Since the pandemic, I have a hard time learning Physics lessons through modules. Thank you much for this lesson! Very insightful and clear. I was able to understand the reasons, parameters, and finding unknowns through derivation.
I just wanna tell here.. This is the first video I have seen in this channel with eyes full of tears longing for a good explanation... After seeing this video I just thanked God and completed all his lectures... Now I am almost clear in my concepts.. Surely he is a legend who makes any student to fall in love with physics... One thank you is not enough for this legend...Rest in peace sir🙏🏻you will be always remembered...
*Centripetal force* Those force which pulls the object towards the centre are called centripetal force F=mv²/r qvB=mv²/r qB=mv/r Velocity v=qBr/m Radius r=mv/qB Angular velocity Omega=qB/m Time period T=2πm/qB _time period is independent of r_
Sir ,In practical view charge particle enters from the side of the magnetic region then what's tragedy? But in yours figure charge particle already exists in the middle of the magnetic field region
the force acting on a charge is QVxB . The cross product between V and B means that it is V.Bsin(angle).When the charge is parallel to the magnetic field the angle will be 0 and sin(0) is 0 so there is no force acting on it
When charge moves parallel then the magnetic field is zero Because magnetic field is perpendicular and parallel give the angle =0... So that's why the magnetic field is zero
Then there would be no magnetic force acting on that electron because F = q v*b which is cross product than the angle between electron and magnetic field will be zero and sin0 = 0. Therefore no magnetic force would act on it.
i have question plz .... i have magnet for dc motor and i need to bring magnetize machine from china to recharge magnet --- my question if ( RE ) charge magnet again and again is any problem will become to magnet ... what about magnet force it will be same ??
V*B because of cross product between them that is v*B = vB sin of angle bw them . And f= Bqvsin(theta) And for getting knowledge about this formula u must read 2nd page of the chapter.
Q 1: A wire 50 cm long lying along the x axis carries a current of 0.5 A in the positive X direction through the magnetic field .In unit vector notation ,what is the magnetic force on the wire ? Magnetic field is : Q 2: An electron in a TV camera tube is moving at 7.2x10^6 m/s in a magnetic field of strength 83.0 mT. (a)without knowing the direction of field ,what can you say about the greatest and least magnitudes of the force acting on the electron due to field? (b)At one point the electron has an acceleration of magnitude 4.90x10^14 nm/s^2. What is the angle between the electron velocity and the magnetic field? Hint: Use magnitude of charge (q=1.6x10^-19 C), mass of electron : 9.11x10^-31 kg, a= F/M
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One of the best explanations you will find on the internet ❤
@Dorian Kace Nice Fake answer to yourself xD
Have u forgot physics wallah
True
Since the pandemic, I have a hard time learning Physics lessons through modules. Thank you much for this lesson! Very insightful and clear. I was able to understand the reasons, parameters, and finding unknowns through derivation.
I just wanna tell here.. This is the first video I have seen in this channel with eyes full of tears longing for a good explanation... After seeing this video I just thanked God and completed all his lectures... Now I am almost clear in my concepts.. Surely he is a legend who makes any student to fall in love with physics... One thank you is not enough for this legend...Rest in peace sir🙏🏻you will be always remembered...
He's no more????????
@@gyanendarkaur2283 yes💔
Really appreciate your teaching skills sir 🙏🏼
Best lecturer in the world.
Thank you so much♥️....your tutorials are very much helpful for students especially here in Pakistan
The Late Physics Legend ❤
Thanks sir. Your teaching style is ossam.
Ossam???
Thanks alot i finally understand
I see you every where
Thanks a lot SIR.
This is exactly what i want! thank you professor
Super sir... It is very useful to understand.... Nice teaching sir
thank you sir for this video ...I have no words to praise you sir ...you r the best physics teacher ...
Thanks a bunch Sir 😍😍 You are great🤩🤩🤟
Name of the sir
??
Very well explained sir 👏
Thank you SIR.I really appreciate that.
Sir ur explanation is clearly understood
*Centripetal force*
Those force which pulls the object towards the centre are called centripetal force
F=mv²/r
qvB=mv²/r
qB=mv/r
Velocity
v=qBr/m
Radius
r=mv/qB
Angular velocity
Omega=qB/m
Time period
T=2πm/qB
_time period is independent of r_
Great explanation 👍👌 Thank you sir
Great explanation, Thank you Sir
just nailed it . thank you sir
Sir really you are just so great, fabulous you are, hats of to you...
Wow..Thanks so much🤍
It was a great help Sir thnks u
Thnx à lot , really good teacher
😙😙love you pradeep sir
Excellent Sir
Thank you for explaining this to us Mr. Kshetrapal :)
👌👌👌grt sir
Umm
Very nice class
I want to like these videos more than once
You are a legend dude
Dude?
Nice explanation...
great work sir
I wish you were my physics teacher 😔
Super 💓
Amazing sir
Amazing!
Thankyou so much sir...
Dope Tie.
Thank you so much sir😊🙏
Good jobs sir🙏
sir please add a video for motion of a charged particle in a uniform magnetic field
Punam Gupta are Bhai ye hi to he..
hehheheheh
What about the helical motion caused by the force or velocity?
But the vedio was very good👍🏻
Amazing
Sir ,In practical view charge particle enters from the side of the magnetic region then what's tragedy?
But in yours figure charge particle already exists in the middle of the magnetic field region
Great sir
thanks alot
Nyc sir 😊😊
king of physics
What if charge is positive or negetive
Sir ji tussi grt ho
Thank you sir😊
Here q is positive charge or negetive
+
Dear ,
Why when the charge moves parallel to the magnetic field, it won't feel any force?
the force acting on a charge is QVxB . The cross product between V and B means that it is V.Bsin(angle).When the charge is parallel to the magnetic field the angle will be 0 and sin(0) is 0 so there is no force acting on it
+tarek radwan i know but why ?
When charge moves parallel then the magnetic field is zero
Because magnetic field is perpendicular and parallel give the angle =0...
So that's why the magnetic field is zero
Great sir
Excellant sir
Sir fast gives this ans.....what happen to the path of electron in magnetic field if electron entre parallel to magnetic field
Then there would be no magnetic force acting on that electron because F = q v*b which is cross product than the angle between electron and magnetic field will be zero and sin0 = 0. Therefore no magnetic force would act on it.
i have question plz .... i have magnet for dc motor and i need to bring magnetize machine from china to recharge magnet --- my question if ( RE ) charge magnet again and again is any problem will become to magnet ... what about magnet force it will be same ??
In what way we can get question from this topic sir
thankuusirrrrrr....
Sir plz av btaiye agr velocity perpendicular to magnetic field and agr perpendicular to magnetic field nhi ho ga to kya hoga
Pls upload the notes Sir..
He is dead😕
റാണി
Please note
Am so sorry 💔
@@praisefunmilayo5910 hey it's kk... I did my exam well
thank you so mauch
How you got that force equation qv*B can u explain
V*B because of cross product between them that is v*B = vB sin of angle bw them
. And f= Bqvsin(theta)
And for getting knowledge about this formula u must read 2nd page of the chapter.
Thanks sir , thanks alot
😊😊🙏👍
Q 1:
A wire 50 cm long lying along the x axis carries a current of 0.5 A in the positive X direction through the magnetic field .In unit vector notation ,what is the magnetic force on the wire ? Magnetic field is :
Q 2:
An electron in a TV camera tube is moving at 7.2x10^6 m/s in a magnetic field of strength 83.0 mT. (a)without knowing the direction of field ,what can you say about the greatest and least magnitudes of the force acting on the electron due to field?
(b)At one point the electron has an acceleration of magnitude 4.90x10^14 nm/s^2.
What is the angle between the electron velocity and the magnetic field?
Hint: Use magnitude of charge (q=1.6x10^-19 C), mass of electron : 9.11x10^-31 kg, a= F/M
رائع
Sir ka teaching thik hein but teaching thora thik karna hein
Riep sir
When he passed away😭
@@sujaneshmeragala last year January 2020 ko riep
@@mrnoob4253 covid aaa
@@sujaneshmeragala not sure about his caused of death.I also received this new 8 month later
Main bachon ko samjha samjha k thak gayi hn about magnetic field.. Unko samj hi nae aa raha😖😢
Thank u sexy legend
Th
Mai toh class12th fail
Right hand rule lagta hain lef5 hand nahi
@vishvajeet singh tu pass hogaya?
Super sir
Excellent Sir