8 years ago and this same video is still helping people understand. pretty crazy, thank you for the thorough explanation and visualization. boson's confused the crap outa me
That was a very good summary! I was studying for my finals and I was looking for a review. I tried 3 other videos before I found this one. This one was the best because it explained everything without shortcuts and had plenty of visual aids.
After studying subnetting for the 4th time, I finally understand what direction to go when calculating subnets and hosts. I finally understand we start with 2^1 for both subnets and hosts but use 2^0 when converting the additional 1s into subnet masks notation. Thank you so very much, Mr. Patrick. Such a phenomenal explanation!
Wow.this is the best video ever.it took me the whole semester to know this buh thanks to this video I now understand everything. By this you get my like and my subscription. Thank you
Thanks Patrick. Yes I do understand that it has to do with combinations. But I don't understand how you can have a zero and a one as if you have one switch it can be on or off. So 2 combinations. I thought two would be the minimum but it isn't.
hello sir! What about if i'm using class C Address and I need: at least 4 subnet, and each subnet i need at lease 120 IP address. Please help me to figure out for this.
What to do if i run into a problem where the number of host that i require is bigger than the host section left after borrowing the bits? Lets say i have 11 subnets, and i need 20 host per subnet. How do i solve this?
Thanks. I understand binary well, 0,1,2,4,8 etc adding them equals 255. 256 possibilities (as you include the zero). 0 is off. 1 is on. 2 is 1 switch with two combinations: either on or off. But I still don't understand why you start at 2. Is it because the computer is on, so 1 has been used and the next number is 2? Like when you normally count bits is starts with 1.
No, it only has to do with the possible combinations. In one bit, there are two possible combinations - 0 or 1. In two bits, there are four possible combinations - 00, 01, 10, or 11. In three bits, there are 8 possible combinations - 000, 001, 010, 011, 100, 101, 110, and 111. That is why we count 2, 4, 8, etc when counting the number of subnets or hosts. Sometimes this is written as 2^n, where n represents the bits. So... you start at two because in the first bit, there are two possible combinations. I don't know what you mean by 'because the computer is on'. You are on the right track with 256 possibilities - 2^8 = 256 . If you cut that number in half, 2^7=128, 2^6=64, 2^5=32, 2^4=16, 2^3=8, 2^2=4, and 2^1=2.
I think you say "the computer is on" because you think that the computer understands things in decimal. Computers do everything in binary, us humans don't. He started at two because starting at two gives you two possible outcomes: 1 or 0. Starting at 1 would just give you one outcome. The way I see it is that computers understand things is a sea of combinations only using 1 and 0.
You're right, I do! When we count the number of subnets or hosts per subnet, we are counting the possible *combinations*. Each bit can have two combinations - 0 and 1. For example, 3 bits represent 8 combinations (2^3 = 8) When we count in binary, we are counting the *value* of the bit. In this case, 0 equals zero, and 1 equals one. For example, 101 equals 5 (4 + 1 = 5).
When you're borrowing at 5:05 ish - you already got past 70 when you added the 64 bit. 32+16+8+4+2 is 62, so that's too low. Going to the next number is 64+32+16+8+4+2 is 126, so you're already past 70. So why not 00100010 which is 64+8? 72
64 is the total amount of possibilities, so you can't add 8 to it because those 8 combinations are already included in the 64. Meaning you will need 1 more bit to get the amount of possibilities you need.
8 years ago and this same video is still helping people understand. pretty crazy, thank you for the thorough explanation and visualization. boson's confused the crap outa me
2024 here and you're making it quite fun. It's not too difficult but not too easy either! It's like a little puzzle that won't break your brain. :)
Thank you Patrick, been searching for a decent video for some time. Finally understand with your one! :)
That was a very good summary! I was studying for my finals and I was looking for a review. I tried 3 other videos before I found this one. This one was the best because it explained everything without shortcuts and had plenty of visual aids.
Finally understand the idea of borrowed bits. Thank you.
this video is old, but still the only video that helped me understand borrowing bits. Thank you!!
I am grateful for this wonderful video. U taught me subnetting in less than 8 minutes. Thank you so much 😍
wow I finally understand how to borrow bits with ease, thank you!!!!!
Thanks for this. It made it very easy to understand when writing it out. This will be very helpful to me.
After studying subnetting for the 4th time, I finally understand what direction to go when calculating subnets and hosts. I finally understand we start with 2^1 for both subnets and hosts but use 2^0 when converting the additional 1s into subnet masks notation. Thank you so very much, Mr. Patrick. Such a phenomenal explanation!
alhamdullilah :)
this literally saved me THANKYOU PATRICK
Good lecture so far.. easy to understand .
I finally understand borrowing bits lmao thank you.
This is really good explanation.
Thank you so much🔥🔥
I finally understand this concept
Excellent instruction Patrick! Thank you
Glad it was helpful!
Wow.this is the best video ever.it took me the whole semester to know this buh thanks to this video I now understand everything.
By this you get my like and my subscription. Thank you
Thank you. Seriously. Thank you. I can sleep 2nite. -U10
so much better then my teacher taught me...thanks a lot
thanks. i've been trying to figure this one out.
thanks alot man this got me out of a jam
wow.. faham akhirnya.. thank you
Great explanation thank you
Thank you for the help!
THANK YOU! I finally get it
Wonderfull job sir
Thank You very much
Thank you!
you are a legend.
really helpful :D
Thank you!!
Thanks a lot 💓💓
Thank you.
THANK YOU.
Thanks Patrick. Yes I do understand that it has to do with combinations. But I don't understand how you can have a zero and a one as if you have one switch it can be on or off. So 2 combinations. I thought two would be the minimum but it isn't.
lets go. thanks patrick
This is my light bulb moment video thank you
Glad it helped!
thanks
hello sir! What about if i'm using class C Address and I need:
at least 4 subnet, and each subnet i need at lease 120 IP address.
Please help me to figure out for this.
So would each individual subnet now have a /23?
What to do if i run into a problem where the number of host that i require is bigger than the host section left after borrowing the bits?
Lets say i have 11 subnets, and i need 20 host per subnet. How do i solve this?
Many thanks, may I ask, why does borrowing 1 bit double the subnets?
Where did you get the 254 from? I am utterly confused on this number.
Thanks. I understand binary well, 0,1,2,4,8 etc adding them equals 255. 256 possibilities (as you include the zero). 0 is off. 1 is on. 2 is 1 switch with two combinations: either on or off. But I still don't understand why you start at 2. Is it because the computer is on, so 1 has been used and the next number is 2? Like when you normally count bits is starts with 1.
No, it only has to do with the possible combinations. In one bit, there are two possible combinations - 0 or 1. In two bits, there are four possible combinations - 00, 01, 10, or 11. In three bits, there are 8 possible combinations - 000, 001, 010, 011, 100, 101, 110, and 111. That is why we count 2, 4, 8, etc when counting the number of subnets or hosts.
Sometimes this is written as 2^n, where n represents the bits.
So... you start at two because in the first bit, there are two possible combinations. I don't know what you mean by 'because the computer is on'. You are on the right track with 256 possibilities - 2^8 = 256 . If you cut that number in half, 2^7=128, 2^6=64, 2^5=32, 2^4=16, 2^3=8, 2^2=4, and 2^1=2.
I think you say "the computer is on" because you think that the computer understands things in decimal. Computers do everything in binary, us humans don't. He started at two because starting at two gives you two possible outcomes: 1 or 0. Starting at 1 would just give you one outcome.
The way I see it is that computers understand things is a sea of combinations only using 1 and 0.
I thought Classes like A,B,C didn't have any relevance in subnetting because its outdated and we have CIDR.
When he counts for the subnet he starts from 2. I thought binary started from 1. Anyone know why? Thank you
You're right, I do! When we count the number of subnets or hosts per subnet, we are counting the possible *combinations*. Each bit can have two combinations - 0 and 1. For example, 3 bits represent 8 combinations (2^3 = 8)
When we count in binary, we are counting the *value* of the bit. In this case, 0 equals zero, and 1 equals one. For example, 101 equals 5 (4 + 1 = 5).
@@PatrickHornung I was doing the same thing as r m. Thank you for your video. It really helped me out.
When you're borrowing at 5:05 ish - you already got past 70 when you added the 64 bit. 32+16+8+4+2 is 62, so that's too low. Going to the next number is 64+32+16+8+4+2 is 126, so you're already past 70. So why not 00100010 which is 64+8? 72
64 is the total amount of possibilities, so you can't add 8 to it because those 8 combinations are already included in the 64. Meaning you will need 1 more bit to get the amount of possibilities you need.
so u borrowed one bit?
He borrowed 7 bits in order to have 128 subnets :)
Class A is 0- 126 not 127.. 127 is a loopback
Technically, the classes are defined by the initial bits in the address. 127 is loopback, and happens to be part of Class A.
Class A 1 - 126
APIPA 127
Class B 128 - 191
Class C 192 - 223
I think Class A begins in 0-127? Am i wrong? What is APIPA?