Hi Infinity, a couple months ago I was struggling really badly in integration and almost failed. I watched a couple of these videos and I instantly understood everything. Thanks for all your hard work
For Q1C, can you use reversing the chain rule, or would that not work as 4 is not the differentiated version or differentiated multiple of the bracket?
Could you write your final answer for 3e as 4 - 2ln3 so a = 4 b = -2 and c = 3? Just curious and have the exam tomorrow so it would be good to know whether such an answer would be acceptable
@@S_G_B From the step before, its ((h-6)^-(1/2))/(-1/2), when you simplify that, it becomes -2((h-6)^-(1/2)), removing the denominator. From there they divide both sides by -2, and when you divide by -2, it's the same as multiplying by -1/2, and that's how they get the -1/2 on the right side. He essentially multiplies both sides by -(1/2)/1 to remove the denominator and this moves the -1/2 to the right side.
Hi Infinity, a couple months ago I was struggling really badly in integration and almost failed. I watched a couple of these videos and I instantly understood everything. Thanks for all your hard work
That is awesome to hear and good luck
i guess we're all here prepping for hell tomorrow morning 😅
ofc
Bro especially after what happened in that stats oaoer
how it go
it was ass@@skillquestion3482
surely 2023 paper sir 🙏🙏🙏🙏🙏🙏🙏🙏your'e the best
Thanks for the solid 3 years of help!!! and on behalf of my friends too
Hey Sir, I just wanted to say thank you so much for all the help you've given. You've literally been a life-saver over the past three years of math :D
holy shit bro ur saving my life
For Q1C, can you use reversing the chain rule, or would that not work as 4 is not the differentiated version or differentiated multiple of the bracket?
Could you write your final answer for 3e as 4 - 2ln3 so a = 4 b = -2 and c = 3? Just curious and have the exam tomorrow so it would be good to know whether such an answer would be acceptable
I did the same question and in the marking schedule it states to accept 4-2ln3 in the excellence criteria. Hope this helps
@@oliviabennett1978 Thanks, that helps heaps!
For question 3d, could i use cos^-1(0) and -cos^-1(0) or do i have to know that that is pi/2
THANK U SIR
For Q2E how do we know to move the -1/2 to the right side?
I'm also stuck on that, have you worked it out since then?
@@S_G_B From the step before, its ((h-6)^-(1/2))/(-1/2), when you simplify that, it becomes -2((h-6)^-(1/2)), removing the denominator. From there they divide both sides by -2, and when you divide by -2, it's the same as multiplying by -1/2, and that's how they get the -1/2 on the right side. He essentially multiplies both sides by -(1/2)/1 to remove the denominator and this moves the -1/2 to the right side.
@oteenie8458 Thanks so much 🙂
Banger
Thank you so much
What the hell was that damn paper ☠️, anyone do 1e??
Attempt JEE-Advanced paper and all this will come to nothing.
Where can one find this JEE-Advanced paper?
@@infinityplusone easily available on Google