I have two questions. 1) Is this a proper DFA? What I meant was that (A,1)=? and (B,0)=? 2) What happens if the start and accepting states are same? For example, (q0,a)=q1, (q0,b)=q3, (q1,a)=q2, (q1,b)=q0, (q2,a)=(q2,b)=q2,(q3,a)=q0,(q3,b)=q2 and q0 is both the initial and final state.
You always teach so well as easy to understand madam🙌
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Beautifully explained
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Awesome explanation ... Thank you !!
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best explanation keep up...
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Nice explanation mam😍
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Amazing explanation
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I have two questions.
1) Is this a proper DFA? What I meant was that (A,1)=? and (B,0)=?
2) What happens if the start and accepting states are same? For example, (q0,a)=q1, (q0,b)=q3, (q1,a)=q2, (q1,b)=q0, (q2,a)=(q2,b)=q2,(q3,a)=q0,(q3,b)=q2 and q0 is both the initial and final state.
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x^+ and x^+ x^(*+) can u plz solve this regular expression? I want this❤