How to Solve Limiting Reagent Using Stoichiometry | Chemistry Problems | Extraclass.com

Best Full Explanation of Limiting Reagent with Example is provided in this video.
By watching this video Chemistry Students will never forget the concept of limiting reagent. Sometimes, this is also referred to as limiting reactant. This video also explains the concept of excess reagent with example - a very important concept required to understand how limiting reagents work in a chemical equation a
Importance of Limiting Reagent in a Chemical Equation
Limiting Reactant and Reagent are the stoichiometric limits which help us to identify the limiting reactant and percent yield.
What is Limiting Reagent?
Theoretical Chemical equations which we study specify precise amounts of reactants that will combine to give products.
However in a real chemical reaction, arbitrary amounts of reactants are mixed together and allowed to form products, which means generally that one of the reactants will be used up completely, while excess amounts of other reactants will remain after the reaction has run to completion.
A reactant that is totally consumed in a chemical reaction thus limiting the amount of product produced during the reaction is known as limiting reagent
Let’s try a simple analogy to understand the concept of limiting reagent.
Let’s assume that there are three essential components required to create a motorcycle namely a headlight, tires and the body containing engine, handle, seat etc.
To create 1 motorcycle, we need 1 headlight, 2 tires and 1 body
Suppose we are given 10 headlights, 22 tires and 9 bodies. How many motorcycles can we create?
By simple calculation we can determine that With 10 headlights we can create 10 motorcycles, with 22 tires we can create 11 motorcycles and with 9 bodies we can only create 9 motorcycles
Therefore after we have consumed the total available 9 bodies to create 9 motorcycles we are still left with 1 headlight and 4 tires which are present in excess and since number of available bodies is totally consumed therefore it is the limiting reagent.
In chemical reactions, we use stoichiometry to determine the limiting reagent. Let’s learn the steps followed in this process
Step 1 : Balance the chemical equation for the chemical reaction.
Step 2: Convert the given information into moles using molar mass or molar volume as conversion factor
Step 3: Calculate the mole ratio from the given information. Compare the calculated ratio to the actual ratio.
Alternatively the third step can be
Step 3 : Use stoichiometry for each individual reactant to find the mass of product produced.
Step 4 : The reactant that produces a lesser amount of product is the limiting reagent.
Step 5: The reactant that produces a larger amount of product is the excess reagent.
Step 6 : To find the amount of remaining excess reactant, subtract the mass of excess reagent consumed from the total mass of excess reagent given.
Let’s solve an example to apply these steps and find the limiting reagent.
This question was asked in IIT JEE 1981 exam
Solution

[@user-lr5lc9ir5q]

Best video on limiting reagent, simple and effective

[@Extraclass]

. Thanks for the appreciation. Please like share comment and subscribe for support

[@anshulthakur7396]

Simply amazing video

[@Extraclass]

Glad you think so!

[@anshulthakur7396]

Loved the animation used

[@Extraclass]

Thanks for the appreciation. Please like, share and subscribe to support us.

[@surprisetest5993]

Great analogy used to explain limiting reagent

[@Extraclass]

. Thanks for the appreciation. Please like share comment and subscribe for support

[@surabhitiwari6954]

Nice animation great video

[@Extraclass]

Thank you so much 😀

[@supratikkundu9450]

Super animation video on limiting reagent...
This is so awesome...
Loved the bike analogy

[@Extraclass]

Thank you so much 😀

[@dhanunikki9594]

Very useful thank you buddy

[@richdotcom6616]

Really helpful thanks

[@Extraclass]

good

[@saleemahmed8169]

Good analogy and question used👏

[@Extraclass]

Thanks

[@Extraclass]

Please like share and subscribe to support us

[@mukunthvg3091]

Very helpful.... THANK YOU EXTRACLASS.... Waiting for you and your team to upload many videos like these further ❤️❤️😃

[@Extraclass]

Thanks for the appreciation. We will upload more than a 1000 videos. Keep supporting us

[@ManojYadav-wd1qo]

Wow

[@Extraclass]

great