Harmonic Force Excitation Steady State Amplitude and Phase Proof

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  • Опубликовано: 30 янв 2025

Комментарии • 14

  • @virtually_passed
    @virtually_passed  3 года назад

    Minor correction: at 9:46 I didn't complete the bracket in the denominator. It should read (1-(w/wn)^2)^2

  • @Legendsneverdie0917
    @Legendsneverdie0917 5 лет назад +4

    Thank you from Mongolian University of Science and Technology

  • @icee562
    @icee562 4 года назад +2

    This is amazing!

  • @jafnisaufi2571
    @jafnisaufi2571 4 года назад +1

    What's the difference between maximum steady state displacement and a steady state amplitude?

  • @gameon8999
    @gameon8999 5 лет назад +3

    Thnx a lot!

  • @srihartono6824
    @srihartono6824 8 месяцев назад

    @virtually_passed , what if Fo*cos (wt), is it cos(wt) equal = e^iwt and take the real part directly ?

    • @virtually_passed
      @virtually_passed  8 месяцев назад

      Cos(wt) = Re {e^jwt}

    • @srihartono6824
      @srihartono6824 8 месяцев назад

      ​@@virtually_passed however, the result is a little bit different from what you written ; the result is X cos (Wt - arctan(phi))

    • @srihartono6824
      @srihartono6824 8 месяцев назад

      ​@@virtually_passedis it right my answer?

  • @bartolomeodiaz7847
    @bartolomeodiaz7847 6 месяцев назад

    What program do you use to write?

    • @virtually_passed
      @virtually_passed  6 месяцев назад

      Microsoft onenote 2016. Although you can use many others like krita or Photoshop

    • @bartolomeodiaz7847
      @bartolomeodiaz7847 6 месяцев назад

      @@virtually_passed Thanks

  • @quantum.starhop
    @quantum.starhop 2 года назад

    I think you may have left a mistake in your final expression for X (written in orange). The second term in the radical in the denominator should be (1-(omega/omega_n)^2)^2.

    • @virtually_passed
      @virtually_passed  2 года назад

      You are correct! Thank you for pointing that out! I've pinned a comment so others can see it :)