Implementing 8X1 MUX using 2X1 MUX
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- Опубликовано: 21 окт 2024
- Digital Electronics: Implementing 8X1 MUX using 2X1 MUX
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This is so much easier than how my professor does it. I can't believe how complicating he can make simple things.
Thanks!
Same here bro
then send me video or any handout for preparation , Brother
Same here as well. Really sad how the education system functions :(
Same here :(
You're my hero. These videos are so clear and concise!
EA THATS RIGHT
Hello Cecilia, I just watched all your videos. It's so nice, keep up the good work!
I M YOUR HERO BABY! listen this song
Sir, you are the best teacher any student ever can have.
For the people who are confused on how the select lines were obtained, try writing the select lines required for all the inputs.
It will give you:
I0 = 000
I1 = 100
I2 = 010
I3 = 110 and so on.
From this, we can see the pattern that the last select line is similar to S2, the middle one is similar to S1 and the first line is similar to S0.
Still unable to get it...Plz help so that I can understand....!!!
Can u elaborate
Thanks
thank you so much! For those who didnt get it, just write down the select lines to get I0-I7. and you'll see
@@meharshaik1070 try seeing it in this way, the final ans Y will depend upon the last 2x1 mux'es select line, so it will have the highest priority. So start from right to left in the block diagram. If you take S2 as the select line of the last 2x1 mux, then S2 will either be 0/1. If S2=0 then you are now at the upper mux at second level. Now if you take S1 as the select line then it also be either 0/1. If S1=0 then you are now at the upper mux at first level. Now only S0 is left , it will also have 2 options 0/1, if S0=0 then I0 will get selected. See this as a hierarchy, (S2S1S0), S2 is the MSB which is switched less, so it will have the most authority, while S0 is switched more frequently to 0,1,0,1 so it will have the least priority.
spent all afternoon trying to figure this out, found this video and completed my problem in 10 mins. Thank you
I have seen a lot of online tutors, very few of them are so organised and in sync with our syllabus. Great job!!
Thanx neso....ur videos are very simple and clear...
Thanks a lot for simplifying this topic.
Thanks man ,😂😂😂 u have best way to convey lesson
Note for future me-:
Notice that S0,S1,S2 is applicable to an entire section of multiplexer.
Means S0 is applicable to those 4 multiplexer,S1 is to those two 2×1 MUX and S2 to that one 2×1 MUX.
IGNORE IF YOU READ THIS COMMENT
You actually saved my whole life
Thank you sir for such an easy explanation
Thank you very much for your good work you have been able to help me many times with logical design and you make such good presentations the reason i know what i know is you please keep up the good work.
Thanks you so much
Maybe now have not enough money to support neso but one day going to do
Your videos are very clear and helpful, thanks a lot for your good work!
Very good explaining! Thank you a lot.
Amazing lecture series. Thanx a ton
Sir your videos are really good and helpful
Thank u so much
keep making more ;)
you are a herooooo and with you my understood becomes from zero to hero :)
Muito bom! Parabéns! Saudações do Brasil.
You sir are the best!
I`m tired of telling Thank you but that is so tiny word against your huge job
Thank You Sir..really a very good lecture..
Great job sir❤
thank you!! is this same as cascading?
Thank you sir
Very worthy! Thanks
Sir , can we draw a 8x1 multiplexer using 2x1 multiplexer using the enable signal?
Hello :) Sorry for disturbing you, but i would like to know if in the last mutiplexer in the right( the 2*1 multiplexer), the control input youve chosen is the last one to choose beetween S2, S1 and S0, because i tought, S2 in the test youve done is also acting like S1 so i asked if you decided that S2 is in the last multiplexer on the right is the last one to decide if its S0, S1,S2.
Thanks
Tq sir .this is so much easy
What is about reducing 4x1 MUX to 2X1 MUX or 8X1 MUX to 4X1 MUX?
I would be grateful if you could make a video about this topic.
The implementation of 6 Boolean functions of 4 variables using an 8-to-1 line multiplexer for each, This is what i am trying to learn for the exam, can you tell me how to do the questions regarding the topic mentioned above
In one of the test they ask to built 2*1 mux using 8*1 mux...I want answer from you? How we can do that?
Sir.. How to decide to take S1 & S2 cz both are 0 0(8×1 MUX using 2×1 MUX)??
Hey nezo answer it
Take another output and sought it u can get which one to take
please give us a lecture about this topic how to solve Boolean Algebra using two 4 * 1 marks and necessary Gates.
THANKS A LOT
NICE LECTURES ....
In the last, how to decide whom to give what among S1 and S2,(in two 2X1 and one 2X1 MUX) because output of both are 0 0 ?
Your videos are awesome as usual...:)
same question here
That is because when you try selecting i2 and i3 at 1st mux u get 0101 2nd mux 0011 3rd mux 0000 hence from the truth table it will be s0 for 1st stage s1 for 2nd stage and s2 for 3rd stage I think this should be a way to find the solution because when I tried solvin for further cases this is the result i got .hope it would be helpful
For the people who are confused on how the select lines were obtained, try writing the select lines required for all the inputs.
It will give you:
I0 = 000
I1 = 100
I2 = 010
I3 = 110 and so on.
From this, we can see the pattern that the last select line is similar to S2, the middle one is similar to S1 and the first line is similar to S0.
@@sandhyachowdhary2511 yes that's the correct one.
3:07(Determining select line)
If I had watched this video today, I swear could have passed my exams.. Great video
Is it not better to conclude that a 2^n by 1 mux can be implemented using (2^n -1) 2 by 1 MUXes
But I know you do it this way so that it is simpler to understand how to line up the 2 by 1 MUXes
Thank you, really helpful video
I am not getting how is S0,S1,S2 are distinguished as selection line in logic diagram
Sir I have a doute that is we take starting 4( 2'1 mux ) there data selectors are S2 i think but u have menton that is S0 how sir
Thanks!
isnt there a need for enable in the above problem? 8:1 using 2:1?
Hello sir, how were you selecting I0, I1 using slect line inputs in circuit diagram? I didn't get that.. Please help me out with that
kya baat!!sb smjh aa gya:)
I have one doubt sir....if we put selector line as 1 for i2 i3 input what will happen ...?
Did you get the answer
thx man ...... very useful
very very easy man tumbs up
How can we implement 16x1 mux using 8x1 mux? Please explain
not understood
Dumb????
sir it was an awesome videos but sir one doubt can we make 1:8 demux using 1:2 mux
Explain how to build ex-nor using 2*1 mux only
What about enable pin? what to connect to enable pin?
thanks !!!
S0,S1,S2 must be the order in that table not S2,S1,S0!!! .. correct me if im wrong
It is nice explanation..
how do u differentiate S2 and S1 since they're both 00? how did u decide output MUX is S2 and not S1?
Respected sir I m not able to select either 1 or 0 given to select line .. please help
For the people who are confused on how the select lines were obtained, try writing the select lines required for all the inputs.
It will give you:
I0 = 000
I1 = 100
I2 = 010
I3 = 110 and so on.
From this, we can see the pattern that the last select line is similar to S2, the middle one is similar to S1 and the first line is similar to S0.
Sir, I am in little doubt .
That why u didn't enable any of the 2:1mux. I think every 2:1 mux must be enable. Am I right?
but if 2 ics use then select line are shoted n ?
For first four mux you told that if “0” is taken as select line for 1st mux then it should be followed for other mux.Why?
yes for all same sequential mux it is same.
Why is it same?
big fan
Sir how u select select line I didn't get it sir please explain sir
Thanks
Select line jaise taise karke samjha Diya🥲🥲🤧🤧
KHOPDI KHOLTE, GAWD BOLTE!
can the last mux be replaced by OR gate??
we don't require enable input ?
How we can judge that the select lines are acting as s0 s1 s2 respectively
Any one reply me
PLEASE HELP !!!!
i could not understand exactly the last part of the video ? if we are having 1|0 for the 4 first MUX 2*1 , and 0|0 for the second part and 0|0 for the last part ,, why the second part is connected to S1 AND the last part to S2 ,,, as S2 contains 0000 on its column and S1 has 00 on its column , in my case i would change the position and might say that the second part is connected to S2 as well as the last part would connect it to S1 which means reversing what you've done , this is just my way to think , i am not saying that is correct !!! just have this doubt in my head ,,,, is a serious doubt that i have and would be great to clarify me please this point ,,,, and why also after using the inputs i0 and i1 we did not set i2 as a third case for getting finally 3 bits in each part rather than 2 bits ?? please explain us this point that would let us jump to the next videos ,,, thank you for the effort that you have done for the community and for your open knowledge that you provide us , Thank you
how to convert 2X1 mux to 16 X1 mux ?anyone
means total select lines are 3 in this implementation!? can anyone confirm this!?🙄
I don't understand why the first four muxs are S0 and the other 2 s1 and the last s2. Can you explain me pls? thanks for the video
For the people who are confused on how the select lines were obtained, try writing the select lines required for all the inputs.
It will give you:
I0 = 000
I1 = 100
I2 = 010
I3 = 110 and so on.
From this, we can see the pattern that the last select line is similar to S2, the middle one is similar to S1 and the first line is similar to S0.
Design 2x1 MUX using 8x1 MUX ?
uild a 2:1 MUX using an 8:1 MUX. (Yes, the question is right. Build a 2:1 MUX using an 8:1
MUX)
Sir is there any possible to design 2:1 mux by using 8:1 mux
iam not get total clearance.
OP BAHI OP!
How Can you say that that all have to be 1 or 0 at 4:29
AMIT BANSAL because it has to be same for all 4 of the MUX than only we can get same selection line
Wdym ?
As Simple As That...
whether we can put s1,s2 alternatively
Sry 1:8 demux using 1:2 demux
Share the video
NICE
mahabakas mudde ki bt kr
❣❣
You r too fast and pls explain detailedly
its a really very wELL..