An Exponential Log Equation
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- Опубликовано: 26 июн 2024
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I like that what matters the most in this channel is the way you get to the answer, rather than the answer itself.
For log based 10 usually is used lg.
For natural log - ln.
Don't know, why English speakers mathematicians don't use this designation, but in Russian school we always use
lg for 10,
ln for e
and log for other bases, and we don't have problems with discrepancies.
x^(log3) + x^(log5) = 8
x = 10^u
10^(ulog3) + 10^(ulog5) = 8
3^u + 5^u = 8 => u = 1
=> *x = 10*
3+5=8
x = 10
I solved it using my foot 😊 by just interchanging the logarithmic argument with the Exponential base after that I compared which one of my leg smells better 😅 then I got 10 as the final answer
Caution:- Don't try this at school 😊
I have gotten too used to log being used for base e. In some situations it's the accepted convention. I'm not sure whether it's a Newton's Method or if you could rig up a Lambert W if the numbers were less convenient, such as if the RHS were 9.
I got x=10 right away.
it is (hroot^log_3(5)(8))^(1/log3)
x=10
I could see the answer (10) in just one second but your solution is satisfying
Yup, I see it, too.
spoiler: there are no other complex solutions
That's assuming you're restricted to the range (0,2π) for the angle, there's infinitely many solutions otherwise (one of them is roughly 25.3023 * e^(9.7167i) for example)