Homologous Recombination for Double Strand Breaks Part 4

Поделиться
HTML-код
  • Опубликовано: 3 фев 2025

Комментарии • 25

  • @purpearl1
    @purpearl1 9 лет назад +2

    I DONT KNOW HOW TO THANK YOU , I WAS SEARCHING FOR CLEAR EXPLANATION OF THIS MACHANISM BUT I FINALLY EVERY HINGS ARE CLEAR TO ME THANK YOU VERY VERY MUCH

  • @anasaldarriaga9362
    @anasaldarriaga9362 5 лет назад +1

    Thank you very much! You are a great teacher, you help me more than any other. This is my thesis topic and after reading a lot of papers you were the only one who lightered the path of understanding

  • @Satkat_Ind3981
    @Satkat_Ind3981 4 года назад

    You are a fantastic teacher. The most diffiult thing innsciencek is to make it simple and you have mastered it. Thanks

  • @sheMessages
    @sheMessages 8 лет назад +1

    I had to pause it just to say this vid is amazing!, thank you!!

  • @anerolvial
    @anerolvial 9 лет назад +1

    Loved your video. Found it very useful, since I am now going over CRISPR/Cas. Thank you!

  • @badmadmat20
    @badmadmat20 8 лет назад +1

    this is delightful! very detailed. love it

  • @lilianavertel9789
    @lilianavertel9789 7 месяцев назад

    You are the best!

  • @indocampus2002
    @indocampus2002 8 лет назад

    thank you very much for your explanation..it really helps me!

  • @annaiahramesh
    @annaiahramesh 7 лет назад

    informative and very nice explanation. Thanks a lot

  • @patamon6475
    @patamon6475 3 года назад

    thanks for your effort

  • @junxing9680
    @junxing9680 7 лет назад

    Thank you very much, very specific explanation

  • @pragha1
    @pragha1 5 лет назад

    Great video! I have just one question. How does it know when to stop strand extension? Because if the extension is too long it won't be necessarily complimentary to the other 3' overhang.

  • @crocketmeow
    @crocketmeow 7 лет назад +1

    I like the comprehensive explanations; questions:
    In prokaryotes, strand invasion is mediated by RecA. The eukaryotic analogue is Rad 51.
    In prokaryotes, branch migration is mediated by RuvAB. What are the eukaryotic analogues of RuvA/B?
    In prokaryotes, Holliday junction resolution is mediated by RuvC. What is the eukaryotic analogue of RuvC?
    In prokaryotes,RuvD cuts the strands horizontally or vertically. What is the eukaryotic analogue of RuvD?

    • @annaiahramesh1542
      @annaiahramesh1542 Год назад

      I am really very much thankful to you for your excellent explanation. But still I don't know how all of a sudden H2A histone protein replaced by H2AX. Because DNA damaging event is random and H2A is canonical histone protein.
      Another one is recombination part, but it's hard to accept the mechanism how it happens between Homologous chromosomes.
      Any how right now this is accepted model by the scientific community, let we look forward for more refined version. Once again thank you very much.

  • @ayaqz3144
    @ayaqz3144 4 года назад

    thank youu i will pray for you

  • @dc33333
    @dc33333 6 лет назад

    excellent speaker

  • @mattiles5811
    @mattiles5811 7 лет назад +1

    how is the overhang ~1000 bp when the MRN only moved back 100-200bp?

    • @Dead1M
      @Dead1M 7 лет назад

      There will be another exonuclease, but a 5'-->3' exonuclease, which cuts away the DNA even further. (On the strand which has the 5' end facing the 'broken' end.)

  • @mobin4333
    @mobin4333 8 лет назад +1

    thanks alot

  • @Professorbubblegum
    @Professorbubblegum 7 лет назад

    bless you

  • @mikesmith3859
    @mikesmith3859 4 года назад +1

    *Knows complex science surrounding DNA repair
    also elliot
    *calls pink purple multiple times

  • @alialviev1848
    @alialviev1848 6 лет назад

    CtIP, not CtLP. But great!

    • @salibkh3208
      @salibkh3208 4 года назад

      For everything HE explained and everything he knows I'm 1000% sure he's well aware of how it is named !!!!!! Great is not enough to describe this lecture !!!

  • @sdas127
    @sdas127 7 лет назад

    nice illustration. Ctlp is not correct. It is actually CtIP.