sir, in the definition it is said that A and B should not be equal to zero but in 48:07 you have solves a question where you have written the value of b = 0, could you please explain how it is true
It was in the form LEOV and,if you've noticed in your ncert; if there is any equation of the type ax+b=0, we can express it as ax+0.y+b=0 Here, in the question • x= -3 If we try to solve this problem, it's x+3=0 (which is in the form ax+b=0) So, if we just apply this (ax+0.y+b=0) to the Equation, We'll get x+0.y+3=0 Where, a=1 b=0 c=3
Kamal sir is good but I'm just missing ritik sir his tecnic is excellent by his tecnic weak student like me in maths can be master😢 please PW we need ritik sir
Thnx sir for such a productive vid, frm this chp so many case based questions come in our school exms so please make a video on case based questions as well its a humble request
Those are the form LEOV and,if you've noticed in your ncert; if there is any equation of the type ax+b=0, we can express it as ax+0.y+b=0 Here, in the question • x= -4 If we try to solve this problem, it's x+4=0 (which is in the form ax+b=0) So, if we just apply this (ax+0.y+b=0) to the Equation, We'll get x+0.y+4=0 Where, a=1 b=0 c=4 Same with the next one!! • 5y=4 5y-4=0 Then, apply (0.x+ay+b=0) to the Equation, We'll get 0.x+5y-4=0 Where, a=0 b=5 c=-4
It was in the form LEOV and,if you've noticed in your ncert; if there is any equation of the type ax+b=0, we can express it as ax+0.y+b=0 Here, in the question • x= -3 If we try to solve this problem, it's x+3=0 (which is in the form ax+b=0) So, if we just apply this (ax+0.y+b=0) to the Equation, We'll get x+0.y+3=0 Where, a=1 b=0 c=3
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Doubt : IN LETV : ax + by +c =0, a, b is not equal to zero but in converting LEOV TO LETV they become zero
thank you sir
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sir, in the definition it is said that A and B should not be equal to zero but in 48:07 you have solves a question where you have written the value of b = 0, could you please explain how it is true
It says that a And b both should not be 0 ,it's about together because it both will be than there would be no variable but one of them can be
It was in the form LEOV and,if you've noticed in your ncert; if there is any equation of the type ax+b=0, we can express it as ax+0.y+b=0
Here, in the question
• x= -3
If we try to solve this problem, it's
x+3=0 (which is in the form ax+b=0)
So, if we just apply this (ax+0.y+b=0) to the Equation,
We'll get x+0.y+3=0
Where,
a=1
b=0
c=3
You teaching very well sir thank you so much 😊
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Sir lekin ax+by+c=0 me a,b is not 0 tha n to aap x ko 0 se multiply kr ke 0 constant kaise la diye😢
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Kamal sir is good but I'm just missing ritik sir his tecnic is excellent by his tecnic weak student like me in maths can be master😢 please PW we need ritik sir
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46:02 #basics clear
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Thnx sir for such a productive vid, frm this chp so many case based questions come in our school exms so please make a video on case based questions as well its a humble request
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Bhaiya question no 1 ke c mai aapne b ka coefficient 0 le liya and same for d as well par apne definition mai kaha tha ki a , b should not be 0
@gamerb0y-zq9gs ya I agree with that but it changes the fundamental rule
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•If a and b not equal to 0,then •(x= -4), •(5y=4) in these given example why is it possible?? Sir please answer me .....
Those are the form LEOV and,if you've noticed in your ncert; if there is any equation of the type ax+b=0, we can express it as ax+0.y+b=0
Here, in the question
• x= -4
If we try to solve this problem, it's
x+4=0 (which is in the form ax+b=0)
So, if we just apply this (ax+0.y+b=0) to the Equation,
We'll get x+0.y+4=0
Where,
a=1
b=0
c=4
Same with the next one!!
• 5y=4
5y-4=0
Then, apply (0.x+ay+b=0) to the Equation,
We'll get 0.x+5y-4=0
Where,
a=0
b=5
c=-4
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1:35:56
Sir ne kaha ki a and b should not equal to zero but in x=(-3) mein sir ka ans tha 1x + 0y + 3=0 ??? Koi mujhe samjaygaa kyuuu please
It was in the form LEOV and,if you've noticed in your ncert; if there is any equation of the type ax+b=0, we can express it as ax+0.y+b=0
Here, in the question
• x= -3
If we try to solve this problem, it's
x+3=0 (which is in the form ax+b=0)
So, if we just apply this (ax+0.y+b=0) to the Equation,
We'll get x+0.y+3=0
Where,
a=1
b=0
c=3
Thanks
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sir we can take y=3 and c=0
We dont take c and we can take any value
43:01 but ek clip m to sir ne bola tha k "b" ie not equal to zero......
1:33:02 ok sir
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42:59 sir! a ≠ 0, b ≠ 0 aisa hota h n... To fir a = 1 and b = 0 kaise?? Mujhe smjh ni aaya... 🤔🙁😕
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Sir may i know if a is not equal to 0 so why you putting in the equation ??
In question no . 1 part 3 and 4
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Q1 (iii) a≠0, b≠0and c≠0 butt....
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ax+by+c=0. a,b are not equal to 0
Very good
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