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Minor correction: at 9:46 I didn't complete the bracket in the denominator. It should read (1-(w/wn)^2)^2
Thank you from Mongolian University of Science and Technology
This is amazing!
What's the difference between maximum steady state displacement and a steady state amplitude?
Thnx a lot!
@virtually_passed , what if Fo*cos (wt), is it cos(wt) equal = e^iwt and take the real part directly ?
Cos(wt) = Re {e^jwt}
@@virtually_passed however, the result is a little bit different from what you written ; the result is X cos (Wt - arctan(phi))
@@virtually_passedis it right my answer?
What program do you use to write?
Microsoft onenote 2016. Although you can use many others like krita or Photoshop
@@virtually_passed Thanks
I think you may have left a mistake in your final expression for X (written in orange). The second term in the radical in the denominator should be (1-(omega/omega_n)^2)^2.
You are correct! Thank you for pointing that out! I've pinned a comment so others can see it :)
Minor correction: at 9:46 I didn't complete the bracket in the denominator. It should read (1-(w/wn)^2)^2
Thank you from Mongolian University of Science and Technology
This is amazing!
What's the difference between maximum steady state displacement and a steady state amplitude?
Thnx a lot!
@virtually_passed , what if Fo*cos (wt), is it cos(wt) equal = e^iwt and take the real part directly ?
Cos(wt) = Re {e^jwt}
@@virtually_passed however, the result is a little bit different from what you written ; the result is X cos (Wt - arctan(phi))
@@virtually_passedis it right my answer?
What program do you use to write?
Microsoft onenote 2016. Although you can use many others like krita or Photoshop
@@virtually_passed Thanks
I think you may have left a mistake in your final expression for X (written in orange). The second term in the radical in the denominator should be (1-(omega/omega_n)^2)^2.
You are correct! Thank you for pointing that out! I've pinned a comment so others can see it :)