Actually, You have done the mistake in fourth statement... Because you have divided (x+1)-(x-1)/(x-1) But you are forgetting that according to the rules of mathematics... You can't divide any number by zero... Hope you will understand...😎😎😎
4:00 When you raise to the second power both sides of the equation, what you get is not a linear equation anymore, but a quadratic equation: it's a completely different equation from the one at the beginning because it has two solutions, but only one is a solution for the first equation too. So, when you consider the second solution and you plug it in the first equation, you make a mistake
When you elevated the Index from 1 to 2 , the possible answer of the "x" will be 1 or -1. So that your 2nd statement is not the same as the 1st statement " x = 1 ".
2:42 You can stop right here. If x=1, then x-1=0, meaning you have divison by 0 on both sides. And as we know, division by 0 is invalid operation in math.
The mistakes is that General formula X² - Y² = (X-Y)(X+Y), where X and Y are different variables ( X is different from Y), but you used this formula for same variables as you said X is equal to 1. So, you can't use this formula for same variables
x -1 is essentially 0 ( as x = 1 and 1-1 = 0) and anything divided by 0 is infinite. (Therefore we sometimes say that it is not defined) So, you can't divide by (x-1) and cancel it.
A very clever and smart Video. We can not divide LHS and RHS by (x-1) as from the first step value of x -1 =0 And we can not divide both sides by 0..this is against rule of maths.
Actually squaring of the linear eqn in 1 variable x-1=0 does the trick here..It makes the linear expression quadratic bringing up an additional root.....Also 0/x-1 's power has been misused as x=1 makes it 0/0 so an indeterminant form is obtained and dividing x-1 by x-1 gives 0/0 form.Instead the teacher here played the trick of cancelling them thus bringing a QUESTION MARK ON to the brains of the viewer....BUT STILL THIS QUESTION ITSELF GIVES THE ELEMENTARY SCHOOL STUDENTS IDEA ABOUT THE INDETERMINANT FORM.....
Before x+1=0 in the calculation the line above the expression (×-1) does not cut out by itself. You shoud have dont cross multiplication to balance the equation.
The second line of the figure contains an error. At the 2nd line he does square of the both side, Then I get the 2 values 1 and --1.This is where the wrong is hidden because at first we let x = 1 but I get from the 2nd line x= +and - 1
First, 1^2=1. So it means that x^2=1, so x^2 -1=0. Second, when dividing both sides by (x-1), we have x=1, so simplified we have 0/0, which is undefined.
Sir you committed a mistake, when you square on both side then there is always a chance of root gain hence when we square on both side then we check our Solution i.e we put our root in initial solution. Here you gain extra root -1 because of squaring on both side. I hope you understand what I am try to say.
5 лет назад+4
ola passando para conhecer seu trabalho e já fortaleci.otima explicações vc passo sobre matemática .
I am explaining mistake by an example... In a quadratic equation, 2 solutions came in which sometimes 1 or 2 both are taken But if something given as {a is +ve or a is age, day time etc...} These are some value that can't be negative
Bro what is this x+1=0 Now divide both sides by x+1 (x+1)/(x+1)=0/(x+1) Then 1=0 Multiple both sides by 2 gives 2=0 Multiple both sides by 3/2 gives 3=0 Multiple both sides by 4/3 gives 4=0 Multiple both sides by 5/4 gives 5=0 It goes like same....
If x=1, it means x-1=0 and plugging in x says that 1-1=0 but you cannot cancel out 0's as that is the same thing as dividing by 0 which is illegal in math.
You have mistaken in 4th line. There, you have divided, "0" by "(X-1)". And, you have done, 0÷(X-1) = 0. But, it is not true. If you write it then you need to declare that (X-1) is not equal to 0. Because, "0÷(X-1) = 0" this condition is true when (X-1) is not equal to 0. And, you can not write that "(X-1) is not equal to 0" according to your condition. So here "(X-1) = 0" and any number can not be divided by 0.. I hope that you have understood.
The mistake was made when he tried to say (x+1)(x-1)/(x-1) = 0/(x-1) The problem here is that the expression (x-1) is equal to 0, hence you cannot have an expression that says something is = 0/0, hence breaking the rules of mathematics
It's been a long time since I did any math other than low level stuff, but I suspect your results come from not taking negatives into account when you squared both sides. Or something along those lines. My brain isn't wanting to accept your math here for some reason. 😜
Hahahaha da vam objasnim sa dječjeg stajališta. Kad računate nešto uvijek obratite pozornost na broj 0.Iako vam ne znači ništa a jednu je od najjačih brojeva. Kad računate nešto nikad nećete ništa moći riješiti bez tog broja 0.a veoma je ključan broj. Imate broj 12,recimo imate 12 jabuka, sad gledaj te vrijednost samo jedne 0.Uz taj broj 12 dodaj te jednu 0.I već imate odmah 120. jabuka.Izgleda veoma smiješno. Okrugla je zemlja, okrukla je vaša glava, okrugli su točkovi na vašem autu. Sve se vrti oko kruga to jest broj 0.
1 + 1=0 another method : ruclips.net/video/J4BD3jKUeoM/видео.html
It is proved: 2+2=5 : ruclips.net/video/I86TArVgnNs/видео.html
Hhhhhh
See 0/x-1
In this case x can't be 1
B/c if we make it zero the fraction becomes undefined 0/1-1 = 0/0
actually when you did this 0/x-1 this x=1, then 1-1=0 and 0/0 is not defined in mathematics so hence your calculations are not accurate
Actually, You have done the mistake in fourth statement...
Because you have divided
(x+1)-(x-1)/(x-1)
But you are forgetting that according to the rules of mathematics... You can't divide any number by zero...
Hope you will understand...😎😎😎
Yes sir
oh really?
@@Sung_jin_andre x=1 hai, agar 1-1 karenge to 0 milta hai.
Cannot divide by x-1
Bcoz x-1=0
4:00 When you raise to the second power both sides of the equation, what you get is not a linear equation anymore, but a quadratic equation: it's a completely different equation from the one at the beginning because it has two solutions, but only one is a solution for the first equation too. So, when you consider the second solution and you plug it in the first equation, you make a mistake
No, you are wrong
He made a mistake at 2:26 by dividing both sides by x-1 which is 0 since x=1
You are not wrong as I am not wrong neither: the extra solution that leads to that result comes from raising both sides to the second power
When you elevated the Index from 1 to 2 , the possible answer of the "x" will be 1 or -1. So that your 2nd statement is not the same as the 1st statement " x = 1 ".
2:42
You can stop right here.
If x=1, then x-1=0, meaning you have divison by 0 on both sides.
And as we know, division by 0 is invalid operation in math.
The mistakes is that
General formula X² - Y² = (X-Y)(X+Y), where X and Y are different variables ( X is different from Y), but you used this formula for same variables as you said X is equal to 1. So, you can't use this formula for same variables
x -1 is essentially 0 ( as x = 1 and 1-1 = 0) and anything divided by 0 is infinite. (Therefore we sometimes say that it is not defined)
So, you can't divide by (x-1) and cancel it.
A very clever and smart Video.
We can not divide LHS and RHS by (x-1) as from the first step value of x -1 =0
And we can not divide both sides by 0..this is against rule of maths.
Cheers!!
Actually squaring of the linear eqn in 1 variable x-1=0 does the trick here..It makes the linear expression quadratic bringing up an additional root.....Also 0/x-1 's power has been misused as x=1 makes it 0/0 so an indeterminant form is obtained and dividing x-1 by x-1 gives 0/0 form.Instead the teacher here played the trick of cancelling them thus bringing a QUESTION MARK ON to the brains of the viewer....BUT STILL THIS QUESTION ITSELF GIVES THE ELEMENTARY SCHOOL STUDENTS IDEA ABOUT THE INDETERMINANT FORM.....
Another fabulous share my dear friend MUCH LOVE ❤️💝👍🏻
Before x+1=0 in the calculation
the line above the expression (×-1) does not cut out by itself. You shoud have dont cross multiplication to balance the equation.
It's really nice
The second line of the figure contains an error. At the 2nd line he does square of the both side, Then I get the 2 values 1 and --1.This is where the wrong is hidden because at first we let x = 1 but I get from the 2nd line x= +and - 1
First, 1^2=1. So it means that x^2=1, so x^2 -1=0.
Second, when dividing both sides by (x-1), we have x=1, so simplified we have 0/0, which is undefined.
Very helpful..nicely explained mate
1+1=0
1+1=2
1+1-2
2-2=0
1+1=0 proved
👍
Sir you committed a mistake, when you square on both side then there is always a chance of root gain hence when we square on both side then we check our Solution i.e we put our root in initial solution.
Here you gain extra root -1 because of squaring on both side.
I hope you understand what I am try to say.
ola passando para conhecer seu trabalho e já fortaleci.otima explicações vc passo sobre matemática .
Hlw you make a my best friend
Excellent sir
this is new expert ny formula
Like 5 Nice video
Likee my friend nice video
L22 good video thanks for sharing
Very interesting. Thumbs up 👍🏼
Hhhhhh
See 0/x-1
In this case x can't be 1
B/c if we make it zero the fraction becomes undefined 0/1-1 = 0/0
And the fraction becomes undefined
Nice ...this one got me thinking longer good one :)
The formula should have been calculated as (x+1)*(x-1) which is X2+1x-1x-1 simplified as X2 - 1 = 0 where x = 1 as originally stated
Watching and Supporting.. Full View Like 27.. Hope your weekend is going well..
Ur vedios are so logical and funny
Awesome informative video 🇮🇩🇨🇦👍🏼👍🏼
Nice man
lk 10 great vedio thanks for sharing
I am explaining mistake by an example...
In a quadratic equation, 2 solutions came in which sometimes 1 or 2 both are taken
But if something given as {a is +ve or a is age, day time etc...} These are some value that can't be negative
Nice dear friend..👍👍💯
Nice !
(X+1)(x-1) =0
x=1 | x=-1
Therefore, x is not equal to 1..
In fourth step x=1 so x-1 will be zero ..... So it will be (x+1)×0 .... And last step will be 0=0
According to BODMAS rule first we have to solve in brackets that is x is equal to 1 in fourth step
Very very good I teach
It's really wosome
Yes mind Blowing!
3:06 bro there is an error,in (x+1)(x-1)/(x-1).Here x-1=0 and if denominator is 0 then the number become infinity
👍conected. 👏
Bro what is this
x+1=0
Now divide both sides by x+1
(x+1)/(x+1)=0/(x+1)
Then
1=0
Multiple both sides by 2 gives
2=0
Multiple both sides by 3/2 gives
3=0
Multiple both sides by 4/3 gives
4=0
Multiple both sides by 5/4 gives
5=0
It goes like same....
If x=1, it means x-1=0 and plugging in x says that 1-1=0 but you cannot cancel out 0's as that is the same thing as dividing by 0 which is illegal in math.
Very nice and informative video 👍👍 Thanks for sharing
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Nice vídeo...8😘🍀
in (x + 1) (x - 1)/(x -1) = 0/(x - 1), x-1 is equal to 0(since x = 1).0 in the denominator is undefined.
In RHS you have divided 0 by x-1 where x=1 so x-1=0 and we can't divide any number by 0 but divided 0 by 0
Your video is very informative. I study
The mistake was to divide x-1 because x = 1, meaning x -1 = 0. Thus, you divided by zero, making your answer false
Nice IQ test. Awesome.. new friend
You have mistaken in 4th line.
There, you have divided, "0" by "(X-1)".
And, you have done, 0÷(X-1) = 0.
But, it is not true. If you write it then you need to declare that (X-1) is not equal to 0. Because, "0÷(X-1) = 0" this condition is true when (X-1) is not equal to 0.
And, you can not write that "(X-1) is not equal to 0" according to your condition. So here "(X-1) = 0" and any number can not be divided by 0..
I hope that you have understood.
Hahhaha mind blowing👏👏👏I love your maths game😊
I love mathematics
who is watching in 2021?
Thx for sharing
When you actually devide by 5-5 or zerois equal to infinity
2+ on eter side and yes if fraction it be 2/0 or 0/2 2 on one side zero on the other
Denominator became zero already which is became all infinite
It can happen , there is just the magic of numbers
The mistake was made when he tried to say (x+1)(x-1)/(x-1) = 0/(x-1)
The problem here is that the expression (x-1) is equal to 0, hence you cannot have an expression that says something is = 0/0, hence breaking the rules of mathematics
Im happy that my students doesnt do math like this guy!!!🙂
(x-1)÷(x-1)≠1 because x=1 and 0÷0 equivalent to UNDEFINED
0/x-1 is in indeterminant form so it will not be zero
Sir x+1 is in bracket so sign changes + to - it becomes 1-1=0
It's been a long time since I did any math other than low level stuff, but I suspect your results come from not taking negatives into account when you squared both sides. Or something along those lines. My brain isn't wanting to accept your math here for some reason. 😜
I’m gonna tell my math teacher next time
Yes because you don’t have to add that one plus one instead you just bring down the zero.
*_We can't divide with (x-1) because it's 0_*
Love your video. Very informative = )
Hahahaha da vam objasnim sa dječjeg stajališta. Kad računate nešto uvijek obratite pozornost na broj 0.Iako vam ne znači ništa a jednu je od najjačih brojeva. Kad računate nešto nikad nećete ništa moći riješiti bez tog broja 0.a veoma je ključan broj. Imate broj 12,recimo imate 12 jabuka, sad gledaj te vrijednost samo jedne 0.Uz taj broj 12 dodaj te jednu 0.I već imate odmah 120. jabuka.Izgleda veoma smiješno. Okrugla je zemlja, okrukla je vaša glava, okrugli su točkovi na vašem autu. Sve se vrti oko kruga to jest broj 0.
This is not possible because
You can't divided by (x-1)
Because (x-1) is not equal to zero(0)
As you thought that x=1
This is just loss of zero you can't cancel it directly
26-2212!)
15 x 0=0 ? You have 15 apples times 0 apples, I'm still looking at 15 apples in front of me.
(x+1)(x-1)/(x-1)=(x+1)(0)/(0)=0/0 (result cannot be determined) (this is the mistake) ie x-1=0
You can't divide any number with 0.
😂😂
x =1 then. x-1=o then division by zero is not possible. Sothe answer is not correct
That multiplication had no place there. and it could not be equal to zero. see you in your next upload
You can't devide by (x-1) , because x-1=0 . And 0/(x-1)= 0/0 in NOT equal 0 ! Here is a trick.
I😱don’t understand how it 1+1=0 join u
Stay connected
1-1=0
1-1=0-1
-1 cancellation from both side
1=0 🤣🤣🤣
X-1 =0 if x=1 then (x+1)(x-1)/(x-1) will become undefined
First here watching and like..
OMG how can it be zero? And I dislike Math.....
You are not good student because mathmatics analysis human mind deeply
if 56-57=0 so it was nice
He made a mistake at 2:26 by dividing both sides by x-1 which is 0 since x=1
Excuse me but (x-1)(x+1)=0 sssi x-1=0 ou x +1=0 sssi
x=1 pour x-1=0
x= -1 pour x + 1= 0
He divided Both side with x-1 thats the error cause Value of X is 1 and 1-1 is 0 and anything divided by Zero is not defined
There is division by 0 in forth statement
I am from india bro 👍👍👍👍😘😘😘😯😯
😂😂👍 nice man nice
Saludos
It is very easy
0/0=2
Nula kao broj nije broj, a nula kao broj puno znači ako uz nulu dodate broj 1.Recimo 1.000000.onda imate puno značenje broja 0.
U r correct if u follow number circle
1+1=2
1+1-2=0
2-2=0
1+1=0 ( proved )
0/x-1 different de0
Nula kao broj ne znači ništa, zato što je ništa. A nekad broj 0.zna biti najjači broj među svim brojevima.
x=1 so x-1=0
you can't divide a number that is equal to 0