You are the best. My lecturer literally watched your videos, came and tried to teach us and still failed to make sense. After watching these i understand everything. Be blessed sir.
Thank you My lecturer in university used virtual power instead of virtual work. I mean he multiplies load to velocity. And for internal power, he multiplies moment to rate of rotation. I dont know which one is better but this video was more understandable.
what an awesome set of videos. That was a pleasure to watch. Brilliant! Just one question, How would I treat a UDL, convert this to a point load and solve the same way?
in case of udl, when we calculate external work done as: load*deflection ; the value of deflection will be in terms of area.. that means u need to calculate area under the udl. triangles are formed in plastic analysis .. so similarly in case of udl we use 1/2 b*h where b is the entire span of udl and h is the deflection acting at the mid section of udl when we get the value of area that becomes our deflection .. hope it helps u mate
Hi Dr, if it is required the minimum plastic moment is that mean that we need to get the plastic moment from the beam mechanism then from sway and then from the combined action and take the lowest one ?
I just took the moment about C = 0 this will result to the following equation Mp + Mp -Xd*4 = 0 then xd = 2Mp/4 = 0.5 Mp. It is already explained and the equation is given I the video. I hope that you understand it.
في المثال الاخير الانهيار كان فقط في الكمرة العلويه. لذلك يمكنك رسم العزم في الكمرة فقط و طرف العمود العلوي. في الطرف السفلي من العمود يوجد عزم بنصف قيمة العزم عند الطرف العلوي.
The moment direction is always opposite to the movement of the element. For Ex, if a column is rotating clockwise, the moment at it ends will be count clock wise. This is also applicable for beams. The tension is always at the tail side of the moment and the compression is at the arrow side of the moment.
Nightmare. Used to have to study for this shit. Now I’m done with studying and became a project manager and never have to deal with these technical shit again.
You are the best. My lecturer literally watched your videos, came and tried to teach us and still failed to make sense. After watching these i understand everything. Be blessed sir.
I have never seen such a great teacher....................keep it up.......Thank you very very much
It's my pleasure
@@MrElgamal77 kindly also upload Rehman frame analysis method
Thank you for these lectures. Great work.
Great explanations throughout. Thank you!
Thank you very much Professor. I am looking forward more of your lecture about Plastic Analysis. Your lectures are really helpful and clear.
Hello
You are a great professor. Thank you for your videos, they have been of great help to me.
Happy to help. You are welcome.
Thank you
My lecturer in university used virtual power instead of virtual work. I mean he multiplies load to velocity. And for internal power, he multiplies moment to rate of rotation. I dont know which one is better but this video was more understandable.
Thank you for the great enlightenment, on this particular analysis of structures.
شكرا لك ولكل جهودك دكتور ...م محمد العراقي
Thank you very much for your lesson sir, that's such a well explained topic!!
Excellent work!
what an awesome set of videos. That was a pleasure to watch. Brilliant! Just one question, How would I treat a UDL, convert this to a point load and solve the same way?
in case of udl, when we calculate external work done as: load*deflection ; the value of deflection will be in terms of area.. that means u need to calculate area under the udl. triangles are formed in plastic analysis .. so similarly in case of udl we use 1/2 b*h where b is the entire span of udl and h is the deflection acting at the mid section of udl when we get the value of area that becomes our deflection .. hope it helps u mate
15:27 if you're taking moments at C why did you include the C mp? shouldnt the equation just be Mp- Xd*4 = 0 since the MP at C will be eliminated?
Thanks so much. Very explanatory
Thank you, professor. Great apresentation.
You are welcome.
im so greatful for this video
Thanks.
How are the upper bound lower bound and uniqueness theorem used?
When looking at Member CD how come both moments at meber C didnt cancel eachother out
Hi Dr,
if it is required the minimum plastic moment
is that mean that we need to get the plastic moment from the beam mechanism then from sway and then from the combined action and take the lowest one ?
Appreciated hard work
Thank you!!
Hey which country u belongs? I m from india
Very good and understandable stuff thank you
If you don't mind would you add one with distributed loads.
if two frame has the same minimum value then both will collapse ?
doesnt the fact that the horizotal and vertical loads being difffernt cause the angle theta to be different for the beam and column
Thanks for your efforts
do you have videos about yield line method ?
Please can you go over a load horizontally in the middle of the column with a vertical load, where the horizontal beam has 2Mp?
Can you do video about designing slabs and plates using yield line method?
I may do that in the future.
Good lecturing Sir, thank you. Do you perhaps have the BMD available for the last 2 examples?
Great explanation. Thank you.
Thanks. Please share with you coleagues.
@@MrElgamal77 Ok!
excellent videos! are you able to do the same analysis but for two storey frames?
pode pôr legenda no vídeo, para eu poder traduzir?
Well explained.
Thanks. You're welcome.
@ 14:51 I dont understand how you got 0.5 to find 12.5
I just took the moment about C = 0 this will result to the following equation Mp + Mp -Xd*4 = 0 then xd = 2Mp/4 = 0.5 Mp.
It is already explained and the equation is given I the video. I hope that you understand it.
If MP Is replaced by EI what will we do
if there is no horizontal load then is there no sway mechanism
That is correct.
Greatful
Many thanks
كيف يتم حساب رسمه العزم لاخر مثال ؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟؟
في المثال الاخير الانهيار كان فقط في الكمرة العلويه. لذلك يمكنك رسم العزم في الكمرة فقط و طرف العمود العلوي. في الطرف السفلي من العمود يوجد عزم بنصف قيمة العزم عند الطرف العلوي.
Jasakalaah dr your lectures are help full for civil engineering students will you uplaod other lectures
I will do IN SHAA ALLAH
In example 1 how do we know which side is compression and which side is tension??
The moment direction is always opposite to the movement of the element. For Ex, if a column is rotating clockwise, the moment at it ends will be count clock wise. This is also applicable for beams. The tension is always at the tail side of the moment and the compression is at the arrow side of the moment.
Kindly sir also upload the Rahmen frame analysis method
Sorry. I am not familiar with this method.
Dr.S.
Nightmare. Used to have to study for this shit. Now I’m done with studying and became a project manager and never have to deal with these technical shit again.
Good for you. You are lucky.
يا دكتور اذا اغلب متابعينك عرب لماذا تتكلم انجليزي
لأن التدريس عندنا بالجامعة لازم بالانجليزي. كمان يوجد كتير متابعين ما يعرفوا عربي. هل رأيك اغير للعربي؟