Best explanation, it should be on top search list on this topic. I've wasted multiple hours trying to understand from different videos, but none of the video explained everything like this video. Thank you for the video. Love from Nepal 🇳🇵
No brother. This theory wrong. Once capacitor charge 0.7 volt. And can not charge again 0.7. Because discharge not occur. How possible again capacitor charge ?
The way you have connected RL1 and R2 makes sense. I have seen other explanations that say the capacitor is charged through RL1 which doesn't make sense because the transistor won't turn on if the negative plate of the capacitor is facing Q2. Good job.
C2 charges through R2 because only that path can connect C2 with Vcc when Q2 is off. If C2 charges through RL1, there will be no direct connection between C2 and Vcc, so that cannot be the charging path
It does make sense so far I think, however when C2 charges, how comes C1 is not charging simultaneously also? Is it because the voltage is Vcc at the negative terminal of the capacitor?
At 7.28 min u said ,when switch us closed,only one transistor will be on ,why both the transistors are ON at a time when the vcc is same for both the transistors?sir..plz clarify my doubt sir
Awesome video! The only thing I am a little confused about is why int he very beginning, how come since one transistor is on the other is off? If both are trying to drive on at first, what makes one magically switch off? After this point though, I understand why the two switch states.
Nicely explained. But i have a doubt sir when we give Vcc in starting what is the path of current/ voltage so that one of the transistor will get 0.7 V and will get on.
+Sneha Murya, may be you know similat transistors do not have identical B-E and B-C junction voltage. the transistor with lower base-emitter junction voltage should turn on first.
Thank you for explaining this circuit. Nicely rendered. And thank you for your "practical" presentation at the last too!
Yes
Best explanation, it should be on top search list on this topic. I've wasted multiple hours trying to understand from different videos, but none of the video explained everything like this video. Thank you for the video. Love from Nepal 🇳🇵
No brother.
This theory wrong.
Once capacitor charge 0.7 volt. And can not charge again 0.7. Because discharge not occur. How possible again capacitor charge ?
nicely and clearly explained, thanks for the details,
The way you have connected RL1 and R2 makes sense. I have seen other explanations that say the capacitor is charged through RL1 which doesn't make sense because the transistor won't turn on if the negative plate of the capacitor is facing Q2. Good job.
C2 charges through R2 because only that path can connect C2 with Vcc when Q2 is off. If C2 charges through RL1, there will be no direct connection between C2 and Vcc, so that cannot be the charging path
Another question: C2 charges when Q1 is in ON state. When does C2 discharge?
C2 get discharge when Q1is in off state
Wow such a good lecturer.... That was very clear. Am satisfied. Everything point is touched. Thank you!
Thanku sir you made it very clear..
Thank you sir You also showed two practicals in the last
Wow, That was really great job
Sir thank you so much I'm very grateful to teachers like you👌👍
Nice explanation sir!
just watched before the practical exam...too good and understandable... thank you so much...keep going on
incredibly and
superbly explained
Great explanation, thanks a lot!
This is amazing really.
Gud explanation....thank u sir...
very well explained . thank-you
Superb explanation SIR... 👌
Please Make more such videos...
sir i found your videoes very helpfull. upload more and more good video.
ee academy u are a grade teacher
very good explanation sir
Thank you sir
can you please do some videos on oscillator circuits?? your way of getting things done is quite effective.
+EE Academy
ok sure.but nice work.and congratulation.which univ u r going
Thank you sir.I must highly recommend you for using universally known language
why is electronics hard to understand? But well explained dude, excellent explanation
Voltage at base terminal become approximately equal to -Vcc when the transistor is off.
wow amazing🎉❤
Thank you for the video!
excellent
It does make sense so far I think, however when C2 charges, how comes C1 is not charging simultaneously also? Is it because the voltage is Vcc at the negative terminal of the capacitor?
InMy Idea
As the Discharging path for c1is lower then that of c2 therefore c1will discharge more rapidly
Bhalo channel banaiso bhai. Chalay jao :)
Excellent explanation.. Brilliant...
Thankyou very Much . Can u tell why the doping conc. is kept different in two transistors
Good question👍
When the capacitors will be discharged through which path?
Can some explain the concept of grounding in this circuit
Awesome explnation very cool nd neat would u give any material for this
By the way thanks for the video
too good and simplicity at its extreme. loved it
if capacitors in the circuit discharges after their fully charged or it discharges after 0.7v to turn on transistors?
Thanks for the nice explanation.....:
At 7.28 min u said ,when switch us closed,only one transistor will be on ,why both the transistors are ON at a time when the vcc is same for both the transistors?sir..plz clarify my doubt sir
I really liked it. I also request for an explanation of 555 timer under this Chanel.
Thank you. A very good explanation about astable multivibrator.
Thank for trying but the quality is the best. Sounding like a the buzz of the circuit you describing :)
Awesome video! The only thing I am a little confused about is why int he very beginning, how come since one transistor is on the other is off? If both are trying to drive on at first, what makes one magically switch off? After this point though, I understand why the two switch states.
masha'Allah brother
thanks bro.very nicely done..(Y)
bahut a66eee guru g
Super explanation thank u so much
Nice explanation, keep it up.
U are great...
Good
sir how do we connect its output for a stepup transformer?
superbly explained..
where is biasing voltage source?
Vcc is the biasing voltage
can we use 555 timer and if yes why we use this
Life saver...cheers mate..
I have one doubt why resistance is connected to vcc will not contribute to any voltage drop
The case assumed in this video is ideal
thnx man. this helped a lot
awesome
Awesome explanation
Tnxx
Thank u so much bro😊😊
Then what is the use of having RL1 and RL2??
To limit current intake for the transistor to avoid damage
Explain the graph of base voltage vs time..
Excellent.
Thnk u so much sir
samjh me aa gya thnk
tnx sir. U're a life saver :D
can we use 555 timer
you can make astable mv using op-amp/ 555 timer / BJT / FET
thank you
Nicely explained. But i have a doubt sir when we give Vcc in starting what is the path of current/ voltage so that one of the transistor will get 0.7 V and will get on.
+Sneha Murya, may be you know similat transistors do not have identical B-E and B-C junction voltage. the transistor with lower base-emitter junction voltage should turn on first.
tq so much .......
Are u bengali
Yes.. From KUET❤
great
use a dark background
Why so hurry
Nice 👍🏻
I bet you are Bengali
Bangladeshi