Mr AndersonThe units in the PV graph are wrong the unit of pressure is pascal and volume has meter cube at 3.56 .Thank you for this helpful videoRegards
dunno if anyone gives a shit but if you guys are stoned like me during the covid times you can stream pretty much all of the latest series on instaflixxer. Been watching with my girlfriend these days =)
Brilliant video. A quick correction for the example you gave at 1:20. This is an isothermal compression, therefore the work done by the surroundings on the system actually causes heat to exit the system, NOT a change in the internal energy. The internal energy stays constant (0 = Q + W hence -Q = W)
I am sorry I say this, but I think you made a mistake in your explanation about internal energy. I have learned that heat is equal to internal energy (dU) + work (dW). So this means instead of dU=Q+W the formula must be dU=Q-W, because of the formula: Q=dU+dW ofcourse. But I could be wrong about this....
Isentropic is a special case of polytropic. Isentropic means constant entropy, which happens for reversible processes with no heat transfer (i.e. adiabatic/quasistatic or adiabatic/reversible). Polytropic processes are governed by the relationship of P*V^n = constant, where n can be any positive real number including infinity. For n=0, we have a constant pressure process. V^n reduces to 1 no matter what volume is, implying that P=constant For n=1, we have a constant temperature process assuming an ideal gas. The process is equally sensitive to changes in volume and pressure, such that pressure and volume each change by each others' reciprocals. For n=infinity, we have a constant volume process. No matter what P is, V^n will dominate the expression, implying that V is constant. The case of isentropic processes occurs when n=k (some books use gamma), where k is the heat capacity ratio. k is a substance-specific value. For air and other 2-atom elemental gasses like it, k=1.4. For a single atom gas like helium, k=1.67. It has to do with the ways that the gas molecule can store energy in addition to pure translation.
I pressed an empty closed cold drink 🍼 bottle so how i know work done by me 2 liter empty bottle closed and pressed by me so how i know work done by me ? Pressure and volume of close bottle are changing but where the volume increased if bottle is closed ??
Depends on what sign convention you assign for the meaning of positive work, positive heat, and change in internal energy. The sign convention is arbitrary, and it is best to always interpret the sign of your results in words, to avoid confusion. And follow the sign convention given in your class. I'm accustomed to the heat engine sign convention, where heat added to the system is positive, and work done by the system is positive. Thus, Q=deltaU + W is correct in that sign convention.
Thanks. Having to go to class to learn this is very annoying if you professor isn't good. You've saved me much time.
Mr Anderson I really enjoy your videos. You are a great teacher, sir.
Yes that was helpful. You are the best teacher ever.
Mr AndersonThe units in the PV graph are wrong the unit of pressure is pascal and volume has meter cube at 3.56 .Thank you for this helpful videoRegards
dunno if anyone gives a shit but if you guys are stoned like me during the covid times you can stream pretty much all of the latest series on instaflixxer. Been watching with my girlfriend these days =)
@Otto Duke Yup, I've been watching on InstaFlixxer for since december myself :D
@Otto Duke Yup, been using InstaFlixxer for years myself :)
@Otto Duke definitely, have been using InstaFlixxer for months myself :D
@Otto Duke definitely, I've been using instaflixxer for since november myself :D
Brilliant video. A quick correction for the example you gave at 1:20. This is an isothermal compression, therefore the work done by the surroundings on the system actually causes heat to exit the system, NOT a change in the internal energy. The internal energy stays constant (0 = Q + W hence -Q = W)
Excellent explanation. Physics bless you sir, Thank you.
It is one of the best videos on that topic, thanks ❤
For the first time I could understand it well! Thanks a lot...
all explanations except isobaric are satisfying.
the best explanation i have seen
Its simple and straight forward
excellent presentation skill sir
saved me from confusion! simple n effective..
Unit of pressure and volume are exchanged in graph in this video
Thank you Mr. Andersen very cool
hello.... please add a video calculating "workdone" at the moving boundary of a simple compressible system.
As always, Thank you, Bozeman. Very useful
Awesome, sir. ❤
I am sorry I say this, but I think you made a mistake in your explanation about internal energy. I have learned that heat is equal to internal energy (dU) + work (dW). So this means instead of dU=Q+W the formula must be dU=Q-W, because of the formula: Q=dU+dW ofcourse. But I could be wrong about this....
Well u r right ,the main formula. Is U= q+w but when we put formula for work ie. - P∆v it will become U=q-w
Heat exchange dq is, dq=du + pdv or du=dq+w because w=-pdv.
Can you explain "polytropic" process, and is it related to "isentropic" process
Isentropic is a special case of polytropic. Isentropic means constant entropy, which happens for reversible processes with no heat transfer (i.e. adiabatic/quasistatic or adiabatic/reversible).
Polytropic processes are governed by the relationship of P*V^n = constant, where n can be any positive real number including infinity.
For n=0, we have a constant pressure process. V^n reduces to 1 no matter what volume is, implying that P=constant
For n=1, we have a constant temperature process assuming an ideal gas. The process is equally sensitive to changes in volume and pressure, such that pressure and volume each change by each others' reciprocals.
For n=infinity, we have a constant volume process. No matter what P is, V^n will dominate the expression, implying that V is constant.
The case of isentropic processes occurs when n=k (some books use gamma), where k is the heat capacity ratio. k is a substance-specific value. For air and other 2-atom elemental gasses like it, k=1.4. For a single atom gas like helium, k=1.67. It has to do with the ways that the gas molecule can store energy in addition to pure translation.
the slope of polytropic process will be more or less steeper than adiabatic process??
Not enough information. We'd have to know where n of the polytropic process is, relative to the adiabatic index k.
thank you sir!
Thanks so much teacher
Thank you i have always ask why deltaU=0 in isothermal. Just know it only for ideal gases :)
Thank you soo much, very helpful video. Well done!
I love you daddy Bozeman. Thanks for the lesson.
Graph has reversed units of Pressure and Volume
which software you are used for making pv diagram and other graph?
please give me name of the software
What software are you using for making the graphs
How is more work is done by the isothermal than adiabatic
What is total work done by atmospheric pressure at globe level ???
How much work do you do pushing against a rigid wall? That's how much work a static atmosphere is doing on our planet.
It's really frustrating when lecture upon lecture teaches you less than this 8 minute video. Thanks.
I pressed an empty closed cold drink 🍼 bottle so how i know work done by me
2 liter empty bottle closed and pressed by me so how i know work done by me ?
Pressure and volume of close bottle are changing but where the volume increased if bottle is closed ??
Then there was no work done w=-P∆V
0=x×O
0=0
Useful
very helpful ,,thnkew
thank you professor ;)
thank you a lot
hello sir, you have a unit mistake on the diagram.
it was helpful
Pls make video 💡⏩topic =enthalp❔
great
thnk u sir
My teacher is making us watch this
❤️
Finals tomorrow, this is deal for fial reviewing :D
DAAAAAAAMN BOIIIIIIIIII Noice stuff
Isn't Delta u = Q-W?
Yes it is.
Depends on what sign convention you give for +Q and +W. I'm accustomed to +Q being heat added to the system, and +W being work done by the system.
The sign convention also varies in chem and phy textbook all u need to focus is that when to use when
Q= ∆U + W right?
Vaibhav Rokde It should be Q=U-W
Depends on what sign convention you assign for the meaning of positive work, positive heat, and change in internal energy. The sign convention is arbitrary, and it is best to always interpret the sign of your results in words, to avoid confusion. And follow the sign convention given in your class.
I'm accustomed to the heat engine sign convention, where heat added to the system is positive, and work done by the system is positive. Thus, Q=deltaU + W is correct in that sign convention.
Nevermind the fact that you look stoned, but good video.
got it
NICE VEDIO
I love u
My name is Jeff
wrong equation dude first thermodynamics
Too fast not detailed enough
Why are you so hurry.....be slow.....
Very insightful!!! 😇😇👏