HashMap or Dictionary in python | PART - 22 | DSA in python in telugu | Engineering Animuthyam

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  • Опубликовано: 29 сен 2024
  • Free python dsa course in Telugu | Part - q | Engineering Animuthyam
    Free python dsa course in Telugu
    Website link:
    vigneshreddyjulakanti.in/python
    Insta:
    Engineering Animuthyam
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    #nit #jee #eamcet #dsa

Комментарии • 8

  • @peddintiganesh-g6u
    @peddintiganesh-g6u 6 дней назад +4

    chala slow ga velthunnamm compare to java so it is better do some long videos bro...
    Python is easy compare to java so you can give more concepts and problem in single video and provide @DSA sheet for preparation

  • @61mahesh16
    @61mahesh16 6 дней назад

    Anna notes upload cheyyava
    And classes kuda regular ga upload cheyavaa final year students ki chala help avuthundhiii......

  • @4750Ahamed
    @4750Ahamed 5 дней назад

    # l=[2,3,4,2,1,1,1,2,4]
    # n=len(l)
    # dict={}
    # count=0
    # for i in range(n):
    # if l[i] not in dict:
    # dict[l[i]]=1
    # else:
    # dict[l[i]]+=1
    # print(dict)
    OR
    from collections import Counter
    l=[2,1,2,1,3,4,1,3,3,4]
    print(Counter(l))

  • @BALIGARISURENDRAREDDY2021-CSEU
    @BALIGARISURENDRAREDDY2021-CSEU 6 дней назад

    list1 = [1,5,8,0,1,8,1,5,1]
    dici = {}
    for i in range(len(list1)):
    if list1[i] not in dici:
    dici[list1[i]] = 1
    else:
    dici[list1[i]] = dici[list1[i]] + 1
    print(dici)

  • @pavanrock4368
    @pavanrock4368 6 дней назад

    Chala baga chepthunnaru bro👏

  • @Maheshkrishna-p3b
    @Maheshkrishna-p3b 6 дней назад

    li = [1,5,8,0,1,8,1,5,1,5,8,5]
    l2 =[]
    for i in range(len(li)):
    count = 1
    if li[i] in l2:
    continue
    for j in range(i+1,len(li)):
    if li[i]== li[j]:
    count +=1
    l2.append(li[i])
    print(li[i] ,'=',count)
    anna okasari chudu ee code to count no of times repeated a num in the list brutebforce vastundhi ni valla thank you anna regular ga classes upload chey anna..........