Hi again. Just uploaded it here as free download: wonkylogic.co/a-level-physics-hq Will put it on TES too but on my website no login needed for download.
The percentages are percentage uncertainties in gradient or intercept. They are related to a quantity of interest - e.g. resistivity (ρ) - so apply uncertainty calculation rules to determine percentage uncertainty in that quantity. Then multiply percentage uncertainty by the value of the quantity for the absolute uncertainty of the quantity. E.G. gradient = ρ/A ⇒ %ρ = %gradient + %A If ρ = 2.3 × 10⁻⁸ Ω m And if %ρ was determined to be 5.8% then absolute uncertainty is 1 × 10⁻⁹ Ω m. So the absolute uncertainty of the gradient or intercept is not of so much interest but the absolute uncertainty of the final value is of interest.
Great video, thanks!
You're welcome!
@@PhysicsHQ Just keep uploading more videos like these 👍
I’ve got the follow up video for analysing log graphs coming soon.
Wow this explained everything so well!! Thank you so much for this video!
You’re welcome ☺️
All the best with your studies!
This video helped me a lot! Thank you very much!
You're welcome! Glad it helped.
really love this, very clear explanation. Is it possible to ask for the ppt you used? Would really appreciate it
Thanks very much!
It’s a Keynote presentation not PowerPoint. But yes I can share that via my website & TES. I’ll ping a link.
Hi again. Just uploaded it here as free download: wonkylogic.co/a-level-physics-hq
Will put it on TES too but on my website no login needed for download.
clean presentation👌👌👌
Thanks. All the best with your studies.
Thank you so much! 🥰 love the hair btw 😅
😊 thanks. I am at the mercy of what my hair does day to day!
All the best - especially if you have exams coming up.
Don’t still get how you got your error bars though
Did you just take a random pick at the +/- values?
thanks a lot sir
Thanks! You’re welcome.
May you please drop the link for the tips for not starting from the zero origin .
Surely you should have a modulus sign on the bottom as if the gradient is negative you'll get a negative uncertainty
That’s right. A negative uncertainty wouldn’t make sense.
@@PhysicsHQ okay was just saying because you didn't include a modulus on the bottom of your formula
Yes I see that now. Had forgotten at the time that the standard percentage difference equation needed modification.
Thx alot, great video
Does %c mean the the percentage uncertainty?
%c is the percentage uncertainty in the y-intercept.
How can I change the percentage to a definite value
The percentages are percentage uncertainties in gradient or intercept. They are related to a quantity of interest - e.g. resistivity (ρ) - so apply uncertainty calculation rules to determine percentage uncertainty in that quantity. Then multiply percentage uncertainty by the value of the quantity for the absolute uncertainty of the quantity.
E.G. gradient = ρ/A ⇒ %ρ = %gradient + %A
If ρ = 2.3 × 10⁻⁸ Ω m
And if %ρ was determined to be 5.8% then absolute uncertainty is 1 × 10⁻⁹ Ω m.
So the absolute uncertainty of the gradient or intercept is not of so much interest but the absolute uncertainty of the final value is of interest.