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Factorial Algebra Problem | How to solve (m-5)!=3!x5!x7! | Math Olympiad | Find m=?

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  • Опубликовано: 11 июл 2024
  • Factorial Algebra Problem | How to solve (m-5)!=3!x5!x7! | Math Olympiad | Find m=?
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Комментарии • 17

  • @MalikHamidov
    @MalikHamidov Месяц назад +3

    Very good question 👍

  • @ToanPham-wr7xe
    @ToanPham-wr7xe Месяц назад +1

    😮

  • @WorldwideBibleClass-qr9jk
    @WorldwideBibleClass-qr9jk Месяц назад +2

    Nice video man. Keep it up

  • @gnanadesikansenthilnathan6750
    @gnanadesikansenthilnathan6750 Месяц назад +1

    Got it . Very easy. 😊😊😊

  • @BruceLee-io9by
    @BruceLee-io9by Месяц назад +2

    Very interesting and instructive video. Dear Professor, can you make others with factorial calculation?

  • @vacuumcarexpo
    @vacuumcarexpo Месяц назад +2

    If 3!×5!×7! is a factorial of a certain number, the number is necessarily larger than 7 and smaller than 11 that is a prime next to 7. And the factorial divided by 7! necessarily includes a prime factor 5. Therefore, m-5=10 is necessary. What we have to do is confirming the sufficiency.

  • @schlingel0017
    @schlingel0017 Месяц назад +1

    just write all factors of right side and try to get as much consecutive numbers using those factors. you will get all numbers until 10. So right side is 10!. m = 15.

  • @boguslawszostak1784
    @boguslawszostak1784 Месяц назад +1

    No problemat all
    3!5!7!=n!
    there is no 11 factor so n

  • @walterwen2975
    @walterwen2975 25 дней назад +1

    Factorial Algebra Problem: (m - 5)! = (3!)(5!)(7!); m = ?
    (m - 5)! = (3!)(5!)(7!) = (6)(120)(7!) = 720(7!) = (10)(9)(8)(7!) = 10!
    m - 5 = 10; m = 15