of the volume pot and tone pot. But how do you "add" the parallel 125K ohms to the Resonance frequency?Ok I will add the cable capacitance, the tone pot capacitance value and the pickup capacitance all together to add in the resonance frequency
"
If the resistance of the pickup is 6K:
1/6+1/125=1/Rtotal
Give them the same denominator:
125/750+6/750=131/750
Divide enumerator and denominator by 131:
131/750=1/5,725
The resulting resistance in the circuit is 5,725 KOhm.
Why are you using 750? The total resistance should 131k, where are you getting the 750ohms?
@@waynegram8907 It's not 750 KOhm, it's simple calculation with fractions.
You want to add two fractions, 1/6 and 1/125, and to do that they must have the same denominator. So you multiply the denominators: 6x125=750. To get to the same fractions the enumerators must also be multiplied: 1x6=6 and 1x125=125.
1/6=125/750 and 1/125=6/750. Now you can add them: 6+125=131 devided by 750, or 131/750.
Because you need 1/Rtotal (and not 131/Rtotal) you must then devide enumerator and denominator by 131: 131/750 = 1/5,725 (rounded off to three decimals)
The 6 and the 125 were KOhm so it is also 5,725 KOhm.
When I was young this was taught in primary school.
Walken esque