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thnku ..sir. ji..for this series......it is very helpful for every student..❤❤❤
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Options A
sir pls upload short trick videos on real analysis
ans A thank you sir
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I DONE MY BETECH ON ELECTRICAL AND ELECTRONICS . BIOTECHNOLOGY ME EXAM KO ATTENDKAR SAKTI HU KYA SIR?
A is the correct answer.
Jab determinant 0 ho jayega tho or eigen value kaise posible hogi
A option is correct
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In Q no.4. 2, -1 not necessarily be eigenvalues of M if the other condition has not been given, so need to explain it properly
CALEY HAMILTON THEORM - EVERY SQUARE MATRIX SATISFY HIS CHARACTERISTICS EQUATIONS ... So value of lambda's are eigen value
@@ankitkumardip90 the characteristics equation of identity matrix is (x-1)^3=0, but it satisfies (x-1)^2(x-2)=0 as well, and then by your logic, 2 also must be an eigen value of identity matrix, which is not possible
@@mdhar7825 you are wrong ... You are going reversely... Sufficient condition is not true
@@mdhar7825 (x-1)^3 ko jo jo satisfy karenge wahi unka eigen value honge ...
@@ankitkumardip90 in question where is it been mentioned that this is the characteristics equation of the matrix, you can't assume on your own
A
Opt A
Thank you sir, option A is correct 😊
Sir iska answer A h
A ans
Aaa
A,c
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A is a correct answer
thnku ..sir. ji..for this series......it is very helpful for every student..❤❤❤
Option A is correct answer 👍👍
Thank you so much sir very helpful video 🙏🙏🔥🤗
No words are enough to complement U sir
Thanks 😊😊😊✌️✌️👌🐦
Key points are outstanding sir 🙏 🙏 🙏
Option (A ) is correct.
Thank you so much Sir . It is helping us a lot. 🤗
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LOVE YOU SIR 😍 💗
A is correct
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Thank u guruji
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A correct ... thanks you so much sir
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Sir please start 2d geometry with starting
A is currect
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Sir vector space ke bhi short trik vedio upload kijiye na ....
Option A sir and thank you so much sir
Thank you sir. Love from Pakistan❤
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Options A
sir pls upload short trick videos on real analysis
ans A thank you sir
Thank you sir🙏. Ans:A
Option A is correct..
A is correct answer 🙏🙏🙏
I DONE MY BETECH ON ELECTRICAL AND ELECTRONICS . BIOTECHNOLOGY ME EXAM KO ATTEND
KAR SAKTI HU KYA SIR?
A is the correct answer.
A is correct
Jab determinant 0 ho jayega tho or eigen value kaise posible hogi
A option is correct
Option a ans. Time taken 2 sec sir
A is correct 💯
A is correct
Option 'a' is correct
Option A is correct
A is the correct answer
Sir please 3 d geometry padha dije
Conicoid se
Only A correct
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Option A sir
Option ( a ) ....
A is correct in 5 sec
Option A
A option
option a
Ans A
Only a is true
A is truu
Only 1 is right
A✔️
In Q no.4. 2, -1 not necessarily be eigenvalues of M if the other condition has not been given, so need to explain it properly
CALEY HAMILTON THEORM - EVERY SQUARE MATRIX SATISFY HIS CHARACTERISTICS EQUATIONS ...
So value of lambda's are eigen value
@@ankitkumardip90 the characteristics equation of identity matrix is (x-1)^3=0, but it satisfies (x-1)^2(x-2)=0 as well, and then by your logic, 2 also must be an eigen value of identity matrix, which is not possible
@@mdhar7825 you are wrong ... You are going reversely... Sufficient condition is not true
@@mdhar7825 (x-1)^3 ko jo jo satisfy karenge wahi unka eigen value honge ...
@@ankitkumardip90 in question where is it been mentioned that this is the characteristics equation of the matrix, you can't assume on your own
A
Opt A
Thank you sir, option A is correct 😊
Sir iska answer A h
A ans
A
Aaa
A,c
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A
A
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A
A
A
A
A
A
A
A
A
A
A
A
A