Hi again. Just uploaded it here as free download: wonkylogic.co/a-level-physics-hq Will put it on TES too but on my website no login needed for download.
The percentages are percentage uncertainties in gradient or intercept. They are related to a quantity of interest - e.g. resistivity (ρ) - so apply uncertainty calculation rules to determine percentage uncertainty in that quantity. Then multiply percentage uncertainty by the value of the quantity for the absolute uncertainty of the quantity. E.G. gradient = ρ/A ⇒ %ρ = %gradient + %A If ρ = 2.3 × 10⁻⁸ Ω m And if %ρ was determined to be 5.8% then absolute uncertainty is 1 × 10⁻⁹ Ω m. So the absolute uncertainty of the gradient or intercept is not of so much interest but the absolute uncertainty of the final value is of interest.
Great video, thanks!
You're welcome!
@@PhysicsHQ Just keep uploading more videos like these 👍
I’ve got the follow up video for analysing log graphs coming soon.
Wow this explained everything so well!! Thank you so much for this video!
You’re welcome ☺️
All the best with your studies!
This video helped me a lot! Thank you very much!
You're welcome! Glad it helped.
thanks a lot sir
Thanks! You’re welcome.
really love this, very clear explanation. Is it possible to ask for the ppt you used? Would really appreciate it
Thanks very much!
It’s a Keynote presentation not PowerPoint. But yes I can share that via my website & TES. I’ll ping a link.
Hi again. Just uploaded it here as free download: wonkylogic.co/a-level-physics-hq
Will put it on TES too but on my website no login needed for download.
Don’t still get how you got your error bars though
Did you just take a random pick at the +/- values?
Thank you so much! 🥰 love the hair btw 😅
😊 thanks. I am at the mercy of what my hair does day to day!
All the best - especially if you have exams coming up.
clean presentation👌👌👌
Thanks. All the best with your studies.
Thx alot, great video
May you please drop the link for the tips for not starting from the zero origin .
Surely you should have a modulus sign on the bottom as if the gradient is negative you'll get a negative uncertainty
That’s right. A negative uncertainty wouldn’t make sense.
@@PhysicsHQ okay was just saying because you didn't include a modulus on the bottom of your formula
Yes I see that now. Had forgotten at the time that the standard percentage difference equation needed modification.
Does %c mean the the percentage uncertainty?
%c is the percentage uncertainty in the y-intercept.
How can I change the percentage to a definite value
The percentages are percentage uncertainties in gradient or intercept. They are related to a quantity of interest - e.g. resistivity (ρ) - so apply uncertainty calculation rules to determine percentage uncertainty in that quantity. Then multiply percentage uncertainty by the value of the quantity for the absolute uncertainty of the quantity.
E.G. gradient = ρ/A ⇒ %ρ = %gradient + %A
If ρ = 2.3 × 10⁻⁸ Ω m
And if %ρ was determined to be 5.8% then absolute uncertainty is 1 × 10⁻⁹ Ω m.
So the absolute uncertainty of the gradient or intercept is not of so much interest but the absolute uncertainty of the final value is of interest.