All well and nicely explained. Pivot Point is not explained as required. Needs PP to explain about ship when stationary, moving ahead and going astern. Regards Capt Abid.
Hello sir I have question that I want to know, sir a cafesize bulk carier full loaded and full speed hard to starboard, so how much is the diameter and how many minutes to complete the turning circle, sir can you give me the idea about the estimate diameter of most cafesize turning circle and complete minutes, thank you, i read this in my exam so i dont know if i answer correct because the choices is 600mters 800 metrs 1.2nm,
Normally turning circle is 3-4times the LBP, so for cape size of length around 250m, 800m would be the probable answer. Time of taking the turn depends on the speed of the ship, it could be anything between 3-5 min when making way reasonably.
Why the turning circle is greater in shallow water? Why stopping distance is greater in shallow waters?? Please explain cant find a good reason for orals
Hi Kamby, in shallow water, the resistance increases, bringing the pivot point aft and thus making rudder less effective, increasing the turning circle. For stopping distance, I can just think on one reason, as momentum of the ship is still the same and vessel does not use it to athwart ship direction due to increased resistance, thus stopping distance eventually increases as momentum is used in ahead direction. I hope this would be useful...
Even I had the same thoughts earlier, however the turning circle of the ship is actually the path of COG also called midship point of the ship. You may search for turning circle path of the ship on google and checkout the images in it. You would get clear.
@@oralexammmdprep8110 yeah, in Google they say path taken by the midship. In Polaris app, turning circle is described w.r.t pivot point (which according to me, makes more sense)... Confused. I'll try to get clarified more... Anyway thanks for the input. Good work with videos...✌️
@@tonythomas5249 it makes more sense to consider pivot point as the turning circle as there is no drift at that point, However if I consider the practicality, midship point circle would be larger, the sweep of the ship in either side of the circle would be same, making it easier to estimate a better manoeuvre.. Considering all this, I decided to put this in my video, if you find some more info on the same, do share so I could edit the data if required. Cheers!
@@oralexammmdprep8110 Yeah, sounds reasonable. Also pivot point may change as the speed changes along the turn, but midship will be a fixed reference... -Sure, will update if i could learn something additional...
Speed would increase or decrease the time a ship takes to make a turn under given circumstances. The turning circle doesn't change because the lateral thrust increases as the speed increases, thus keeping the turning circle same.
All well and nicely explained. Pivot Point is not explained as required. Needs PP to explain about ship when stationary, moving ahead and going astern.
Regards Capt Abid.
Perfect explanation 👌
Thanks Aman!
How does pivot point change throughout the turn?
Hello sir I have question that I want to know, sir a cafesize bulk carier full loaded and full speed hard to starboard, so how much is the diameter and how many minutes to complete the turning circle, sir can you give me the idea about the estimate diameter of most cafesize turning circle and complete minutes, thank you, i read this in my exam so i dont know if i answer correct because the choices is 600mters 800 metrs 1.2nm,
Normally turning circle is 3-4times the LBP, so for cape size of length around 250m, 800m would be the probable answer. Time of taking the turn depends on the speed of the ship, it could be anything between 3-5 min when making way reasonably.
Thank you so much sir for answering my question
Why the turning circle is greater in shallow water?
Why stopping distance is greater in shallow waters??
Please explain cant find a good reason for orals
Hi Kamby, in shallow water, the resistance increases, bringing the pivot point aft and thus making rudder less effective, increasing the turning circle.
For stopping distance, I can just think on one reason, as momentum of the ship is still the same and vessel does not use it to athwart ship direction due to increased resistance, thus stopping distance eventually increases as momentum is used in ahead direction.
I hope this would be useful...
Turning circle is the path of the pivot point right?
Not the center of gravity.
Even I had the same thoughts earlier, however the turning circle of the ship is actually the path of COG also called midship point of the ship. You may search for turning circle path of the ship on google and checkout the images in it. You would get clear.
@@oralexammmdprep8110 yeah, in Google they say path taken by the midship. In Polaris app, turning circle is described w.r.t pivot point (which according to me, makes more sense)... Confused. I'll try to get clarified more... Anyway thanks for the input. Good work with videos...✌️
@@tonythomas5249 it makes more sense to consider pivot point as the turning circle as there is no drift at that point, However if I consider the practicality, midship point circle would be larger, the sweep of the ship in either side of the circle would be same, making it easier to estimate a better manoeuvre.. Considering all this, I decided to put this in my video, if you find some more info on the same, do share so I could edit the data if required. Cheers!
@@oralexammmdprep8110
Yeah, sounds reasonable. Also pivot point may change as the speed changes along the turn, but midship will be a fixed reference...
-Sure, will update if i could learn something additional...
How does the speed effect the turning circle can you explain please?
Speed would increase or decrease the time a ship takes to make a turn under given circumstances. The turning circle doesn't change because the lateral thrust increases as the speed increases, thus keeping the turning circle same.
NICE VIDEO....
Thanks Amar!
Why there is no drift angle at pivot point
How do you calculate advance and transfer when you know the speed and rudder position?
Advance & transfer depends on the ship design. Thus they are calculated case to case basis using practical ship trials
I didn't understand😉
Consider english medium in next life😂