Aaron's BJT videos are great. It takes him 25 minutes to explain various topics, I spend hours offline to understand the contents. After putting that offline effort in, I watch the video again.
Excellent course, thank you! I am just a little confused by the small signal model you use. I was taught the hybrid pi model and I was pretty happy with it. Why do you prefer that one instead?
@12:00 shouldn't that be 1.2k // 1M ? Since the collector is tied at one of its ends to a DC source, it's therefore connected between the collector and an AC ground making it in parallel with the one megohm load, right?
This would be correct only if the transistor was modelled as a current source. 1.2 kΩ is output impedance/resistance. In current sources, it's wired in paralel. Considering he modelled the transistor with the voltage source, according to the Thevenin's theorem, it should be wired in series. Hope this clears things out. 👍🏻
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Aaron's BJT videos are great. It takes him 25 minutes to explain various topics, I spend hours offline to understand the contents. After putting that offline effort in, I watch the video again.
Brilliantly explained! Have never seen this specific calculation before and it’s very intuitive to understand with this lesson 🙏
Thank you professor
thank you for sharing
Amazing video
Excellent course, thank you! I am just a little confused by the small signal model you use. I was taught the hybrid pi model and I was pretty happy with it. Why do you prefer that one instead?
What's the difference between the gain you write next to the voltsge source in the small-signal model and the overall gain of the circuit?
Thank you 😊
Waiting for the next video
Can you make a series on MOSFET as well
Why is re calculated as 26mV/3.3mA ? How does kT/q appear here?
By definition. It’s the quotient of thermal voltage divided by emitter current.
thanks
@12:00 shouldn't that be 1.2k // 1M ? Since the collector is tied at one of its ends to a DC source, it's therefore connected between the collector and an AC ground making it in parallel with the one megohm load, right?
This would be correct only if the transistor was modelled as a current source. 1.2 kΩ is output impedance/resistance. In current sources, it's wired in paralel. Considering he modelled the transistor with the voltage source, according to the Thevenin's theorem, it should be wired in series. Hope this clears things out. 👍🏻
@@mihajlopetkovic2003 Makes sense indeed. Thanks.
I’m guessing this does not work for saturation?
и что с этим делать?
Why do you call R as "arse"
😂😂😂 ... It's "R sub E", not "arse E" ...🙋🏻♂️🙋🏻♂️
You went too fast ! Why ?