Hello Amr, You can use Excel, the software accompanying the potentiostat, or write your own script. We have illustrations on how to do it in Excel in this video: ruclips.net/video/Oa0eVt3GXSY/видео.html&ab_channel=EChemChannel Alternatively, here is a way to develop your own script: ruclips.net/video/0qMCvQeHurY/видео.html&ab_channel=EChemChannel and ruclips.net/video/4RlvEayn2pw/видео.html&ab_channel=EChemChannel
Hi Bruno, usually you need to consider the potential range so that your electrode and electrolyte do not experience unwanted side reactions. For electrodes, that could be conversion reactions at very low potentials. For electrolytes, it could be the breakdown of the solvents, like HER and OER in aqueous systems.
@@EChem_Channel ah! All right! Thank you for your answer! I have just started work with supercapacitors and, unfortunately, I'm a little lost in this basic experimental principles! Do you have any reference that could help me with this? (If I'm not asking too much)
Voltage between the cathode and anode is an important parameter in energy calculation. In three electrode systems, you are testing one electrode against the reference electrode, so you know it's electrochemical potential, but you can't calculate the voltage against its counterpart.
Hi there@@8421809859, it is the fundamental definition of energy. Work is defined as moving a charge across a potential difference (voltage). In a three-electrode system (let's say you are testing a cathode material), you don't know what the actual anode you are going to use. Therefore, energy will be different if you use graphite or lithium. In three electrode systems, you know the reference point. With a reference electrode, you know a potential. It's like knowing an altitude in terms of height. You won't be able to calculate the gravitational energy unless you know how far the sea level is from the center of the earth. It's just how energy is defined.
This problem came up in my work and this video helped me to perform the important job that was expected of me. I am so relieved! Thank you!
Glad it helped!
Thank you, your video helped a lot.
Thank you!
Thank you for the great effort.
My question is, how to perform the integral of (iVdt) and which software you usually used?
Hello Amr,
You can use Excel, the software accompanying the potentiostat, or write your own script. We have illustrations on how to do it in Excel in this video: ruclips.net/video/Oa0eVt3GXSY/видео.html&ab_channel=EChemChannel
Alternatively, here is a way to develop your own script: ruclips.net/video/0qMCvQeHurY/видео.html&ab_channel=EChemChannel and ruclips.net/video/4RlvEayn2pw/видео.html&ab_channel=EChemChannel
Hi .... it was a very informative tutorial. I want to know how to calculate the Columbic efficiency from CV and CD curves?
CE=discharge capacity/charge capacity
Is it like CE = Discharge time / Charging time ??
Hello Dr. Wang, what I have to consider when choosing the potential window for a three electrode cell experiment?
Hi Bruno, usually you need to consider the potential range so that your electrode and electrolyte do not experience unwanted side reactions. For electrodes, that could be conversion reactions at very low potentials. For electrolytes, it could be the breakdown of the solvents, like HER and OER in aqueous systems.
@@EChem_Channel ah! All right! Thank you for your answer! I have just started work with supercapacitors and, unfortunately, I'm a little lost in this basic experimental principles! Do you have any reference that could help me with this? (If I'm not asking too much)
@@brunorossi2831 You may find this guideline paper helpful: onlinelibrary.wiley.com/doi/abs/10.1002/aenm.201902007
coulumbic efficiency is for all cycles?
You have to calculate CE of individual cycles
In the end of the video, why is the S iv dt integral divided by M? Isn't the unit Joule/kg now?
Yes, Franklin. It is the equation for gravimetric energy density.
What is the constant 1/2 in the E = 1/2*CV^2
It comes from integration of the curve. If it's a straight line, imagine calculating the area of a triangle.
what is M
Total mass of both positive and negative electrodes.
Can i have your email
why can't we calculate energy density using 3 electrode?
Voltage between the cathode and anode is an important parameter in energy calculation. In three electrode systems, you are testing one electrode against the reference electrode, so you know it's electrochemical potential, but you can't calculate the voltage against its counterpart.
thank you@@EChem_Channel for the reply. could you please cite any reference for your statement.
Hi there@@8421809859, it is the fundamental definition of energy. Work is defined as moving a charge across a potential difference (voltage). In a three-electrode system (let's say you are testing a cathode material), you don't know what the actual anode you are going to use. Therefore, energy will be different if you use graphite or lithium. In three electrode systems, you know the reference point. With a reference electrode, you know a potential. It's like knowing an altitude in terms of height. You won't be able to calculate the gravitational energy unless you know how far the sea level is from the center of the earth. It's just how energy is defined.