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Thanku soo much sir, i am trying to understand this topic from books and college teachers from 1 week but i can't able to understand. Thanku so much magician 🙏🙏
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what happen if i take all clockwise moment positive and anticlockwise moment negative....and why parabola drawn like upward not downward....pl guide......btw very easy way of teaching i like it....
at point B y we taking 3KN as possitive as it is on the left of the point B nd acting downwords. as sign convention says any force acting downwards to the left of point while calcuating Sf should be treated negative
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a beam of span l is fixed at one end & simply supported at other end. it carries uniformly distributed load of w per unit run over the whole span. the reaction at the simply supported end is what ?
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But while calculating for point load we haven't taken horizantal support reaction know sir?? Also we didn't take Moment at A to... In previous problems i.e.,for point load
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amazing videos. but why you keep finding a moment from the left side and suddenly at the end start to find a moment from the right side in every single video? please feel free to reply
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Udl is inbetween C and D . So this udl will not produce moment for the distance between D and E . Therefore we take only the distance (ie half of 2m = 1m )
Ur teaching style is good but the bending moment will be negative as for the right portion of the section and the moment load is clockwise.. If I am wrong then pls explain to me.
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U multiplied 3kN at point B while calculating shear force but at bending moment at B point why didn't u multiply the 3kN as it is earlier considered while calculating shear force at B??
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Becoz from right to left at free end of beam the distance is 0 Bending moment =load ×distance = Load what ever will be ×distance 0=0 Anything multiple by 0=0
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Please please anyone explain to me why some books tell me to take the downward forces to be negative values when calculating SF values in cantilevers And here they are calculated as positive values on SF values Pls help me out
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Your teaching is good and clear sir. l learned much from your classes.
Nice ihave seen lot of video you fully clears the all doubts about sf and bm with one video thank you so much❤
Thanku soo much sir, i am trying to understand this topic from books and college teachers from 1 week but i can't able to understand. Thanku so much magician 🙏🙏
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Doubts that had been cleared by you very clearly sir...Thanks a lot...Keep posting a videos for us sir...
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Your teaching was great ... it's really helpful
Leki Khandu
thank you sir
THANKS U SIR, U CLEARED THE CONCEPT
VERY GOOD STYLE OF TEACHING U HAVE
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You are the great teacher thankx for this lecture.
It is very benifitial for me and all other students
Explain clear each step by step sir at some points I didn't understand
Superb sir your teaching
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Please explain 1 example of simply supported beam on which udl is acting on entire span
Good explanation sir..
Very very impressive 🤩🤩🤩🤩👍👍👍👍
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what happen if i take all clockwise moment positive and anticlockwise moment negative....and why parabola drawn like upward not downward....pl guide......btw very easy way of teaching i like it....
U will be modda guduusu in the exam
at point B y we taking 3KN as possitive as it is on the left of the point B nd acting downwords. as sign convention says any force acting downwards to the left of point while calcuating Sf should be treated negative
You're right 3 must be negetive and the answer will be i.e SF at B will be 4.5 not 7.5
Thanks a lot
Sir make ur video easy
Explain all things
Like 3:41 minute
How do u find support reaction ?
YOU ARE GOOD SIR...
I undertood clearly thank you sir
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Sir i wanna know ki
During BMD why is the parabola made this way??
Not the other way??
so useful sir. thank you
Nice sir ❤️👍
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Plz make a vdo for overhanging beam also
It's very helpful for me
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nice video, we need more lactures in fluid mechanics and thermodynamics please
Wah chacha good videos
Thank you so much sir...
U r really god for me... Thanx again
Thanks srr
nice lecture
Love u sir so musch
very nyc explanation
Superb
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Sir please upload the sum for couple acting at every beam with some loads also...
sir I think moment reaction is opojit side here
awsome sir
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sir can you upload a video on derivation of forming a torsion equation
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Sir what about udl in calculating moment at A to find Reaction at B
Sir plz a video is uploaded for fixed beam problem and also continues beam
a beam of span l is fixed at one end & simply supported at other end. it carries uniformly distributed load of w per unit run over the whole span. the reaction at the simply supported end is what ?
We are more than happy to solve your queries.However for this you will have to download the Ekeeda-Learning Application by going through this link bit.ly/353lpP2 ,because we don't answer any technical queries on youtube for this we have a dedicated team.
Thanks a lot sir
You are always welcome!
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Sir parabolab rise way se bi to be skta tha na.
Thanku sir
e keeda rocks.
But while calculating for point load we haven't taken horizantal support reaction know sir??
Also we didn't take Moment at A to... In previous problems i.e.,for point load
Please give reply as soon as possible sir 🙏...
@@sriguruskandha9920 i dont get your question.can u please tell again once
How can we take since there is no any horizontal force acting… so horizontal reaction is zero … and for point load BM is zero at the supports
while calculating bending moment in step 3 Mb bending moment b the udl is not negative white ?
Sir plz... fixed beam pay ek sfd and bmd ka numerical bataeye na..
Sir in sfd why you not take left side and right side
Sir shouldnt be the +7kn for sf at A be -7kn pls explain
-7
0
Why did you calculate M at A twice and that too having different directions as per signs?
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Sir
Section right side clock wise.moment so it is -ve value. Clarify.
Question cantilever beam me ......aap moment clockwise Kyu liye h...plz reply sir...anticlock wise Kyu nhi liye
thanks u
sir fixed beam ka SFD and BMD ka videos daliye sir
amazing videos. but why you keep finding a moment from the left side and suddenly at the end start to find a moment from the right side in every single video? please feel free to reply
He found reactions and shear force and finally moment at last...you can find bending moment only from the right on case of cantilever beam
I want the problem of cantilever beam with udl and non udl
I don't want peace !! I want problem always !!😊🤣
Hello sir this video for diploma students also
nice
Moment about C
Distance is 1.5
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Udl is inbetween C and D . So this udl will not produce moment for the distance between D and E . Therefore we take only the distance (ie half of 2m = 1m )
Ur teaching style is good but the bending moment will be negative as for the right portion of the section and the moment load is clockwise.. If I am wrong then pls explain to me.
Hello
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Sir cantilever beam ke liye sfd aur bmd negative hona chahiye.
ha....if we go from left to right ..the forces r diffrent
Sir what is the relationship between SF AND BM
Lovers anna
Agar point load udl par kuch duri par lag raha hai aur free end par koi force nahi hai
Can u explain in clarity way
Sir bm value is oppsite
Why did multiply 2 in(1*2*3.5) in Moment at A
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sir Ra -7.5 AANA chahiye na
U multiplied 3kN at point B while calculating shear force but at bending moment at B point why didn't u multiply the 3kN as it is earlier considered while calculating shear force at B??
We are more than happy to solve your queries.However for this you will have to download the Ekeeda-Learning Application by going through this link bit.ly/353lpP2 ,because we don't answer any technical queries on youtube for this we have a dedicated team.
@Ekeeda poda %$@#%$$
In maximum bending moment u did wrong.. the forces should be negative as the sign convention is negative not positive (anti clockwise)
Why we take b.m of cantilever at free end zero ..... explain sir g
Becoz from right to left at free end of beam the distance is 0
Bending moment =load ×distance
= Load what ever will be ×distance 0=0
Anything multiple by 0=0
Sir ek que bta do plz
while calculating BM why dont you find it from left side...
Because it’s an rule to find BM from the free end
👍
Why we didn't find moment about A in 1 problem
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🎉❤
Please please anyone explain to me why some books tell me to take the downward forces to be negative values when calculating SF values in cantilevers
And here they are calculated as positive values on SF values
Pls help me out
Study the sign convention properly....
same confusion, my college teacher also taught by taking downwards forces as -ve
lolo like teaching
true
@@pratik2319 bhai pura paka deta hai
Jaldi
t h a n k s
Explanation is not good in sf calculation
Xiii everything is wrong I waste my time
Very impressive class thanks a lot sir 🙏🙏
Thank you so much sir...
U r really god for me... Thanx again
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so useful sir. thank you
Thank u sir
nice
Jaldi
Thank u sir
Thank you sir