Thank you very much for providing such a helpful example to the Galerkin Method. I feel other people really over-complicate this but you have explained it very well!
Thanks. I was just wondering why did you truncate the last two terms of R= - 6a1x + a2(2 - 6x) - 28 - 3x^2 (in 25.50 minutes to the end of the video) when calculating with four co-efficient(a1,a2,a3,a4). Why you did not consider - 28 - 3x^2 in final gelerkin equation?
If you integrate twice, and introduce the boundary conditions: y(0) =0 and y(1)=0 to eliminate the two constants of integration, you will arrive at that equation that also contains the term you are asking about.
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I hate some teachers... 30 min on yt are more useful than a full 2h bs course in person.. Thank you!
woowww, really fantastic explanation, I have exam, I searched a lot, This video was the best, thanks for sharing that, really helped me
Thank you very much for providing such a helpful example to the Galerkin Method. I feel other people really over-complicate this but you have explained it very well!
Glad it was helpful!
I'm inspired that an African is explaining this complicated stuff to me big up brother
the intro is like metal shavings running through my ear drums at 56 m/s
Very well explained, thank you
Great video
Great Content
Wowwww! 10K views. Way to go Big Bro! And you hit over 1k subscribers too.
From a fellow Nigerian thank you
Thank you! Everything is clear.
Can anyone give me the book name of galerkin method which is mention in this tutorial???
thanks well understood, make more of this pls.
Yeah. Thanks. More will come in good time
Very nice
Thanks. I was just wondering why did you truncate the last two terms of R= - 6a1x + a2(2 - 6x) - 28 - 3x^2 (in 25.50 minutes to the end of the video) when calculating with four co-efficient(a1,a2,a3,a4). Why you did not consider - 28 - 3x^2 in final gelerkin equation?
Thank you very clear . could you provide example for 2 d ?
Brooooo, you are a G
Many thanks, very helpful !! But in the end ... where does the value -57/4 x come from ? ( In the end of the exact equation )
If you integrate twice, and introduce the boundary conditions: y(0) =0 and y(1)=0 to eliminate the two constants of integration, you will arrive at that equation that also contains the term you are asking about.
thx !!!!
thanks! I'm grateful for this sharing of knowledge! (just a small note: the audio is a bit noisy and low quality, seems to be in a crowded bar haha)
Hahahaha
first thanks
second why do you start your video like rap music videos from 90s😂
😂. That is my first video ever. I was still learning how to make videos then.