NBHM 2024 Complete Solution PART 1

[@Aingmathematics]

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[@funscience905]

Thanks sir ji , aapka explanation bahut achha rhta , pls next part bhi RUclips par upload karna

[@riyapramanik8385]

Explanation bahut achha tha sirr

[@anshumanagrawal346]

For the first question, the existence and uniqueness theorem only ensures uniqueness in some interval around 0. There is no guarantee that the interval is big enough that it contains 1.

[@Aingmathematics]

By using existence and uniqueness one can prove for such ode maximal interval of existence is R

[@DEEPAKKUMAR-tc6sz]

Sir, non-identical value permutations ke nichle m hoga na

[@PragatiiThisSIDE]

❤️👍🏻

[@Harinarayan-m7u]

❤

[@niveditasingh8906]

Ur explanation 👍....too good

[@rohitpathak5055]

Where is the 2nd part?

[@ChampaRai-u5d]

👍👍

[@GopikarMenon]

Thank you for such explanatory solutions❤