Steel Beam Design Calculations for Beginners - Structural Engineer
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- Опубликовано: 11 сен 2024
- Example of a simple steel beam design done as a practicing engineering.
The reason I’m not checking the shear resistance is because I know that bending and deflection are the critical checks for this UDL condition. It is still worth checking if you are unsure or inexperienced.
It is really important to get good at hand writing calculations. If you are to sit your chartership exam with the iStructe, you must be proficient at writing calculations. So don’t become over reliant on computer software!
I am using Goodnotes 5 on my IPad Pro to write my calculations. I do this not only in this video but in real life for my work as I am trying to cut down on paper waste and embrace new technology.
I am a qualified Chartered Structural Engineer working in the UK. If you have questions please drop me a comment.
#structuralengineering #calculations #civilengineering
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/ everydaydazz
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Very helpful…especially for someone like me who is an intern and currently undergoing undergrad degree trying to reconcile all the concepts I learnt in class with the field❤
I'm looking to replace hardwood bed frame nonsense roof beams in my garage, and doing some back-of-the-envelope structural analysis with your guide was really helpful. It's remarkable how strong 80x80mm hardwood beams are, I seem to need 120mm section i beam to match the strength!
That was terrific! I remember it Iook several tutorials to get to grips with the BS equivalent, isn't the internet wonderful!! Definitely subscribed......thanks
Great videos, keep up the good work is really helpful, thank you. A wee question, why did you take the deflection limit as 200mm and not 20mm when calculating the second moment of area?
its 20mm, just my handwriting looks like 200 😛
Hi Daz, I think with the moment of inertia required, the deflection required should be 20mm not 200mm. Or am I wrong in this. Thank you for the great video. Keep it up as always.
Great video. Please do more examples
ruclips.net/video/fRyUf-GY754/видео.html..
Great stuff, looking for a calc to build a small gym with 150mm H beams
Do you have an example of two beams supporting an external wall? One resisting the brickwork, one resisting the blockwork and roof weight. Should the beams be tied together, if so, how?
It would be great to see how you would design this same beam if the masonry above was existing. Would you increase the size of the section to minimize cracking in the existing masonry or would you pack out the beam? If so, how do you calculate the size of your beam packers and at what spacing do the spacers decrease in size as they approach the support ends? This is something I’ve always struggled with, thanks.
Heh, I’ve just recorded a video which goes through this very problem, will be uploaded this weekend 😬😬
@@EverydayDazz Which video is this in? It's a question i've wondered as well
Hey, it’s in this video
ruclips.net/video/-XaigaTW7R4/видео.html
In your example you've used the combine deflection limit of 200 yet your calculation was for the live loading of 24kn, is there a reason for this?
Hi Dazz, this is really helpful, thanks. But I was wondering if it's normal not to consider the beam's self weight in the calculation? Or you'd reiterate again with the beam's weight?
great video, very informative👍
Can you explain why deflection is 20*10^4 please? Around 7 mins in?
Can you design a cantilever beam connection
with one support example with a pinned or and a moment connection? Also a wood column subject to overturning from wind.
There is much confusion on holding column down on open porches.
Thx
Sure.
Just fyi, you can’t have a cantilever beam with a pin connection.
Hi there, in which document did you get the deflection limits for the combined load, dead load and live load? Could you specifically direct me? Thanks
Hi!
I was referring Design of Structural Elements by Chanakya arya to brush up my basics. In this book, steel design section, they did designing some different way. They did not use the blue book like you did. Can you please tell me where should I start to learn from the basics.
Thanks in advance.
Hello, the weight is 5.5 tons per meter. Which type of iron can bear this weight? Thank you
I reg formula is wrong. he is using 5000lenght in mm and then gets the result in cm? The 200*10^4 should be 200*10^3 i think to make it work
This is so helpful! Thank you. Please do more examples of column and beam design for steel and concrete. Do you have any textbook recommendations where they give a lot of examples? It's so time consuming trying to find examples that use EC2 and EC3 :( our uni doesnt provide as with much examples or solutions so half the time I dont know if Im doing my beam and column designs correctly or not.
I’ve done a video on books so worth checking out.
Concrete centre or concrete society does lots of examples for concrete design.
SCI has plenty of documents with good examples for steel.
w= PSF load. W = total tributary load/ : PSF x area
Hi Dazz, Why is it that you and others use (wL^2)/8 as the formula for moments in a simply supported beam with a UDL but the red book (page 70) and other sources suggest using (WL)/8. Are these the same formulas? if so what how does (w) relate to (W)? And which one should I be using?
Hope my query makes sense, cheers.
So small w is kN/m and W is total load in kN. So to get W you do w multiplied by L.
That was confusing me! Who knew that there was a difference between W and w. Never seen that mentioned in any of the books I’ve read. It’s one formula or the other leaving me baffled.
Good,,, I didn't see BS 5950 applications??
Hi, if length of steel beam is 5000 mm including 200 mm bearing in each side. This means length of clear span is 4600 mm.which length will use in design.
Clear span length or full length of the beam? Please advice.
Thanks.
I would take the bearing centre length. So 4800mm.
@@EverydayDazz : Thanks for your reply.4800 mm is known as effective length of beam?
That’s right
Hi, please I had been asked to design a perimeter beam of a two-way-slab How do I go about this?
Attribute the load correctly to the edge beam, it depends on the dimensions of the slab but typically you can attribute a quarter of the area to the edge beam.
I was wondering where you got the "I required" formula?
It’s the formula for deflection rearranged to solve for the “I” given the deflection limit. The deflection of a beam under uniform load is:
d = (5 * w * L^4) / (384 * E * I)
Where:
d = deflection (m)
w = uniform load (kN/m)
L = length of span (m)
E = Young’s modulus (aka modulus of elasticity) (Pa)
I = second moment of area (aka moment of inertia) (m^4)
Some use units of mm, MPa, etc., but I always use base units of m, N, Pa
So basically if the deflection is okay, I can choose the beam right?
For this load condition. For the inexperienced always check bending and shear as well.
Sorry cause I'm a mechanical engineer can you explain in better plz. For this load condition what do y mean?
Low sound and small font
what is the value of Es? 20mm?
Es is the Young’s modulus of steel
THIS IS NOT FOR BEGINNERS AT ANY POINT.............
lol. Gotta start somewhere. I am less confused and more confused at the same time