What are...Steiner systems?
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- Опубликовано: 29 сен 2024
- Goal.
I would like to tell you a bit about my favorite theorems, ideas or concepts in mathematics and why I like them so much.
This time.
What are...Steiner systems? Or: Finite geometry and puzzles.
Disclaimer.
Nobody is perfect, and I might have said something silly. If there is any doubt, then please check the references.
Slides.
www.dtubbenhaue...
Thumbnail picture.
commons.wikime...
Material used.
www.maths.qmul....
math.ucdenver.e...
cameroncounts....
Steiner systems & block designs.
en.wikipedia.o...
mathworld.wolf...
mathworld.wolf...
mathworld.wolf...
ncatlab.org/nl...
en.wikipedia.o...
A bit of history.
www.maa.org/si...
Finite projective planes and finite geometry.
en.wikipedia.o...
en.wikipedia.o...
en.wikipedia.o...
en.wikipedia.o...
Kirkman schoolgirl problem.
en.wikipedia.o...
math.stackexch...
Witt graph.
mathworld.wolf...
www.distancere...
Applications.
en.wikipedia.o...
en.wikipedia.o...
en.wikipedia.o...
en.wikipedia.o...)
en.wikipedia.o...)
Mathematica.
demonstrations...
demonstrations...
demonstrations...
What if I add another constraint that every element should appear exactly m times?
Hmm, I have never seen discussed that anywhere...🧐 But Steiner systems are already tricky to find, so I am not sure what one could say.
Mmmmm😊
Yes, its Steiner systems are tasty ☺
First of all thanks for the quick and detailed response I will utilize your kindness and knowledge for further question. Suppose I want to construct an array (6,6,36) S
As you explained in the video, a form of determining the number of lines and points is pp have n ^ 2 + n + 1 point and line
On each line is a number of points N + 1
This means that in the case of (6,6,36) S
point and line = 6^6 + 6 + 1
Number of dots placed on each line is 7?
Thank you very much for your heart junction!
Maybe that was not clear, sorry for that! But only for certain values of t,k,n for the Steiner system S(t,k,n) you get some associated finite geometry. For t=k=6 and n=36 the solution is to simply take all 6-element subsets as your blocks, and I would not try to use any points and line picture.
i thanks for the great explanation!
I would love to get answered some questions to better understanding
Suppose I want to build a Steiner system for (3,3,9) s
For the initial 9 static of several points
For 3 mid length subgroup
For the first 3 on the left I did not understand the meaning of this entry can I get an explanation?
For the number of points (3,3,9) s to understand the number of points one has to perform for N ^ 2 + N + 1 I mean for this value N = 3 which means that there are 13 lines and points?
N + 1 means for this case there are 4 points in each line?
Hope I did not waste your time
Lots of congratulations
moshe
Ok, let me try a different formulation.
Let me modify your example to S(2,3,9), which is a bit easier to explain.
Suppose you are looking for S(t,k,n). Here n is the size of the underlying set X, in your example we take X={1,…,9}. Now take a set Y, called blocks, of subsets of X, all having size k. So in your example I could take Y consisting of 123, 456, 789, 147, 258, 369, 159, 267, 348, 168, 249 and 357. Now comes the condition given by t: every collection of t elements from X has to be contained in precisely one block. For example, if I take 37 from X, then it is contained in 357 and in no other block.
I hope that this makes it clear that there is no reason for arbitrary S(t,k,n) to exist: the condition given by t is killing most triples (t,k,n). A Steiner system S(2,3,9) for example does exist, but that is not obvious. One needs an explicit realization, e.g. via the affine plane of order 3 to see that. A Steiner system S(3,3,9) does exist, but it is rather boring: Take Y to be all 3-element subsets of X. Since t=3 this works out. In general S(t,t,n) is always rather boring.
And be careful with the numbers: if t=2, k=q+1 and n=q^2+q+1 (for example S(2,3,7), which is q=2), then the Steiner system comes from a finite projective plane with q^2+q+1 points, and each line passes through q+1 points, and each pair of distinct points lies on exactly one line. So in your example, q=3 and we get S(2,4,13) which is a finite projective plane with 13 points and each line passes through 4 points. And indeed, such a projective plane exists: en.wikipedia.org/wiki/Projective_plane#A_finite_example
I hope that helps!
I've been looking to find the actual blocks of both S(5,6,12) and S(5,8,24). I've found a lot of proofs of uniqueness and stuff like that, but I want to get a hold of the actual "Block 1: (A,B,C,D,E,F) Block 2: (A, F, G...) or whatever. Anyone know where I could find that?
They are rather complicated, I hope someone has some knowledge to share. I would be happy to know this as well!
What I would try is (potentially useless): I think you need to look at the explicit constructions (involving some Mathieu group maybe), which you might be able to do via SageMath. This side linear.ups.edu/eagts/section-24.html looks promising; maybe one can take it from there.
hey . hope u're doing great
please i have struggles to build systems S(6,6,36) for long term support succesfully
how can deal with it .
like the instructions on how ti build it .
thank u for u time
Not sure what you want. Steiner systems S(t,k,n) with t=k are trivial: just take all k-element subsets as the blocks. Is that what you are looking for?
Conway felt great pressure on him to find a new thing until he discovered Mathieu M12 Leech Lattice. Then he felt more freedom on his researches.
Well, I certainly would be happy if I would discover 1% of what Conway did.
thank you for your explanation
You are very welcome! I hope you enjoyed it.