Madam in the starting, I have written 6th Problem as square root of (√n^4 ....) this is Problem is convergence because Vn is (1/n^2) by p test Vn convergence and imit of (Un/Vn) not equal to zero, hence Un is also convergence By limit comparison test but inside I have changed Problem 6 i.e. (√n^2 .....) problem this is divergence because Vn is (1/n) is divergence by p test, and limit of (Un/Vn) not equal to zero, hence By limit comparison test Un is also divergence, Is it clear
@@TEAMEDUCATIONMATHEMATICS sir are you mentioning the problem sq.root(n^4 +n^2 + 1) + sq root(n^4). i found this as divergent by necessary condition lim of Un =1/2.
@@geethaaliyangal5147, yes ma'am, thank you very much for identifying, 6th one (display problem ) is divergent from the necessary condition , might be due to that reason I didn't solve the same problem. moreover, that is not in the above forms
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P=2less than 2 why we compare with 2
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sir what about the 6th problem you wrote in the beginning? it diverges rt? no need to apply L C T
Madam in the starting,
I have written 6th Problem as square root of (√n^4 ....) this is Problem is convergence
because Vn is (1/n^2)
by p test Vn convergence
and imit of (Un/Vn) not equal to zero,
hence Un is also convergence
By limit comparison test
but inside I have changed Problem 6 i.e. (√n^2 .....) problem
this is divergence because
Vn is (1/n) is divergence by p test, and limit of (Un/Vn) not equal to zero, hence
By limit comparison test Un is also divergence,
Is it clear
@ ageetha Aliyangal, I received quiry from you on LCT model 4 problem, Vn=X^n chosen because (0
@@TEAMEDUCATIONMATHEMATICS sir are you mentioning the problem sq.root(n^4 +n^2 + 1) + sq root(n^4). i found this as divergent by necessary condition lim of Un =1/2.
@@geethaaliyangal5147, yes ma'am, thank you very much for identifying, 6th one (display problem ) is divergent from the necessary condition , might be due to that reason I didn't solve the same problem. moreover, that is not in the above forms
@@TEAMEDUCATIONMATHEMATICS thank you so much sir