You know what the best part is? You're explaining it from the perspective of a learner. What doubts might come up remain your primary concern, and that helps so much more to understand. Also, That 0/0 part was funny. Ami dekhte dekhte bhabchilam ei ekhoni bhul korbi (0/0 ke 0 bolbi. But then you went to some other level xD. Infinity?, Nahi.. Undefined! Kudos to you man! :)
Sir, in this video you explained it with the help of an external resistance. I have thought it in a totally different way in which there is no external resistance. The circuit only consists of conducting wire, the cell and the load. Let there be some finite potential difference across the cell terminals. This also creates a potential difference across the terminals of the load. Here, let's bring the concept of heat generated due to flow of current. For the sake of simplicity, let us assume that across the conducting wire between the positive terminal of the cell and that of the load, there is no heat energy generated (of course there is heat energy generated but relative to the heating of the load, that can be considered negligible). So, the potential energy of the charges (assumed to be some kind of positive charge) remains intact as none of it is getting converted to heat. So the potential energy across the conductor between like terminals of cell and load is 0. Potential difference exists between the unlike terminals of the cell and the load. This is very much sufficient to maintain the current flow. The chemical reaction within the cell does work against the electric force and brings the charges to the higher potential and the cycle continues. So if we consider two points on the conducting wire between the load and the cell, the potential difference between those 2 points is 0, yet current flows across the two points, hence the answer. I had thought of this as a class IX student. I just want to know whether my explanation is correct or not. Please correct me if I am wrong anywhere.
You are comparing the resistance across the conducting wire with the external resistance.. But suppose there is 0 external resistance.. Resistance of conductor is very high then(relative to external resistance). This would result in very low current which can be assumed to be 0 current
Sir in the video you explained 0/0 to be undefined(not infinity). Let's talk first what you have explained in the video. You told that relative to external resistance, resistance of conducting wire is 0. So, nothing opposes the flow of current across 2 given ends of the wire. So, shouldn't infinite current flow when external resistance is very high compared to internal resistance?
1:13 sorry sir but I have a very stupid doubt that is ---> when current starts flowing from battery why is it already 2A, it should be 2A after passing through the resistor so my actual doubt is that current before and after the resistor should be different because current faces resistor after passing through half the circuit😢😢 pls reply ASAP sir
@@sagunsachan528 But you have a misconception. Current is the amount of charge flowing through a cross section. The resistor just opposes the flow of current, due to which the KE of free electrons decreases but the amount of charges still remains the same. Why are you saying that it should be 2A after the resistor? The current drawn from the battery is 2A and this current will flow unchanged throughout the circuit
Sir if potential difference is very less then electric field between those points will also be very low. And similarly the potential difference across resistor is comparatively very high then there will be high electric field inside the resistor. Is it possible to have variable electric field inside same circuit? Could you plz explain it🙏
You know what the best part is? You're explaining it from the perspective of a learner. What doubts might come up remain your primary concern, and that helps so much more to understand. Also, That 0/0 part was funny. Ami dekhte dekhte bhabchilam ei ekhoni bhul korbi (0/0 ke 0 bolbi. But then you went to some other level xD. Infinity?, Nahi.. Undefined! Kudos to you man!
:)
Thankyou for paying attention to the tiny details 🙈. I am literally reading this comment on loop and smiling 😂. Thankyou so much❤
Thank u so much sir
Super bro
Great
Great answer
Excellent method of teaching
Sir, in this video you explained it with the help of an external resistance. I have thought it in a totally different way in which there is no external resistance. The circuit only consists of conducting wire, the cell and the load. Let there be some finite potential difference across the cell terminals. This also creates a potential difference across the terminals of the load. Here, let's bring the concept of heat generated due to flow of current. For the sake of simplicity, let us assume that across the conducting wire between the positive terminal of the cell and that of the load, there is no heat energy generated (of course there is heat energy generated but relative to the heating of the load, that can be considered negligible). So, the potential energy of the charges (assumed to be some kind of positive charge) remains intact as none of it is getting converted to heat. So the potential energy across the conductor between like terminals of cell and load is 0. Potential difference exists between the unlike terminals of the cell and the load. This is very much sufficient to maintain the current flow. The chemical reaction within the cell does work against the electric force and brings the charges to the higher potential and the cycle continues. So if we consider two points on the conducting wire between the load and the cell, the potential difference between those 2 points is 0, yet current flows across the two points, hence the answer.
I had thought of this as a class IX student. I just want to know whether my explanation is correct or not. Please correct me if I am wrong anywhere.
you are great 👍
Awesome 😎🔥
Nice explanation!
You are comparing the resistance across the conducting wire with the external resistance.. But suppose there is 0 external resistance.. Resistance of conductor is very high then(relative to external resistance). This would result in very low current which can be assumed to be 0 current
@@suryavajana9986 correct
Sir in the video you explained 0/0 to be undefined(not infinity). Let's talk first what you have explained in the video. You told that relative to external resistance, resistance of conducting wire is 0. So, nothing opposes the flow of current across 2 given ends of the wire. So, shouldn't infinite current flow when external resistance is very high compared to internal resistance?
Voice match with rahul gandhi
Oshadharon teacher bhai tui ❤️
Thankyou dada. Glad to hear that💛😁
Keep it up man!
1:13 sorry sir but I have a very stupid doubt that is ---> when current starts flowing from battery why is it already 2A, it should be 2A after passing through the resistor so my actual doubt is that current before and after the resistor should be different because current faces resistor after passing through half the circuit😢😢 pls reply ASAP sir
pls reply sir
i will have science test after few days
@@sagunsachan528 But you have a misconception.
Current is the amount of charge flowing through a cross section.
The resistor just opposes the flow of current, due to which the KE of free electrons decreases but the amount of charges still remains the same.
Why are you saying that it should be 2A after the resistor?
The current drawn from the battery is 2A and this current will flow unchanged throughout the circuit
Voice and accent both matches with rahul gandhi
Sir if potential difference is very less then electric field between those points will also be very low. And similarly the potential difference across resistor is comparatively very high then there will be high electric field inside the resistor. Is it possible to have variable electric field inside same circuit? Could you plz explain it🙏
Yes its possible if we vary the pd applied across the ends of the conductor.