ANSWER EXPLAINED BELOW HERE: Q: Prove that if there is a vowel on the front, there will be an even number on the back A: Check the back of A and see if it’s true. Then check the back of the 7 and see if it’s true. Done! If you check the D you are wasting time because the question doesn’t ask about non-vowels at all. If you check the back of the 4 then you won’t learn anything new. If it’s a vowel then you didn’t learn any more than turning the A. And it it’s not a vowel it doesn’t matter.
There is also nothing in the problem as stated, to say that all cards have a letter on one side and a number on the other. This brings the D back into play if we assume that front and back are interchangeable, as it could have a vowel on the other side, which would therefore, not have an even number on its reverse.
We care about D, because if there is a vowel on the other side, then the theory is disproven. As you will have vowel card with something other than an even number on the back. In this case, a “D”. There is no constraint stated that there must be letters on one side and numbers on the other.
I’m not very good at puzzles, but I got this one immediately. Easy way to explain it is to say that in order to prove something you also have to give it a chance to be disproven.
It seems like you also need to stipulate that each card has a letter on one side and a number on the other. Otherwise, if you flipped the "D" card and it had an "E" (vowel) on the other side, this would disprove the premise.
@@WesBarker Your pinned response doesn't deal with issue @garyjenkins pointed out. I think you maybe missed what they are trying to state. Typically this riddle has the stipulation that there is a letter on one side of each card and a number on the other side, so you can ignore the possibility of the "D" card having a vowel on the other side. If it's possible that there is a vowel on the other side of the "D" card, then you'd have to flip any card that doesn't show an even number (so three cards in this case) to check the required condition. A statement ("If a vowel is on one side, then an even number is on the other.") is equivalent to its contrapositive ("If an even number is not on one side, then a vowel is not on the other.") You flip the A to check the statement, and you flip the 7 to check the contrapositive.
Good riddle but you should redo it with all the needed info. You need a conditional statement of that all the cards have letters on one side which is considered the "front" and numbers on the reverse which is the "back". Otherwise 1 could be a correct answer. I assumed we were shown the front of all the cards. Which would just be flipping over the "A". Then saying if you "OBSERVE someone drinking an alcoholic beverage" thier age must be over 21 kinda reninforced to me that we were looking at the fronts of the cards cause i was only "observing" 1 person with an alcoholic beverage.
Yeah. I already understood the riddle. I don't think you understand my point that there is missing information in the explationation of the riddle. Reread my point.
I got it but I started on the same track as Wes before realising that the 4 was irrelevant and that the 7 was indeed relevant. Might have been about 15 seconds once i understood the question. EDIT: however, there is a little bit of information missing from the problem as stated. It could be argued that only the visible side of the cards counts as the front, so you only need to turn the A. Alternatively, it hasn't been stated that every letter has a number on its back or vice versa, so, going with the assumption that either side may be considered front or back, the D could have a vowel on the other side which would not have an even number on its back and would, therefore, need to be checked (although the D is an even-numbered letter, so, perhaps that counts).
@@WesBarker the riddle as written creates a heuristic error. the word front basically means facing forward, therefore only the paper with the A would need to be checked (blank paper has no orientation). If you had written on Playing cards (you do have a deck laying around somewhere, right) it has a defined "front" and "back'
1. State that each card has a letter and a number, one on each side. 2. Ask how to 'find out" if the statement is true, in the fewest flips. (prove OR disprove)
actually you have to flip also the D card. The problem does not assure you that alla cards are letter on one side and number on the other. So it is possible that there is a vowel letter behind the D card and you have to check that it is not the case otherwise you would have a vowel with a D on the other side that is actually non an even number.
I said that each related to the pattern of how many letter away are then from the previous vowel/consonant. (1 for A cuz there’s nothing before it, 4 for E cuz it’s 4 letters after A, or 1 for D cuz it’s 1 letter away from C) therefore u don’t need to flip any. Then she said the alcohol and I lost it
Yeah -- i felt like we needed more information to prove anything. If you turn the 7 over and it doesnt have a vowel, it doesnt prove that all odd numbers dont have a vowel. So the premise still could hold that an odd number could have a vowel. Maybe the question just needed to be worded differently....or that the universe only consists of these 4 cards....which makes the question phrasing needlessly unclear....or is that the point? I love your riddles! This one just hasnt been able to break through my thick skull for some reason.
Sorry, but as the question is posed, that answer is incorrect. That 4 could have a 9 or some scribbbles on the opposite side or a constant. It could even be blank. Proving something isn't, doesn't mean something else is. That is a common fallacy used in illogical arguments. The question was not "do only vowels have even numbers on the reverse side."
Paused at 1:37-- I don't understand the instructions at all. On the front of what? On the back of what? The opposite side of the paper? The sequence of letters and numbers? Finished the video: I still don't get it. It seems like the instructions are missing pertinent information.
So.... anyone else not catch the "flip" part and thought she meant to rearrange them to make it true? Because then the answer is zero. "A" is already at the front and sEVEN at the back. Lol. I look for trick questions too much. She even made it clear that it was a LOGIC puzzle.
I don't understand this at all, and the explanation made it even more confusing. I don't understand the statement, "We didn't say anything about consonants at all," and then, the "D" and "4" cards are become "irrelevant.' How does the "4" card equate to a consonant?
The 4 was irrelevant because the statement said a vowel has an even number. Not that an even number has a vowel. Therefore consonants and even numbers on the front are irrelevant.
This riddle kind of assumes the backs are Even/Vowels. If the A or 4 had a 5 or D on the back, wes would be right. So there's no way of really solving this properly unless you already know what's behind the cards which sort of the defeats the purpose of a riddle
If the A had a 5 behind it, you've disproven it. But if the 4 had a D behind it, the statement still stands because it says every vowel has an even number behind it, not that every even number has a vowel behind it. So basically every vowel has an even number but not every even number has a vowel
@WesBarker The rules of the "game" was to turn over the vowels. 4 & 7 are numbers. And D is not a vowel. I think people who not only logical, but literal as well won't be able to get this one. When she added the changes my thought process was the same as yours. So I will take a loss and admit that I am not as smart as your wife.
Given the original requirement flipping only the card with the number 4 is enough to prove that if there is a vowel on the front, there is an even number on the back, because it's never stated that odd numbers can't have a vowel on the back. Therefor, A could have been odd and flipping it would have proven nothing. For the solution the correct wording should have been "only vowels can have even number on the back"
Damian , you have misunderstood and/or misread the premise we are being asked to prove. We are to prove “if there is a Vowel on the front, there is an Even number on the back. Thus, your statement that “it is never stated that odd numbers can’t have vowels” is what the quiz is actually asking us to prove. Thus, we have to flip “A”. If it has even number the premise of the quiz holds true so far. If it was odd, then premise is wrong and quiz ends. But we also have to flip 7, because for premise to hold 7 can’t have a vowel. Your statement that you only have to flip 4 is wrong/backwards. The premise did not say that consonants cannot have even numbers; premise says that vowels have to have even numbers.
I have never seen a riddle more poorly explained than this one. I did not even understand the question until I have seen the entire solution. A proper explanation should mention that the question is about the back of the cards and not the back of the 4-digit string.
It's just the way you think, inductive or perspective. If you start thinking with a theory and then you go through the process to find the proofs or on the contrary you arrived at a theory using proofs and observations. So the statement "if there's a vowel on a side there's a even number on the back" DOESN'T correspond to the different statement "if there's an even number on a side there's a vowel on the back" because are two completely different situations without a logic correlation (which is the right answer to the dilemma). Starting from this assumpion you can solve their riddle 😉
@@biancaenera2500I think op meant the front seems like "AD" and the back seems like "47" so it seems like it suggest A corresponds to 4 and D corresponds to 7. I initially thought the same
ANSWER EXPLAINED BELOW HERE:
Q: Prove that if there is a vowel on the front, there will be an even number on the back
A: Check the back of A and see if it’s true. Then check the back of the 7 and see if it’s true. Done!
If you check the D you are wasting time because the question doesn’t ask about non-vowels at all.
If you check the back of the 4 then you won’t learn anything new. If it’s a vowel then you didn’t learn any more than turning the A. And it it’s not a vowel it doesn’t matter.
🙏🤘
If front means the side showing and back means the side not showing then you don't have to check the back of 7 because that's irrelevant, surely?
There is also nothing in the problem as stated, to say that all cards have a letter on one side and a number on the other. This brings the D back into play if we assume that front and back are interchangeable, as it could have a vowel on the other side, which would therefore, not have an even number on its reverse.
We care about D, because if there is a vowel on the other side, then the theory is disproven. As you will have vowel card with something other than an even number on the back. In this case, a “D”. There is no constraint stated that there must be letters on one side and numbers on the other.
I took "back" to mean the side against the table as they sit. Four 'backs' in existence rather than 8. Tricky
I’m not very good at puzzles, but I got this one immediately. Easy way to explain it is to say that in order to prove something you also have to give it a chance to be disproven.
That was a really good puzzle. I got it, but my husband didn't. 😂
It seems like you also need to stipulate that each card has a letter on one side and a number on the other. Otherwise, if you flipped the "D" card and it had an "E" (vowel) on the other side, this would disprove the premise.
I pinned an explanation
I’m with you. Gonna need Presh @MindYourDecisions to weigh in.
@@WesBarker Your pinned response doesn't deal with issue @garyjenkins pointed out. I think you maybe missed what they are trying to state.
Typically this riddle has the stipulation that there is a letter on one side of each card and a number on the other side, so you can ignore the possibility of the "D" card having a vowel on the other side. If it's possible that there is a vowel on the other side of the "D" card, then you'd have to flip any card that doesn't show an even number (so three cards in this case) to check the required condition.
A statement ("If a vowel is on one side, then an even number is on the other.") is equivalent to its contrapositive ("If an even number is not on one side, then a vowel is not on the other.") You flip the A to check the statement, and you flip the 7 to check the contrapositive.
Hi Wes, I hope you guys will dive into the 'Knights and Knaves' style of puzzles soon
This is crazy, I didn't get it lol, great one Kristen, love you guys
Good riddle but you should redo it with all the needed info. You need a conditional statement of that all the cards have letters on one side which is considered the "front" and numbers on the reverse which is the "back". Otherwise 1 could be a correct answer. I assumed we were shown the front of all the cards. Which would just be flipping over the "A". Then saying if you "OBSERVE someone drinking an alcoholic beverage" thier age must be over 21 kinda reninforced to me that we were looking at the fronts of the cards cause i was only "observing" 1 person with an alcoholic beverage.
I pinned an explanation
Yeah. I already understood the riddle. I don't think you understand my point that there is missing information in the explationation of the riddle. Reread my point.
I got it but I started on the same track as Wes before realising that the 4 was irrelevant and that the 7 was indeed relevant. Might have been about 15 seconds once i understood the question.
EDIT: however, there is a little bit of information missing from the problem as stated.
It could be argued that only the visible side of the cards counts as the front, so you only need to turn the A.
Alternatively, it hasn't been stated that every letter has a number on its back or vice versa, so, going with the assumption that either side may be considered front or back, the D could have a vowel on the other side which would not have an even number on its back and would, therefore, need to be checked (although the D is an even-numbered letter, so, perhaps that counts).
I pinned an explanation
@@WesBarker the riddle as written creates a heuristic error. the word front basically means facing forward, therefore only the paper with the A would need to be checked (blank paper has no orientation). If you had written on Playing cards (you do have a deck laying around somewhere, right) it has a defined "front" and "back'
1. State that each card has a letter and a number, one on each side.
2. Ask how to 'find out" if the statement is true, in the fewest flips. (prove OR disprove)
actually you have to flip also the D card. The problem does not assure you that alla cards are letter on one side and number on the other. So it is possible that there is a vowel letter behind the D card and you have to check that it is not the case otherwise you would have a vowel with a D on the other side that is actually non an even number.
This is the only logic puzzle I've ever known that I don't understand at all. Forget about solving it, I don't even know what the goal is.
I pinned an explanation
I like her bringing you riddles too! Good fun!
I said that each related to the pattern of how many letter away are then from the previous vowel/consonant. (1 for A cuz there’s nothing before it, 4 for E cuz it’s 4 letters after A, or 1 for D cuz it’s 1 letter away from C) therefore u don’t need to flip any. Then she said the alcohol and I lost it
i'M A ONE PERCENTER. I haven't the foggiest what just happened but I love you two so much, I'm not all mad and stuff.
I pinned an explanation
Yeah -- i felt like we needed more information to prove anything. If you turn the 7 over and it doesnt have a vowel, it doesnt prove that all odd numbers dont have a vowel. So the premise still could hold that an odd number could have a vowel. Maybe the question just needed to be worded differently....or that the universe only consists of these 4 cards....which makes the question phrasing needlessly unclear....or is that the point?
I love your riddles! This one just hasnt been able to break through my thick skull for some reason.
I pinned an explanation
1:33 foreshadowing 😊
Yep, I'm in the 90% alright 🤣...
But when it's explained? 🤯
Loving these videos guys 😁🤘❤️
I pinned an explanation
For once I'm in the 1% I needed to watch the video 3 times to understand what was going on... I need to I'mprove my English hahaha
Sorry, but as the question is posed, that answer is incorrect. That 4 could have a 9 or some scribbbles on the opposite side or a constant. It could even be blank. Proving something isn't, doesn't mean something else is. That is a common fallacy used in illogical arguments. The question was not "do only vowels have even numbers on the reverse side."
Can you make a Video, who you Test and use a period pain Simulator? Please 🥺 😅
Paused at 1:37-- I don't understand the instructions at all. On the front of what? On the back of what? The opposite side of the paper? The sequence of letters and numbers?
Finished the video: I still don't get it. It seems like the instructions are missing pertinent information.
I pinned an explanation
So.... anyone else not catch the "flip" part and thought she meant to rearrange them to make it true? Because then the answer is zero. "A" is already at the front and sEVEN at the back. Lol. I look for trick questions too much. She even made it clear that it was a LOGIC puzzle.
Something tells me that Wes pinned an explanation
The premise of the puzzle makes no sense to me.
I don't understand this at all, and the explanation made it even more confusing. I don't understand the statement, "We didn't say anything about consonants at all," and then, the "D" and "4" cards are become "irrelevant.' How does the "4" card equate to a consonant?
The 4 was irrelevant because the statement said a vowel has an even number. Not that an even number has a vowel. Therefore consonants and even numbers on the front are irrelevant.
I pinned an explanation
This riddle kind of assumes the backs are Even/Vowels. If the A or 4 had a 5 or D on the back, wes would be right. So there's no way of really solving this properly unless you already know what's behind the cards which sort of the defeats the purpose of a riddle
If the A had a 5 behind it, you've disproven it. But if the 4 had a D behind it, the statement still stands because it says every vowel has an even number behind it, not that every even number has a vowel behind it. So basically every vowel has an even number but not every even number has a vowel
I pinned an explanation
Still made no logical sense to me.
A was the only vowel, and 8 is not 21.
I'll just admit defeat and Kristen is smarter than us all.
I pinned an explanation
@WesBarker The rules of the "game" was to turn over the vowels. 4 & 7 are numbers. And D is not a vowel.
I think people who not only logical, but literal as well won't be able to get this one.
When she added the changes my thought process was the same as yours.
So I will take a loss and admit that I am not as smart as your wife.
Given the original requirement flipping only the card with the number 4 is enough to prove that if there is a vowel on the front, there is an even number on the back, because it's never stated that odd numbers can't have a vowel on the back. Therefor, A could have been odd and flipping it would have proven nothing. For the solution the correct wording should have been "only vowels can have even number on the back"
Damian , you have misunderstood and/or misread the premise we are being asked to prove. We are to prove “if there is a Vowel on the front, there is an Even number on the back. Thus, your statement that “it is never stated that odd numbers can’t have vowels” is what the quiz is actually asking us to prove. Thus, we have to flip “A”. If it has even number the premise of the quiz holds true so far. If it was odd, then premise is wrong and quiz ends. But we also have to flip 7, because for premise to hold 7 can’t have a vowel. Your statement that you only have to flip 4 is wrong/backwards. The premise did not say that consonants cannot have even numbers; premise says that vowels have to have even numbers.
I have never seen a riddle more poorly explained than this one. I did not even understand the question until I have seen the entire solution. A proper explanation should mention that the question is about the back of the cards and not the back of the 4-digit string.
It's just the way you think, inductive or perspective. If you start thinking with a theory and then you go through the process to find the proofs or on the contrary you arrived at a theory using proofs and observations.
So the statement "if there's a vowel on a side there's a even number on the back" DOESN'T correspond to the different statement "if there's an even number on a side there's a vowel on the back" because are two completely different situations without a logic correlation (which is the right answer to the dilemma).
Starting from this assumpion you can solve their riddle 😉
@@biancaenera2500I think op meant the front seems like "AD" and the back seems like "47" so it seems like it suggest A corresponds to 4 and D corresponds to 7. I initially thought the same
@@alinaa_a1009May you tell me what "OP" means?
Thank you in advance 😊
@@clairegresswell original poster!
@lmaogtfo16 Oh, so simple - thank you once again!
I thought it'd be about how you ever got a show on tv.